Chegg Solutions for Microelectronic Circuits (Adel S Sedra, Kenneth C Smith) (Z-Library)_parte_068

Prévia do material em texto

Step of 9 8.036P Consider the expression for the bias current W 2 Substitute 25 for 400 for and 8 for W L 1600 m V Therefore, the value of the overdrive voltage is 0.125 V Step 2 of 9 Calculate the value of the D Substitute 0.125 V for and 25 for 0.125 =0.4 Therefore, the value of the is 0.4 mA/V Step 3 of 9 Calculate the value of the intrinsic gain A. Substitute 5 V/µm for 0.36 for L and 0.125 V for 0.125 3.6 0.125 Therefore, the value of the intrinsic gain is 28.8 Step Calculations for the drain current Consider the expression for the bias current ID 2 Substitute 250 for 400 for and 8 for L 250 1600 m Therefore, the value of the overdrive voltage IS 0.395 V Step 5 of 9 Calculate the value the transconductance Substitute 0.395 V for and 250 for ID 0.395 =1.27 mA/V2 Therefore, the value of the transcondcutance is Step of 9 Calculate the value of the intrinsic gain A. Substitute 5 V/µm for 0.36 for L and 0.395 V for 0.395 3.6 0.395 =9.11 Therefore, the value of the intrinsic gain A. is 9.11 Step Consider the expression for the bias current ID 2 Substitute 2.5 mA for 400 for and 8 for W L (400 Therefore, the value of the overdrive voltage V Step of 9 Calculate the value f the transconductance 8. Substitute 1.25 V for and 2.5 mA for 2(2.5 m) 1.25 =4 Therefore, the value of the transconductance, is Step Calculate the value of the intrinsic gain A. Substitute 5 V/µm for 0.36 for L and 1.25 V for 1.25 3.6 1.25 =2.88 Therefore, the value of the intrinsic gain is 2.88