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1.1 Find the rate of reaction defined as mol used = sec. m3 of tank Evaluate terms E = V or V = 5 or treatment Volume of tanks) = day)(32000 day m3 ) = 10667 used (200 mg lit 1000mg 1gm 32gm day = mol day Oz Thus the rate of reaction 02/day = 18.75 day 10667m3 = 2.17 1.3 Find -r' and evaluate terms = 50000kg 800 kg/m3 = 62.5 of catalyst = 50000 kg = [20(12) + 42(1) J 1000 = 0.282 kg/mol Ffeed = = 5400000 kg/day So dt = 5 400 000 24(3600)s day ) (0.6) = 133 mol reacted/s Thus the rate of disappearance of = Weat dN dt = 50000 (133) = 0,0027 cat. = Veat dN = 62.5 (133) = 2.13