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Solutions for Reactions of Aromatic Compounds H H C CH3 CH3 CH3 OH C H H H C CH3 CH3 CH3 C CH3 CH3 CH3 + BF3 (b) + HF (a) 16 CH2 C CH3 CH3 C CH3 CH3 CH3 C CH3 CH3 CH3 HO CHCH3 CH3 CHCH3 CH3 CH3 CH3 C CH3 CH3 CH3 C CH3 CH3 CH3 CH3 ++ BF3(d) + HF (c) C CH3 CH3 CH3 CH3 C CH(CH3)2 CH3 CH3 AlCl3 CH3 + (d) (c) No reaction: nitrobenzene is too deactivated for the Friedel- Crafts reaction to succeed. (b)(a) 17 In (a), (b), and (d), the electrophile has rearranged. plus poly-alkylation products 18 (a) + CH3CH2CH2CH2Br (b) Gives desired product: activated ring plus 3° carbon in the electrophile gives para as the major product. (c) Gives desired product plus ortho isomer; use excess bromobenzene to avoid overalkylation. (d) No reaction; benzamide is too deactivated for a Friedel-Crafts reaction. (e) Gives desired product: methyl is slightly activating; putting three deactivating nitro groups requires forcing conditions, and great care to avoid detonation! BOOM! rearranged rearranged rearranged rearranged—not the desired product 392