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14 Chemical Kinetics Solutions to Exercises (c) From the slopes of the lines in the figure at the right, 1.8 the rates are: at 75.0 min, 1.6 4.2 or 1.4 (M) 1.2 7.0 10⁻⁵ M/s; at 250 min, 1.0 2.1 or 0.8 3.5 0.6 0 100 200 300 400 time (min) 14.23 Analyze/Plan. Follow the logic in Sample Exercise 14.3. Solve. (a) (b) (c) (d) 14.24 (a) (b) (c) (d) 14.25 Analyze/Plan. Use Equation [14.4] to relate the rate of disappearance of reactants to the rate of appearance of products. Use this relationship to calculate desired quantities. Solve. (a) H₂ is burning, = 0.48 mol/s O₂ is consumed, = = 0.48 mol/s/2 = 0.24 mol/s is produced, = = 0.48 mol/s (b) The change in total pressure is the sum of the changes of each partial pressure. NO and Cl₂ are disappearing and NOCI is appearing. = -56 torr/min - 28 torr/min + 56 torr/min = -28 torr/min 401