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20 Electrochemistry Solutions to Exercises 20.37 Analyze/Plan. Follow the logic in Sample Exercise 20.6. Solve. (a) Cl₂(g) = 1.359 V I₂(s)+2e⁻ (b) Ni(s) Ce³⁺(aq)] (c) Fe(s) 2[Fe³⁺(aq)+1e⁻ Fe²⁺(aq)] (d) 3[Cu(s) 20.38 (a) 2F⁻(aq) H₂(g) (b) Cu(s) Ca(s) (c) Fe(s) (d) 5[2Br⁻(aq) 20.39 Analyze/Plan. Given four half-reactions, find from Appendix E and combine them to obtain a desired (a) The largest will combine the half-reaction with the most positive as the cathode reaction and the one with the most negative as the anode reaction. (b) The smallest positive will combine two half-reactions whose values are closest in magnitude and sign. Solve. (a) Ag(s)] Cr(s) Cr³⁺(aq)+3e⁻ 622