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Questão 1:
Utilizando o SciLab
X=[-2000000:10000:160000000]
Y=x2-140006258x+5
Y’=x*0
 Plot(x,y,x,y’)
F(x)=x2-140006258x+5
∆=b2-4ac
X’ =(-b+√∆)/2a = 140006257,999999964
X” =(-b-√∆)/2a =3,57103999704122543*10-8
Questão 2:
RA= 140006258
√RA=±11832,4240120103877
Número de iterações 3 utilizando o VCN
F(x)= X2-140006258 I=[11832,11833] ε=10-3
	k
	a
	b
	xk
	f(xk)
	b-a
	F(a)=a2-140006258
	F(a)*F(b)
	0
	11832
	11833
	11832,50
	1798,250
	1
	-10034,00
	-18043640,50
	1
	11832
	11832,5
	11832,25
	-4117,93750
	0,5
	-10034,00
	41319384,88
	2
	11832,25
	11832,5
	11832,375
	-1159,8593750
	0,25
	-4117,9375
	4776228,415
	3
	11832,375
	11832,5
	11832,4375
	319,191406250
	0,125
	-1159,859375
	-370217,145
	4
	11832,375
	11832,4375
	11832,40625
	-420,33496093750
	0,0625
	-1159,859375
	487529,4451
	5
	11832,40625
	11832,4375
	11832,42188
	-50,5720214843750
	0,03125
	-420,3349609
	21257,18868
	6
	11832,42188
	11832,4375
	11832,42969
	134,3096313476560
	0,015625
	-50,57202148
	-6792,309562
	7
	11832,42188
	11832,42969
	11832,42578
	41,86878967285150
	0,0078125
	-50,57202148
	-2117,389331
	8
	11832,42188
	11832,42578
	11832,42383
	-4,351619720
	0,00390625
	-50,57202148
	220,070206
	9
	11832,42383
	11832,42578
	11832,4248
	18,75858402252190
	0,001953125
	-4,35161972
	-81,63022416
	10
	11832,42383
	11832,4248
	11832,42432
	7,203481912612910
	0,000976563
	-4,35161972
	-31,34681395
Questão 3:
RA= 140006258 F(x)=x2-140006258
 √RA=±11832,4240120103877 f’(x)=2x
 A0=x0=11832 f”(x)=2
	k
	Xk
	F(xk)
	F'(xk)
	Xk-((Fxk)/F'(xk))
	0
	11832,0000000000000000
	-10034,0000000000000000
	23664,0000000000000000
	11832,4240196078000000
	1
	11832,4240196078000000
	0,1797926127910610
	23664,8480392157000000
	11832,4240120104000000
	2
	11832,4240120104000000
	0,0000000000000000
	23664,8480240208000000
	11832,4240120104000000
	3
	11832,4240120104000000
	0,0000000000000000
	23664,8480240208000000
	11832,4240120104000000
X0=B0=11833
	k
	Xk
	F(xk)
	F'(xk)
	Xk-((Fxk)/F'(xk))
	0
	11833,0000000
	13631,00000000
	23666,0000000
	11832,4240260
	1
	11832,4240260
	0,331746011972
	23664,8480521
	11832,4240120
	2
	11832,4240120
	0,000000000000
	23664,8480240
	11832,4240120
	3
	11832,4240120
	0,000000000000
	23664,8480240
	11832,4240120
f’(x)=2x
f’(11832)=23664
f’(11833)=23666
A derivada de A0 é menor que a de B0
f’(x)=2x e f”(x)=2 portanto não são nulas porém f(x)*f”(x)<0 para A0 e B0 
Questão 4: RA→140006258
Encontrar o raio da esfera
Volume da semi esfera = 10000l=10m3
Volume da esfera = 20000l=20m3
20m3=(4πR3)/3
R3=4,775m3
R=1,683890301m
Volume admissível = 6,258m3
 6,258=[πh2(3R-h)]/3
 -h3+5,051670903h2-5,975949803=0
 Calculando as raízes do polinômio pelo método de Bairstow encontramos x1 ,x2 e x3 sendo estas:
x1 = 1,25450945535557852m
x2 = -0,994200585653303853m não admissível
x3 = 4,79136203329772533m supera o limite de altura da calota
Portanto a boia deve ser instalada a 1,254509... m de altura.
Questão 5:
i ) 
A = | 140006259 140006258 | * | X | = | 1 |
 |140006258 140006257 | | Y | | 0 |
detA = (140006259*140006257)-(140006258*140006258)
detA = 0. 
O sistema é indeterminado.
ii ) 
A-1 = inversa =
 
 0.7142538*10-8 0.7142538*10-8 
 0.7142538*10-8 0.7142538*10-8