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Tiago Lima - Instagram: @professor_disciplinas_exatas • Seja f x, y, z =( ) xyz Calcule fx, fy e fz. Resolução: As derivadas parciais de são;f x, y, z = = xyz( ) xyz ( ) 1 3 f = = xyz ⋅ yz = xyz ⋅ yz = xyz ⋅ yz = =x 𝜕f 𝜕x 1 3 ( ) -1 1 3 1 3 ( ) 1- 3 3 1 3 ( ) -2 3 yz 3 xyz( ) 2 3 yz 3x y z 2 3 2 3 2 3 = = = = = = y ⋅ z 3x 1- 2 3 1- 2 3 2 3 y ⋅ z 3x 3- 2 3 3- 2 3 2 3 y z 3x 1 3 1 3 2 3 yz 3x ( ) 1 3 2 3 3 yz x2 1 3 xz x2 f = = xyz ⋅ xz = xyz ⋅ xz = xyz ⋅ xz = =y 𝜕f 𝜕y 1 3 ( ) -1 1 3 1 3 ( ) 1- 3 3 1 3 ( ) -2 3 xz 3 xyz( ) 2 3 xz 3x y z 2 3 2 3 2 3 = = = = = = x ⋅ z 3y 1- 2 3 1- 2 3 2 3 x ⋅ z 3y 3- 2 3 3- 2 3 2 3 x z 3y 1 3 1 3 2 3 xz 3y ( ) 1 3 2 3 3 xz y2 1 3 xz y2 f = = xyz ⋅ xy = xyz ⋅ xy = xyz ⋅ xy = =z 𝜕f 𝜕z 1 3 ( ) -1 1 3 1 3 ( ) 1- 3 3 1 3 ( ) -2 3 xy 3 xyz( ) 2 3 xy 3x y z 2 3 2 3 2 3 = = = = = = x ⋅ y 3z 1- 2 3 1- 2 3 2 3 x ⋅ y 3z 3- 2 3 3- 2 3 2 3 x y 3z 1 3 1 3 2 3 xy 3z ( ) 1 3 2 3 3 xy z2 1 3 xy z2 3 3 3 3 3 3 3 3 3 3 3 (Resposta - 1) (Resposta - 2) (Resposta - 3)
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