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Prévia do material em texto
Encontre a função de transferência do sistema elétrico mostrado na figura a seguir: E0(s)Ei(s)=(R1C1s+1)2(R1C1s+1)(R2C2s+1)+R2C1sE0(s)Ei(s)=(R1C1s+1)2(R1C1s+1)(R2C2s+1)+R2C1s E0(s)Ei(s)=(R1C1s+1)2(R1C1s+1)(R2C2s+1)+R2C1s2E0(s)Ei(s)=(R1C1s+1)2(R1C1s+1)(R2C2s+1)+R2C1s2 E0(s)Ei(s)=(R1C1s+1)(R2C2s+1)(R1C1s+1)(R2C1s+1)+R1C1sE0(s)Ei(s)=(R1C1s+1)(R2C2s+1)(R1C1s+1)(R2C1s+1)+R1C1s E0(s)Ei(s)=(R1C1s+1)(R2C2s+1)(R2C2s+1)+R2C1sE0(s)Ei(s)=(R1C1s+1)(R2C2s+1)(R2C2s+1)+R2C1s E0(s)Ei(s)=(R1C1s+1)(R2C2s+1)(R1C1s+1)(R2C2s+1)+R2C1sE0(s)Ei(s)=(R1C1s+1)(R2C2s+1)(R1C1s+1)(R2C2s+1)+R2C1s Explicação:
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