Prévia do material em texto
<p>02- MM= C 21 H 30 O2 = I 26 30 1-mol 6,02.10 1 mol C H II 32g 80 1000 X X 314 26 g 314X 6,02.10 23 252000 252000 6,02.1023 314 04- 12 mg FE 05- 1 5.10 56 w 2 56 = I Na 0 X 1 Ca 6.10 ca 23 X = 40 Ca II g 1 40 X= - of X = 4.10 X=1,5.10 22 tilibra</p><p>/ / 06- = 27 = 1,8 mg 1 mol Al 6.10 at N° = 9 27 g 6.1023 al MAC = 12u = 12 g/ mol 500 al X 1 C C 12g C C 2MX = X 23 27 X= 1025 12X 08 MM= 291 12 1 mol - 6-1023 atoms 291, of X 1 291 09- = 1 106g X 106 X = 132 X =132 10 = 106 X= MMc5 Hey O3 = + food 1 mol moleculor 168g 6.1023 168X = 168X = 168 X= tilibra</p>