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CHAPTER 8 267 8.77. There is only one alkene (compound Y, shown below) that is consistent with the information provided in the problem statement. Ozonolysis of that alkene results in cleavage of the C=C bond to give two separate compounds, each of which has a C=O bond, shown below: Br HBr, ROOR O 1) O3 2) DMS H H O+H2, Pt Compound Y C7H12 8.78. Each of the products is an aldehyde, and their sp2 hybridized carbon atoms were once connected to each other as a C=C bond in the original alkene. That gives the following two possibilities (stereoisomers) for the structure of the original alkene: 8.79. (a) In the presence of aqueous acid, the epoxide is first protonated (two curved arrows), as shown below. The resulting intermediate can then undergo an SN2-like, intramolecular attack (two curved arrows), in which the OH group functions as the nucleophilic center. Then, in the final step of the mechanism, a molecule of water functions as a base and removes a proton, thereby generating the product. This final step is a proton transfer step, and therefore requires two curved arrows: O OH O OH H H O H H HO HO H O HO O H (b) In the presence of aqueous acid, the epoxide is first protonated (two curved arrows), as shown. The resulting intermediate can then undergo an SN2-like, intramolecular attack (two curved arrows), in which the bond functions as the nucleophilic center. Then, in the final step of the mechanism, a molecule of water functions as a base and removes a proton, thereby generating the product. This final step is a proton transfer step, and therefore requires two curved arrows: 8.80. Treatment of the alkyl halide with a strong base gives an alkene which can then be converted into the desired product via ozonolysis: 8.81. When the alkene is treated with molecular bromine (Br2), the bond functions as a nucleophilic center and attacks Br2 (three curved arrows), resulting in an intermediate bromonium ion. The bromonium ion is then subject to attack by a nucleophilic center, such as www.MyEbookNiche.eCrater.com