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Step of 5 8.004P Refer to Figure 7.23 in the textbook for the Channel width of transistor is five times the channel width of transistor The transistors have equal channel length. 4=4 The output current of the current mirror circuit is, W Substitute 4 for for and 20 for in the equation. 5W, =100x10⁻⁶ Hence, the output current is, Step of 5 Minimum allowable value of is equal to over drive voltage. The over drive voltage is, = 0.7 V Step of 5 The drain current in linear region is, I W I The condition for nominal value of current is Substitute this in the equation. 20 20 20 =0.7 V Thus, the output voltage is, Step of 5 The output resistance is, 20 = Step of 5 Write the equation for output resistance. Rearrange the equation. Substitute 200 kΩ for R. and 1 V for in the equation 1 Thus, the change in drain current is,