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Step of 6 8.006E Refer to Figure 8.12(a) from the text book. Calculate the value of the output current I₀ Substitute 5 for and 100 for Therefore, the value of the output current is 500 Step of 6 Calculate the value of the output resistance Substitute 20 V/µm for 40 for and 500 for 40 k = 20 500 4 = 20 4 µm Therefore, the value of the length 4 is 1 The value of the length 4 is equal to the value of the length 4 therefore, the value of the is 1 µm Step of 6 Consider the expression for the input resistance. Substitute kΩ for 1 1k 8ml 1 k 8ml mS Therefore, the value of the transconductance 8ml is mS Step of 6 Consider the expression for transconductance 8ml in terms of the over drive voltage and the bias current. Substitute 100 for and 1 mA for 1 m 200 m 0.2 V Therefore, the value of the over drive voltage is 0.2 V Step of 6 Consider the expression for the transconductance = Substitute 0.2 V for mA for 8ml 1 µm for 4 and 400 for = 12.5 µm Therefore, the value of the width is 12.5 µm Step of 6 Calculate the value of the current gain = Substitute 12.5 µm for 5 for and 4 for 5 5 W₂ Therefore, the value of the width is 62.5 µm