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Step of 5 8.009P Refer to Figure 8.7 from the text book. Consider the circuit diagram shown in Figure 1 REF I₀ + + BE2 - - - - Figure 1 Step 5 Consider the relation for the base to emitter voltages for both the transistors Substitute In for and In for In But equal m Hence, m Therefore, the value of the current m Step 5 Consider the expression for the reference current. Substitute for and for Substitute for m m = m m REF 1+m (1) m Therefore, the expression for the current transfer ratio is 1+m 1+ Step of 5 Recall equation (1) Substitute 8 for m 8 1+0 =m (2) Step 5 Recall equation (1). REF Here, is 10% lower to the value of equation m Substitute 80 for 0.9 80 1+m 80 0.9 1+m 10 1+ 80 9 1+m 10 80 1+m 10-9 80 9 1+m 80 9 80 1+m 9 80 9 80-9 m 9 71 9 =7.89 Therefore, the value of the current transfer ratio m is 7.89