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Semiconductor Physics and Devices: Basic Principles, 4
th
 edition Chapter 7 
By D. A. Neamen Problem Solutions 
______________________________________________________________________________________ 
 
 
    2612 1025.1210904.4
1


 
L 
 310306.3  H 306.3 mH 
(b) 
 (i) For 1RV V, 14.12C pF 
 
    2/1123 1014.1210306.32
1
 


f 
 51094.7  Hz 794.0 MHz 
 (ii) For 5RV V, 704.6C pF 
 
    2/1123 10704.610306.32
1
 


f 
 
610069.1  Hz 069.1 MHz 
_______________________________________ 
 
7.26 
 
 
2/1
max
2









s
dRbi NVVe
 
 Let 75.0biV V 
(a)  25105.2  
 
  
   












14
19
1085.87.11
1075.0106.12 dN
 
 161088.1  dN cm 3 
(b)  2510 
 
  
   












14
19
1085.87.11
1075.0106.12 dN
 
 151001.3  dN cm 3 
_______________________________________ 
 
7.27 
     pnp xxWx  20.020.0 
     np xx 2.08.0  
 pn xx 4 
  pdndpa xNxNxN 4 
 da NN 4 
(a) 









2
ln
i
da
tbi
n
NN
VV 
  
  









26
2
108.1
4
ln0259.0 dN
 
 
  
2/1
2 








daRbi
das
NNVV
NNe
ACAC 
 
      
 







22
1085.81.13106.1
10
1419
4
biV
 
 
 
 
2/1
2
5
4





d
d
N
N
 
 
2
10724.2106.0 2012

 
bi
d
V
N
 
 By trial and error, 
 1510504.1 dN cm 3 , 
 1510016.6 aN cm 3 , 
 10.1biV V 
(b) From part (a), 
 
5
10724.2106.0 2012

 
bi
d
V
N
 
 By trial and error, 
 1510976.2 dN cm 3 , 
 161019.1 aN cm 3 , 
 135.1biV V 
_______________________________________ 
 
7.28 
(a)  
  
  










210
1415
105.1
10105
ln0259.0biV 
 or 
 5574.0biV V 
 (b) 
 
2/1
12

























daa
dbis
p
NNN
N
e
V
x 
 
   








19
14
106.1
5574.01085.87.112
 
 
2/1
151415
14
10510
1
105
10



















 
 or 
 
61032.5 px cm 
 Also 
 
2/1
12

























dad
abis
n
NNN
N
e
V
x

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