exercícios de resmat II
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exercícios de resmat II


DisciplinaResmat II465 materiais1.498 seguidores
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\ud835\udc70\ud835\udc99 =
\ud835\udc83 . \ud835\udc89³
\ud835\udfcf\ud835\udfd0
=
\ud835\udfd3 . \ud835\udfd0, \ud835\udfd3³
\ud835\udfcf\ud835\udfd0
= \ud835\udfd4, \ud835\udfd3\ud835\udfcf\ud835\udc8e\u2074 
\u1a0\ud835\udc87\ud835\udc8d =
\ud835\udf452. \ud835\udc6c . \ud835\udc70
\ud835\udc8d2\ud835\udc87. \ud835\udc68
=
\ud835\udf452. \ud835\udfd0, \ud835\udfcf\ud835\udfce . \ud835\udfcf\ud835\udfce6. \ud835\udfd4, \ud835\udfd3\ud835\udfcf
\ud835\udfcf\ud835\udfd3\ud835\udfce2 . \ud835\udfcf\ud835\udfd0, \ud835\udfd3
= \ud835\udfd2\ud835\udfd6\ud835\udfce\ud835\udc77\ud835\udc82 
Momento de inercia 
- Peça biarticulada 
- Seção retangular de 30x50cm 
- comprimento de 4,3m 
- Instalações 
- 0 < \ud835\udf40 < 40 \uf0e0 mínima tendência a flambar 
- 40 < \ud835\udf40 < 80 \uf0e0Tendência a flambar 
- \ud835\udf40 > 80 \uf0e0Flambagem 
\ud835\udf40 = \ud835\udc8d\ud835\udc87\u221a
\ud835\udc68 
\ud835\udc70
 
\ud835\udc83 . \ud835\udc89 
\ud835\udc83 . \ud835\udc89³
\ud835\udfcf\ud835\udfd0
 
\ud835\udc83 . \ud835\udc89 = \ud835\udfd3\ud835\udfce . \ud835\udfd1\ud835\udfce = \ud835\udfcf\ud835\udfd3\ud835\udfce\ud835\udfce\ud835\udfce\ud835\udc8e² 
\ud835\udc68 = \ud835\udfce, \ud835\udfcf\ud835\udfd3\ud835\udc8e² 
\ud835\udf40 = \ud835\udfd2, \ud835\udfd1\u221a
\ud835\udfce, \ud835\udfcf\ud835\udfd3 
\ud835\udfcf, \ud835\udfcf\ud835\udfd1 . \ud835\udfcf\ud835\udfce\u207b³
\u2234 \ud835\udfd2\ud835\udfd7, \ud835\udfd3 
49,5 > 40 \uf0e0 Tendência a flambar 
 
1 \u2013 Uma barra de aço de seção retangular de 2,5mx5m, articulada nas 2 extremidades é 
comprimida axialmente. Dados: \u1a0P = 2,10 KPa E = 2,10 Mpa 
Determine 
a) O comprimento mínimo para aplicar a formula de Euler 
 
 
b) A tensão de flambagem no caso do comprimento da barra ser 150m 
 
 
2 \u2013 Identifique a situação de um pilar de concreto armado (peça comprimida) com os dados a 
seguir: 
 
 
 
 
 
 
 
Para o caso de flambagem ou tendência a flambar, proponha uma solução para minimizar esse 
efeito. 
 
 
 
 
 
 
 
 
\ud835\udc70\ud835\udc9a =
\ud835\udc83 . \ud835\udc89³
\ud835\udfcf\ud835\udfd0
=
\ud835\udfd0, \ud835\udfd3 . \ud835\udfd3³
\ud835\udfcf\ud835\udfd0
= \ud835\udfd0\ud835\udfd4, \ud835\udfce\ud835\udfd2\ud835\udc8e\u2074 
\u1a0\ud835\udc84\ud835\udc93 =
\ud835\udf452. \ud835\udc6c . \ud835\udc70
\ud835\udc8d2 . \ud835\udc68
= \ud835\udc8d = \u221a
(\ud835\udfd0, \ud835\udfcf . \ud835\udfcf\ud835\udfce6 . \ud835\udfd4, \ud835\udfd3\ud835\udfcf) 
(\ud835\udfd0, \ud835\udfcf\ud835\udfce . \ud835\udfcf\ud835\udfce3. \ud835\udfcf\ud835\udfd0, \ud835\udfd3)
 . \ud835\udf45 = \ud835\udfd5\ud835\udfcf, \ud835\udfd4\ud835\udfd7\ud835\udc8e 
\ud835\udc70\ud835\udc99 =
\ud835\udc83 . \ud835\udc89³
\ud835\udfcf\ud835\udfd0
=
(\ud835\udfd3\ud835\udfce. \ud835\udfcf\ud835\udfce-2). (\ud835\udfd1\ud835\udfce . \ud835\udfcf\ud835\udfce-2)³
\ud835\udfcf\ud835\udfd0
= \ud835\udfcf, \ud835\udfcf\ud835\udfd1 . \ud835\udfcf\ud835\udfce\u207b³\ud835\udc8e\u2074 
\ud835\udc70\ud835\udc9a =
\ud835\udc83 . \ud835\udc89³
\ud835\udfcf\ud835\udfd0
=
(\ud835\udfd1\ud835\udfce . \ud835\udfcf\ud835\udfce-2). (\ud835\udfd3\ud835\udfce . \ud835\udfcf\ud835\udfce-2)³
\ud835\udfcf\ud835\udfd0
= \ud835\udfd1, \ud835\udfcf\ud835\udfd1 . \ud835\udfcf\ud835\udfce\u207b³\ud835\udc8e\u2074 
\ud835\udc8d 
\ud835\udfd3\ud835\udfce\ud835\udc8e\ud835\udc8e 
\ud835\udf40 = \ud835\udc8d\ud835\udc87\u221a
\ud835\udc68 
\ud835\udc70
 
\ud835\udc8d\ud835\udc87 = \ud835\udfce, \ud835\udfd3\ud835\udc8d 
\ud835\udc68 = \u41f\ud835\udf452 = \ud835\udf45 . (\ud835\udfd0\ud835\udfd3 . \ud835\udfcf\ud835\udfce-3)2 = \ud835\udc68 = \ud835\udfcf, \ud835\udfd7\ud835\udfd4 . \ud835\udfcf\ud835\udfce
-3\ud835\udc8e² 
Momento de inercia 
\ud835\udfcf\ud835\udfce\ud835\udfd3 = \ud835\udfce, \ud835\udfd3\ud835\udc8d\u221a
\ud835\udfcf, \ud835\udfd7\ud835\udfd4 . \ud835\udfcf\ud835\udfce\u207b³ 
\ud835\udfd1, \ud835\udfce\ud835\udfd5 . \ud835\udfcf\ud835\udfce\u207b\u2077
 
\ud835\udfd5
,\ud835\udfd0
\ud835\udc8e
 
\ud835\udc77\ud835\udc82\ud835\udc93 
\ud835\udc77\ud835\udc82\ud835\udc93 
\ud835\udfd5\ud835\udfd3\ud835\udc8e\ud835\udc8e 
\ud835\udc77\ud835\udc82\ud835\udc93 =
\ud835\udf452. \ud835\udc6c . \ud835\udc70
\ud835\udc8d²\ud835\udc87
 
\ud835\udc70 =
\ud835\udf45. (\ud835\udc6b4. \ud835\udc854) 
\ud835\udfd4\ud835\udfd2
 
\ud835\udc77\ud835\udc82\ud835\udc93 =
\ud835\udf452. \ud835\udc6c 
\ud835\udc8d²\ud835\udc87
 .
\ud835\udf45. (\ud835\udc6b4. \ud835\udc854) 
\ud835\udfd4\ud835\udfd2
 
\ud835\udc77\ud835\udc82\ud835\udc93 =
\ud835\udf452. \ud835\udfd0\ud835\udfce\ud835\udfce . \ud835\udfcf\ud835\udfce\u2079 
\ud835\udfd5, \ud835\udfd0²
 .
\ud835\udf45. ((\ud835\udfd5\ud835\udfd3 . \ud835\udfcf\ud835\udfce-3)4 \u2212 (\ud835\udfd5\ud835\udfce . \ud835\udfcf\ud835\udfce-3)4) 
\ud835\udfd4\ud835\udfd2
= \ud835\udfcf\ud835\udfd2, \ud835\udfd1\ud835\udc72\ud835\udc75 
\u1a0\ud835\udc84\ud835\udc93 =
\ud835\udc77\ud835\udc82\ud835\udc93
\ud835\udc68
 \ud835\udc68 =
\ud835\udf45. (\ud835\udc6b². \ud835\udc85²) 
\ud835\udfd2
 
\u1a0\ud835\udc84\ud835\udc93 =
\ud835\udc77\ud835\udc82\ud835\udc93
\ud835\udf45. (\ud835\udc6b². \ud835\udc85²) 
\ud835\udfd2
 
\u1a0\ud835\udc84\ud835\udc93 =
\ud835\udfcf\ud835\udfd2, \ud835\udfd1 . \ud835\udfcf\ud835\udfce³
\ud835\udf45. ((\ud835\udfd5\ud835\udfd3 . \ud835\udfcf\ud835\udfce \u207b³)² \u2212 (\ud835\udfd5\ud835\udfce . \ud835\udfcf\ud835\udfce-3)²) 
\ud835\udfd2
 
\u1a0\ud835\udc84\ud835\udc93 = \ud835\udfd0\ud835\udfd3, \ud835\udfcf\ud835\udc74\ud835\udc77\ud835\udc82 
\u1a0\ud835\udc84\ud835\udc93 < \u1a0\ud835\udc91 \u2192 \ud835\udc6c\ud835\udc94\ud835\udc95á \ud835\udc8f\ud835\udc90 \ud835\udc8d\ud835\udc8a\ud835\udc8e\ud835\udc8a\ud835\udc95\ud835\udc86 \ud835\udc85\ud835\udc86 \ud835\udc6c\ud835\udc96\ud835\udc8d\ud835\udc86\ud835\udc93 
Domínio de Euler 
 
3 \u2013 Determine o comprimento mínimo para a aplicação da equação de Euler sabendo que para 
isso. \u3bb\u2265 105 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
4 \u2013 Um tubo de aço com 7,2m de comprimento e seção transversal vazado, deve ser usado 
como uma coluna presa por pinos nas extremidades. Determine a carga axial crítica sem sobre 
flambagem e verifique o domínio de Euler sabendo que \u1a0 = 250MPa e Eaço = 200GPa 
 
 
 
 
 
 
 
 
 
 
 
\ud835\udc70\ud835\udc99 = \ud835\udc70\ud835\udc9a =
\ud835\udf45 . \ud835\udc85\u2074
\ud835\udfd4\ud835\udfd2
=
\ud835\udf45 . (\ud835\udfd3\ud835\udfce . \ud835\udfcf\ud835\udfce-2)\u2074
\ud835\udfd4\ud835\udfd2
= \ud835\udfd1, \ud835\udfce\ud835\udfd5 . \ud835\udfcf\ud835\udfce\u207b\u2077\ud835\udc8e\u2074 
\ud835\udc8d =
\ud835\udfcf\ud835\udfce\ud835\udfd3
\ud835\udfce, \ud835\udfd3\u221a
\ud835\udfcf, \ud835\udfd7\ud835\udfd4 . \ud835\udfcf\ud835\udfce\u207b³
\ud835\udfd1, \ud835\udfce\ud835\udfd5 . \ud835\udfcf\ud835\udfce\u207b\u2077
\u2234 \ud835\udc8d = \ud835\udfd0, \ud835\udfd4\ud835\udfd1\ud835\udc8e 
\u1a0\ud835\udc8e\ud835\udc99 =
\ud835\udc77
\ud835\udc68
+
\ud835\udc74\ud835\udc8e\ud835\udc99\ud835\udc82
\ud835\udc70
 
á\ud835\udc93\ud835\udc86\ud835\udc82: \ud835\udc68 = \u41f\ud835\udf452 = \ud835\udf45(\ud835\udfcf\ud835\udfce\ud835\udfce . \ud835\udfcf\ud835\udfce-3)² 
\ud835\udc68 = \ud835\udfd1, \ud835\udfcf\ud835\udfd2 . \ud835\udfcf\ud835\udfce\u207b²\ud835\udc8e² 
Momento 
\ud835\udc74\ud835\udc8e\ud835\udc99 = \ud835\udc77 . \ud835\udc84 = \ud835\udfd0\ud835\udfce\ud835\udfce . \ud835\udfcf\ud835\udfce3. \ud835\udfd3 . \ud835\udfcf\ud835\udfce\u207b³ \ud835\udc74\ud835\udc8e\ud835\udc99 = \ud835\udfcf\ud835\udfce\ud835\udfce\ud835\udc75. \ud835\udc8e 
\ud835\udc82 = \ud835\udfcf\ud835\udfce\ud835\udfce\ud835\udc8e\ud835\udc8e 
\ud835\udc70 =
\ud835\udf45. \ud835\udc854 
\ud835\udfd4\ud835\udfd2
= \ud835\udc70 =
\ud835\udf45 . (\ud835\udfd0\ud835\udfce\ud835\udfce . \ud835\udfcf\ud835\udfce-3)\u2074 
\ud835\udfd4\ud835\udfd2
= \ud835\udfd5, \ud835\udfd6\ud835\udfd3 . \ud835\udfcf\ud835\udfce\u207b\u2075\ud835\udc8e\u2074 
substituído 
\u1a0\ud835\udc8e\ud835\udc99 =
\ud835\udfd0\ud835\udfce\ud835\udfce . \ud835\udfcf\ud835\udfce³
\ud835\udfd1, \ud835\udfcf\ud835\udfd2 . \ud835\udfcf\ud835\udfce \u207b²
+
\ud835\udfcf\ud835\udfce\ud835\udfce\ud835\udfce . \ud835\udfcf\ud835\udfce\ud835\udfce . \ud835\udfcf\ud835\udfce\u207b³
\ud835\udfd5, \ud835\udfd6\ud835\udfd3 . \ud835\udfcf\ud835\udfce\u207b\u2075
= \ud835\udfd5, \ud835\udfd4\ud835\udfd2\ud835\udc74\ud835\udc77\ud835\udc82 \u1a0\ud835\udc8e\ud835\udc99 =
\ud835\udc77
\ud835\udc68
+
\ud835\udc74\ud835\udc8e\ud835\udc99\ud835\udc82
\ud835\udc70
 
\ud835\udc8d 
 
 
5 \u2013 Uma barra circular maciça de alumínio está engastada na sua base e livre na extremidade 
superior se a carga axial excêntrico de 200KN está aplicada com uma excentricidade de 5mm, 
determine a tensão máxima. 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
\ud835\udfcf\ud835\udfd3\ud835\udfce\ud835\udc8e\ud835\udc8e \ud835\udfcf\ud835\udfd3\ud835\udfce\ud835\udc8e\ud835\udc8e 
\ud835\udfd3
\ud835\udfce
\ud835\udc8e
\ud835\udc8e
 
\ud835\udfd3
\ud835\udfce
\ud835\udc8e
\ud835\udc8e
 
\ud835\udc73\ud835\udc96 \ud835\udfd3
\ud835\udfce
\ud835\udc8e
\ud835\udc8e
 
\ud835\udfd3
\ud835\udfce
\ud835\udc8e
\ud835\udc8e
 
\ud835\udc92 =
\ud835\udc78\ud835\udc74\ud835\udc94
\ud835\udc70
 \ud835\udc92 =
\ud835\udc8f\ud835\udc6d
\ud835\udc7a
 
\ud835\udc7a = \ud835\udfcf\ud835\udfd3\ud835\udfce\ud835\udc8e\ud835\udc8e = \ud835\udfcf\ud835\udfd3\ud835\udfce . \ud835\udfcf\ud835\udfce-³ 
\ud835\udc78 = \ud835\udfd1\ud835\udc72\ud835\udc75 = \ud835\udfd1 . \ud835\udfcf\ud835\udfce³ 
\ud835\udc6d =? 
 
Momento Estático 
\ud835\udc92 =
\ud835\udc78\ud835\udc74\ud835\udc94
\ud835\udc70
 
\ud835\udc74\ud835\udc94 = \ud835\udc68 . \ud835\udc85 = \ud835\udc83 . \ud835\udc89 . \ud835\udc85 
\ud835\udc74\ud835\udc94 = \ud835\udfcf\ud835\udfd3\ud835\udfce . \ud835\udfcf\ud835\udfce-3. \ud835\udfd3\ud835\udfce . \ud835\udfcf\ud835\udfce-3. \ud835\udfd0\ud835\udfd3 . \ud835\udfcf\ud835\udfce-3 = \ud835\udfcf, \ud835\udfd6\ud835\udfd6 . \ud835\udfcf\ud835\udfce\u207b\u2074\ud835\udc8e³ 
Momento de Inércia 
\ud835\udc70 =
\ud835\udc83 . \ud835\udc89³
\ud835\udfcf\ud835\udfd0
=
(\ud835\udfcf\ud835\udfd3\ud835\udfce . \ud835\udfcf\ud835\udfce \u207b³) . (\ud835\udfcf\ud835\udfce\ud835\udfce . \ud835\udfcf\ud835\udfce-3)³
\ud835\udfcf\ud835\udfd0
= \ud835\udfcf, \ud835\udfd0\ud835\udfd3 . \ud835\udfcf\ud835\udfce\u207b\u2075\ud835\udc8e\u2074 
Substituindo
: 
\ud835\udc92 =
\ud835\udc78\ud835\udc74\ud835\udc94
\ud835\udc70
 \ud835\udc92 =
\ud835\udfd1 . \ud835\udfcf\ud835\udfce3 . \ud835\udfcf, \ud835\udfd6\ud835\udfd6 . \ud835\udfcf\ud835\udfce\u207b\u2074
\ud835\udfcf, \ud835\udfd0\ud835\udfd3 . \ud835\udfcf\ud835\udfce\u207b\u2075
= \ud835\udfd2, \ud835\udfd3\ud835\udfcf . \ud835\udfcf\ud835\udfce\u2074\ud835\udc75/\ud835\udc8e 
\ud835\udc92 =
\ud835\udc8f\ud835\udc6d
\ud835\udc7a
\u2234 \ud835\udc6d =
\ud835\udc92\ud835\udc7a
\ud835\udc8f
=
\ud835\udfd2, \ud835\udfd3\ud835\udfcf . \ud835\udfcf\ud835\udfce4 . \ud835\udfcf\ud835\udfd3\ud835\udfce . \ud835\udfcf\ud835\udfce\u207b³
\ud835\udfd0
= \ud835\udfd1, \ud835\udfd1\ud835\udfd6\ud835\udc72\ud835\udc75 
 
CISALHAMENTO 
 
A viga é construída com 2 tábuas presas, uma força de cisalhamento interno de 3KN for 
aplicada às tábuas. Determine a força de cisalhamento à qual cada prego resistirá. 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
\ud835\udc7a = \ud835\udfcf\ud835\udfd3\ud835\udfce\ud835\udc8e\ud835\udc8e = \ud835\udfcf\ud835\udfd3\ud835\udfce . \ud835\udfcf\ud835\udfce-³ 
\ud835\udc6d = \ud835\udfd0, \ud835\udfd3\ud835\udc72\ud835\udc75 
\ud835\udc78 =? 
 
\ud835\udc92 =
\ud835\udc78\ud835\udc74\ud835\udc94
\ud835\udc70
 \ud835\udc92 =
\ud835\udc8f\ud835\udc6d
\ud835\udc7a
 
\ud835\udc78\ud835\udc74\ud835\udc94
\ud835\udc70
=
\ud835\udc8f\ud835\udc6d
\ud835\udc7a
 
\ud835\udc78 =
\ud835\udc8f\ud835\udc6d\ud835\udc70
\ud835\udc7a\ud835\udc74\ud835\udc94
=
\ud835\udfd0 . \ud835\udfd0, \ud835\udfd3 . \ud835\udfcf\ud835\udfce3 . \ud835\udfcf, \ud835\udfd0\ud835\udfd3 . \ud835\udfcf\ud835\udfce\u207b\u2075
\ud835\udfcf\ud835\udfd3\ud835\udfce . \ud835\udfcf\ud835\udfce-3 . \ud835\udfcf, \ud835\udfd6\ud835\udfd6 . \ud835\udfcf\ud835\udfce\u207b\u2074
= \ud835\udfd0, \ud835\udfcf\ud835\udc72\ud835\udc75 
\ud835\udfd3
\ud835\udfce
\ud835\udc8e
\ud835\udc8e
 
\ud835\udfd3
\ud835\udfce
\ud835\udc8e
\ud835\udc8e
 
\ud835\udfcf\ud835\udfd3\ud835\udfce\ud835\udc8e\ud835\udc8e 
\ud835\udd75\ud835\udc91 =
\ud835\udc78\ud835\udc74\ud835\udc94
\ud835\udc83 . \ud835\udc70
 
Momento Estático 
\ud835\udc74\ud835\udc94 = \ud835\udc68 . \ud835\udc85 = \ud835\udfcf\ud835\udfce\ud835\udfce . \ud835\udfcf\ud835\udfce-3. \ud835\udfd3\ud835\udfce . \ud835\udfcf\ud835\udfce-3. (\ud835\udfcf\ud835\udfd0, \ud835\udfd3 + \ud835\udfd0\ud835\udfd3)3. \ud835\udfcf\ud835\udfce = 
\ud835\udc74\ud835\udc94 = \ud835\udfcf, \ud835\udfd6\ud835\udfd6 . \ud835\udfcf\ud835\udfce\u207b\u2074\ud835\udc8e³ 
Momento de Inércia 
\ud835\udc70 =
\ud835\udc83 . \ud835\udc89³
\ud835\udfcf\ud835\udfd0
=
(\ud835\udfcf\ud835\udfce\ud835\udfce . \ud835\udfcf\ud835\udfce \u207b³) . (\ud835\udfcf\ud835\udfd0\ud835\udfd3 . \ud835\udfcf\ud835\udfce-3)³
\ud835\udfcf\ud835\udfd0
= \ud835\udfcf, \ud835\udfd4\ud835\udfd1 . \ud835\udfcf\ud835\udfce\u207b\u2075\ud835\udc8e\u2074 
Tensão no ponto P 
\ud835\udd75\ud835\udc91 =
\ud835\udfd1 . \ud835\udfcf\ud835\udfce3 . \ud835\udfcf, \ud835\udfd6\ud835\udfd6 . \ud835\udfcf\ud835\udfce\u207b\u2074
\ud835\udfcf\ud835\udfce\ud835\udfce . \ud835\udfcf\ud835\udfce-3 . \ud835\udfcf, \ud835\udfd4\ud835\udfd1 . \ud835\udfcf\ud835\udfce\u207b\u2075
= \ud835\udfce, \ud835\udfd1\ud835\udfd2\ud835\udfd4\ud835\udc74\ud835\udc77\ud835\udc82 
\ud835\udd75\ud835\udc8e\ud835\udc99 = \ud835\udfcf, \ud835\udfd3
\ud835\udc78
\ud835\udc68
=
\ud835\udfd1 . \ud835\udfcf\ud835\udfce³
\ud835\udfcf\ud835\udfce\ud835\udfce . \ud835\udfcf\ud835\udfce\u207b³
 
\ud835\udfcf, \ud835\udfd3
\ud835\udfcf\ud835\udfd0\ud835\udfd3 . \ud835\udfcf\ud835\udfce\u207b³
 
\ud835\udd75\ud835\udc8e\ud835\udc99 = \ud835\udfce, \ud835\udfd1\ud835\udfd4\ud835\udc74\ud835\udc77\ud835\udc82 
\ud835\udc77 
\ud835\udc77 
\ud835\udfcf
\ud835\udfd0
\ud835\udfd3
\ud835\udc8e
\ud835\udc8e
 
\ud835\udfd3
\ud835\udfce
\ud835\udc8e
\ud835\udc8e
 \ud835\udfd3
\ud835\udfce
\ud835\udc8e
\ud835\udc8e
 
\ud835\udfcf
\ud835\udfd0
\ud835\udfd3
\ud835\udc8e
\ud835\udc8e
 
\ud835\udfcf\ud835\udfce\ud835\udfce\ud835\udc8e\ud835\udc8e 
\ud835\udfd0\ud835\udfd3\ud835\udc8e\ud835\udc8e 
\ud835\udfcf\ud835\udfd0, \ud835\udfd3\ud835\udc8e\ud835\udc8e 
\ud835\udc73\ud835\udc75 
\ud835\udfd4
\ud835\udfd0
,\ud835\udfd3
\ud835\udc8e
\ud835\udc8e
 
\ud835\udfd4
\ud835\udfd0
,\ud835\udfd3
\ud835\udc8e
\ud835\udc8e
 
 
 
A viga é construída com 2 tábuas presas uma à outra na parte superior e na parte inferior por 2 
fileiras de pregos espaçados de 150mm. 
Se cada prego puder suporta uma força de cisalhamento de 2,5KN, determine a força de 
cisalhamento máximo que pode ser aplicada na viga. 
 DADOS: Ms = 1,88 . 10\u207b\u2074m³ e I =1,25 . 10\u207b\u2075m\u2074 
 
 
 
 
 
 
 
 
 
2 \u2013 A viga mostrada na figura é feita de madeira e está sujeita a uma força de cisalhamento 
interna resultante de 3KN. Determine a tensão de cisalhamento no pontal P e a tensão de 
cisalhamento máximo. 
 
 
 
 
 
 
 
 
 
 
 
 
 
\ud835\udd75\ud835\udc8e\ud835\udc99 =
\ud835\udc78
\ud835\udc85 . \ud835\udc89
 
\ud835\udd75\ud835\udc8e\ud835\udc99 =
\ud835\udfd2\ud835\udfd2 . \ud835\udfcf\ud835\udfce³
\ud835\udfd4 . \ud835\udfcf\ud835\udfce-3 . \ud835\udfd4\ud835\udfd0 . \ud835\udfcf\ud835\udfce\u207b³
= \ud835\udfcf, \ud835\udfcf\ud835\udfd6\ud835\udc74\ud835\udc77\ud835\udc82 
\ud835\udfd2\ud835\udfd0\ud835\udc84\ud835\udc8e 
\ud835\udfd3\ud835\udfce\ud835\udc84\ud835\udc8e 
\ud835\udfd4\ud835\udc84\ud835\udc8e 
\ud835\udfd4\ud835\udc84\ud835\udc8e 
\ud835\udfd4\ud835\udc84\ud835\udc8e 
\ud835\udfd1\ud835\udfce\ud835\udc8e\ud835\udc8e 
\ud835\udc78 
\ud835\udd75\ud835\udc8e\ud835\udc99 =
\ud835\udfd2
\ud835\udfd1
 . 
\ud835\udc78
\ud835\udc68
 
\ud835\udd75\ud835\udc8e\ud835\udc99 =
\ud835\udfd2
\ud835\udfd1
 . 
\ud835\udfd0\ud835\udfd3 . \ud835\udfcf\ud835\udfce³
\ud835\udfd1\ud835\udf45 . (\ud835\udfd1\ud835\udfce . \ud835\udfcf\ud835\udfce-3)²
= \ud835\udfcf\ud835\udfcf, \ud835\udfd6\ud835\udc74\ud835\udc77\ud835\udc82 
 
3 \u2013 Para a seção transversal \u201cI\u201d da viga, vista na figura, calcule a tensão máxima de 
cisalhamento para um esforço cortante de 44KN 
 
 
 
 
 
 
 
 
 
 
 
4 \u2013 O raio da haste de aço é 30mm se ela for submetida a um cisalhamento de 25KN. 
Determine a tensão de cisalhamento máxima 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
\ud835\udfcf, \ud835\udfd1\ud835\udfd3 . \ud835\udfcf\ud835\udfce\u2077\ud835\udc75 \ud835\udfcf, \ud835\udfd1\ud835\udfd3 . \ud835\udfcf\ud835\udfce\u2077\ud835\udc75 
\ud835\udfcf, \ud835\udfd1\ud835\udfd3 . \ud835\udfcf\ud835\udfce\u2077\ud835\udc75 
\ud835\udfcf, \ud835\udfd1\ud835\udfd3 . \ud835\udfcf\ud835\udfce\u2077\ud835\udc75 
\ud835\udfcf, \ud835\udfd6\ud835\udc8e 
\ud835\udd75\ud835\udc8e\ud835\udc99 = \ud835\udfcf, \ud835\udfd3 . 
\ud835\udc78
\ud835\udc68
 
\ud835\udd75\ud835\udc8e\ud835\udc99 = \ud835\udfcf, \ud835\udfd3 . 
\ud835\udfcf, \ud835\udfd1\ud835\udfd3 . \ud835\udfcf\ud835\udfce\u2077