Ed
ano passado
Para resolver essa questão, precisamos encontrar a relação entre as densidades volumétricas de carga das esferas A e B. A densidade volumétrica de carga (ρ) é dada pela fórmula: \[ \rho = \frac{Q}{V} \] onde \(Q\) é a carga e \(V\) é o volume da esfera. O volume de uma esfera é dado por: \[ V = \frac{4}{3} \pi r^3 \] Assim, para as esferas A e B, temos: \[ \rho_A = \frac{Q_A}{V_A} = \frac{Q_A}{\frac{4}{3} \pi R_A^3} \] \[ \rho_B = \frac{Q_B}{V_B} = \frac{Q_B}{\frac{4}{3} \pi R_B^3} \] Como os raios são proporcionais, podemos expressar \(R_A\) em termos de \(R_B\): Dado que \(10R_A = 3R_B\), temos: \[ R_A = \frac{3}{10} R_B \] Agora, substituindo na fórmula do volume: \[ V_A = \frac{4}{3} \pi \left(\frac{3}{10} R_B\right)^3 = \frac{4}{3} \pi \frac{27}{1000} R_B^3 = \frac{36 \pi R_B^3}{1000} \] Agora, substituindo as cargas: Sabemos que \(5Q_A = 2Q_B\), então podemos expressar \(Q_A\) em termos de \(Q_B\): \[ Q_A = \frac{2}{5} Q_B \] Agora, substituindo as densidades: \[ \rho_A = \frac{Q_A}{V_A} = \frac{\frac{2}{5} Q_B}{\frac{36 \pi R_B^3}{1000}} = \frac{2 \cdot 1000 Q_B}{5 \cdot 36 \pi R_B^3} = \frac{2000 Q_B}{180 \pi R_B^3} = \frac{2000}{180} \cdot \frac{Q_B}{\pi R_B^3} \] \[ \rho_B = \frac{Q_B}{V_B} = \frac{Q_B}{\frac{4}{3} \pi R_B^3} = \frac{3 Q_B}{4 \pi R_B^3} \] Agora, a relação entre as densidades é: \[ \frac{\rho_A}{\rho_B} = \frac{\frac{2000}{180} \cdot \frac{Q_B}{\pi R_B^3}}{\frac{3 Q_B}{4 \pi R_B^3}} = \frac{2000}{180} \cdot \frac{4}{3} = \frac{2000 \cdot 4}{180 \cdot 3} = \frac{8000}{540} = \frac{400}{27} \] Portanto, a relação entre as densidades volumétricas de carga \( \frac{\rho_A}{\rho_B} \) é: d) 400/27.
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Ed
há 2 anos
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