Pergunta 8 5 / 5 pts Dada f(x)=2x²+5x−3f(x)=2x²+5x−3, determine: i) f(-2) ii) f(-1) iii) f(0) iv) f(3) v) f(h+1) Assinale a alternativa que tem as ...

Vamos calcular os valores pedidos: i) f(-2): f(-2) = 2(-2)² + 5(-2) - 3 f(-2) = 2(4) - 10 - 3 f(-2) = 8 - 10 - 3 f(-2) = -2 - 3 f(-2) = -5 ii) f(-1): f(-1) = 2(-1)² + 5(-1) - 3 f(-1) = 2(1) - 5 - 3 f(-1) = 2 - 5 - 3 f(-1) = -3 - 3 f(-1) = -6 iii) f(0): f(0) = 2(0)² + 5(0) - 3 f(0) = 0 + 0 - 3 f(0) = -3 iv) f(3): f(3) = 2(3)² + 5(3) - 3 f(3) = 2(9) + 15 - 3 f(3) = 18 + 15 - 3 f(3) = 33 - 3 f(3) = 30 v) f(h+1): f(h+1) = 2(h+1)² + 5(h+1) - 3 f(h+1) = 2(h² + 2h + 1) + 5h + 5 - 3 f(h+1) = 2h² + 4h + 2 + 5h + 5 - 3 f(h+1) = 2h² + 9h + 4 Portanto, as respostas são: i) f(-2) = -5 ii) f(-1) = -6 iii) f(0) = -3 iv) f(3) = 30 v) f(h+1) = 2h² + 9h + 4