Para encontrarmos a força resultante, realizaremos os cálculos abaixo:

\(\begin{align} & {{F}_{2}}x=26\cdot \sin 30 \\ & {{F}_{2}}x=26\cdot 0,5 \\ & {{F}_{2}}x=-13i \\ & \\ & {{F}_{2}}y=26\cdot \cos 30 \\ & {{F}_{2}}y=26\cdot 0,86 \\ & {{F}_{2}}y=-22,5j \\ & \\ & {{F}_{1}}x=30\cdot \sin 30 \\ & {{F}_{1}}x=15 \\ & {{F}_{1}}x=+15i \\ & \\ & {{F}_{1}}y=30\cdot \cos 30 \\ & {{F}_{1}}y=30\cdot 0,86 \\ & {{F}_{1}}y=-25,8j \\ & \\ & R=\sqrt{{{(-13+15)}^{2}}+{{(-25,8-22,5)}^{2}}} \\ & R=\sqrt{{{2}^{2}}+{{(48,3)}^{2}}} \\ & R=48,3KN \\ \end{align}\ \)