The question asks for the correct sequence of instructions to draw a triangle. Let's analyze the given instructions: * **I - Em uma folha de papel em branco, desenhe um segmento de reta em qualquer posição: horizontal, vertical ou inclinada.** (On a blank sheet of paper, draw a line segment in any position: horizontal, vertical or inclined.) * This is a good first step to start drawing a triangle, as it provides the first side. * **II - Una, com outro segmento de reta, as extremidades livres dos segmentos de retas já existentes.** (Join, with another line segment, the free ends of the already existing line segments.) * This instruction seems to imply there are already multiple line segments with free ends, which is not the case after only instruction I. This would be the *last* step to close the triangle. * **III - Partindo da ponta escolhida, desenhe outro segmento de reta em qualquer posição que seja diferente da do segmento de reta anterior.** (Starting from the chosen point, draw another line segment in any position different from the previous line segment.) * This is a suitable second step after drawing the first line segment (from instruction I). We would choose one end of the first segment and draw a second segment. * **IV - Escolha uma das pontas do segmento de reta desenhado na folha.** (Choose one of the ends of the line segment drawn on the sheet.) * This instruction is about choosing a point. It makes sense to choose a point after drawing a segment (as in instruction I) and before drawing the next segment (as in instruction III). Let's try to form a logical sequence for drawing a triangle: 1. **Start by drawing the first side:** This corresponds to instruction I. 2. **Choose an end point of the first side to start the second side:** This corresponds to instruction IV. 3. **Draw the second side from the chosen end point:** This corresponds to instruction III. 4. **Finally, connect the free ends to form the third side and close the triangle:** This corresponds to instruction II. So, a logical sequence would be **I, IV, III, II**. Let's perform a "table test" (teste de mesa) to validate this sequence: 1. **I:** Draw a line segment AB. 2. **IV:** Choose point B (an end of the segment AB). 3. **III:** From point B, draw another line segment BC, such that BC is not collinear with AB. 4. **II:** Join the free end of AB (which is A) with the free end of BC (which is C) using a new line segment AC. This forms triangle ABC. This sequence successfully constructs a triangle. The final answer is $\boxed{I, IV, III, II}$