a)
\(\[\begin{align} & \gamma \text{ }=\text{ }{{3.17.10}^{-6}} \\ & \gamma \text{ }=\text{ }{{51.10}^{-6}} \\ \end{align}\] \)

b)

Utilizaremos:

\(\[\Delta V\text{ }=\text{ }{{V}_{0}}.\gamma .\Delta t\]\)

Onde:
ΔV: Variação de volume
V₀: Volume inicial
γ: Coeficiente de dilatação
Δt:Variação de temperatura

Substituindo:

\(\[\begin{align} & \Delta V\text{ }=\text{ }5\times {{51.10}^{-6}}\times 100 \\ & \Delta V\text{ }=\text{ }{{25500.10}^{-6}} \\ & \Delta V\text{ }=\text{ }0,0255\text{ }L \\ \end{align}\] \)

c)

O volume da panela à 120º, logo:

\(\[\begin{align} & Vt\text{ }=\text{ }5\text{ }+\text{ }0,0255 \\ & Vt\text{ }=\text{ }5,0255\text{ }L \\ \end{align}\] \)