Calcule a medida da diagonal, a área total e o volume de cada um dos paralelepípedos retângulos representados abaixo?

a)

\[\eqalign{ & d = \sqrt {{{2,5}^2} + {{2,5}^2} + {{2,5}^2}} \cr & d = \sqrt {18,75} \cr & \boxed{d \cong 4,33{{\ cm}}} \cr & \cr & A = \left( {2,5 \cdot 2,5} \right) \cdot 2 + \left( {2,5 \cdot 2,5} \right) \cdot 2 + \left( {2,5 \cdot 2,5} \right) \cdot 2 \cr & A = 12,5 + 12,5 + 12,5 \cr & \boxed{A = 37,5{{\ c}}{{{m}}^2}} \cr & \cr & V = 2,5 \cdot 2,5 \cdot 2,5 \cr & \boxed{V = 15,625{{\ c}}{{{m}}^3}} }\]

b)

\[\eqalign{ & d = \sqrt {{{3,0}^2} + {{1,5}^2} + {{2,0}^2}} \cr & d = \sqrt {15,25} \cr & \boxed{d \cong 3,91{{\ cm}}} \cr & \cr & A = \left( {3,0 \cdot 2,0} \right) \cdot 2 + \left( {1,5 \cdot 2,0} \right) \cdot 2 + \left( {3,0 \cdot 1,5} \right) \cdot 2 \cr & A = 12 + 6 + 9 \cr & \boxed{A = 27{{\ c}}{{{m}}^2}} \cr & \cr & V = 3,0 \cdot 1,5 \cdot 2,0 \cr & \boxed{V = 9{{\ c}}{{{m}}^3}} }\]

c)

\[\eqalign{ & d = \sqrt {{{2,0}^2} + {{2,0}^2} + {{2,5}^2}} \cr & d = \sqrt {14,25} \cr & \boxed{d \cong 3,77{{\ cm}}} \cr & \cr & A = \left( {2,0 \cdot 2,5} \right) \cdot 2 + \left( {2,0 \cdot 2,5} \right) \cdot 2 + \left( {2,0 \cdot 2,0} \right) \cdot 2 \cr & A = 10 + 10 + 8 \cr & \boxed{A = 28{{\ c}}{{{m}}^2}} \cr & \cr & V = 2,0 \cdot 2,0 \cdot 2,5 \cr & \boxed{V = 10{{\ c}}{{{m}}^3}} }\]

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