9780070109100, Chapter 16 2, Problem 2E

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Chapter 16.2, Problem 2E Step-by-step solution Step (a) Since 180 degrees 14159 radians, 1 radian degrees 57 degrees (or 57°18') Step 21 (b) Similarly, degree 3.14159 radians 0.01745 radians Step (a) sin2 = because R defined to be (v2 h2)1/2 This result is true regardless of the value hence we use the identity sigh. Step 21 (b) When have so = Thus, Step Step (b) 26 sin cos2 sin2 cos2 +sin2 sin2 Step 02)+sin (sin 01 02 COS sin 02)+(sin 01 Step (d) = = = Step III Step = Step 11 of 21 (a) Step 12 of 21 30) (20 (b) Step 13 of 21 Step (b) = + Step 15 of 21 (c) = + Step 16 of 21 (d) - = (1 Step of 21 (a) With R = 2 and = and = 1. The form Step (b) With R and The cartes form Step (c) Taking the complex number as we have R and [by (16.14) and = The cartesian form is h+vi taking the number as we = instead, with the result that h The cartesian form is then the same Step (a) and = find Since must satisfy = = Table 16.2 gives us Thus Step (b) With = In order that