ExerciciosComplementaresQuatro

1. Um laço retangular formado por um condutor ideal, no e spaço livre, junta os pontos \ue723 \uf23a \ue373\ue1e1 \ue372\ue1e1 \ue373 \uf23b \ue1e2 \ue003\ue724 \uf23a \ue375\ue1e1 \ue372\ue1e1 \ue373 \uf23b \ue1e2 \ue725 \uf23a \ue375\ue1e1 \ue372\ue1e1\ue376 \uf23b \ue003\ue741\ue003\ue726 \uf23a \ue373\ue1e1 \ue372\ue1e1 \ue376\uf23b . Neste condutor e xiste uma corrente d e \ue378\ue003 \ue749\ue723 , correndo na direção de \ue887 \uebed \ue003 de \ue724 para \ue725 . Além disso, existe uma corrente f ilamentar de \ue373\ue377 \ue003\ue723 ao longo de todo eixo \ue756 na direção \ue887 \uebd3 . Encontre as forças que agem sobre os segmentos \ue724\ue725 e \ue723\ue724 . Solução: Antes de qualquer coisa precisamo s calcular a densidade de f luxo ma gnético \ue724 devido ao filamento in finito de corrente sobre o eix o \ue756 . Como vimos, o ca mpo magnético em torno de um filamento infinito de corrente será dado por: \ue874 \ued4c \ue72b \ue374 \ue7e8\ue7e9 Podemos relacionar e ste camp o magnético com a densidade d e fluxo m agnético no espaço livre por: \ue86e \ued4c \ue7e4 \ueb34 \ue874 Logo: \ue72a \ued4c \ue7e4 \ueb34 \ued6c \ue72b \ue374\ue7e8\ue7e9 \ued70 \ued4c \ue003 \ue72b \ue7e4 \ueb34 \ue374 \ue7e8\ue7e9 Note que este campo varia com a distância \ue7e9 e que \ue7e9 é a distância entre o f ilamento e o ponto onde vamos perceber a existência deste campo neste cas o, precisaremos calcular o c ampo em \ue887 \uebec s obre os dois segmento s de interesse: \ue724\ue725 e \ue723\ue724 Sendo assim, para o primeiro lado d a espira \ue724\ue725 que está a 3 unidades de distância do eixo \ue756 , temos: \ue874 \uebbb\uebbc \ued4c \ue003 \ue72b \ue7e4 \ueb34 \ue374 \ue7e8\ue7e9 \ued4c \ue373\ue377 \uf23a\ue376\ue7e8 \ued48 \ue373\ue372 \ued46\ue379 \uf23b \ue374\ue7e8\uf23a\ue375\uf23b \ue887 \uebec \ue874 \uebbb\uebbc \ued4c \ue003 \ue373\ue377 \uf23a\ue376\ue7e8 \ued48 \ue373\ue372 \ued46\ue379 \uf23b \ue374\ue7e8\uf23a\ue375\uf23b \ue887 \uebec \ued4c \ue003 \ue373\ue377 \uf23a\ue374\ue003 \ued48 \ue373\ue372 \ued46\ue379 \uf23b \ue003\uf23a\ue375\uf23b \ue887 \uebec \ue874 \uebbb\uebbc \ued4c \ue003 \uf23a \ue373\ue372 \ued48 \ue373\ue372 \ued46\ue379 \uf23b \ue887 \uebec Para calcular a força que age sobre esta e spira no segmento \ue724\ue725 teremos: \ue872 \ued4c \uedb1 \ue72b\ue740 \ue878 \ued48 \ue86e \uebd5 \uebd4 Substituindo: \ue872 \ued4c \uedb1 \uf23a \ue378 \ued48 \ue373\ue372 \ueb3f\ueb37 \uf23b \ue003\ue740\ue756 \ue003 \ue887 \uebed \ued48 \uf23a \ue373\ue372 \ued48 \ue373\ue372 \ueb3f\ueb3b \uf23b \ue887 \ue755 \ueb38 \ueb35 Resolvendo este produto vetorial teremos: \ue872 \ued4c \uee2d \ue887 \ue754 \ue887 \ue755 \ue887 \ue756 \ue372 \ue372 \ue378 \ued48 \ue373\ue372 \ueb3f \ueb37 \ue372 \uf23a \ue373\ue372 \ued48 \ue373\ue372 \ueb3f\ueb3b \uf23b \ue372 \uee2d \ue872 \ued4c \ue003 \uee2c \ue372 \ue378 \ued48 \ue373\ue372 \ueb3f\ueb37 \uf23a \ue373\ue372 \ued48 \ue373\ue372 \ueb3f\ueb3b \uf23b \ue372 \uee2c \ue887 \ue754 \ued46 \uee2c \ue372 \ue378 \ued48 \ue373\ue372 \ueb3f\ueb37 \ue372 \ue372 \uee2c \ue887 \ue755 \ued45 \uf25a \ue372 \ue372 \ue372 \uf23a \ue373\ue372 \ued48 \ue373\ue372 \ueb3f\ueb3b \uf23b \uf25a \ue887 \ue756 \ue872 \ued4c \ued46\ue003 \ue378 \ued48 \ue373\ue372 \ueb3f\ueb37 \uf23a \ue373\ue372 \ued48 \ue373\ue372 \ueb3f\ueb3b \uf23b \ue887 \uebeb \ued4c \ue003 \ued46\ue378 \ued48 \ue373\ue372 \ueb3f \ueb3d \ue887 \uebeb Agora podemos fazer a inte gral: \ue872 \ued4c \uedb1 \ue003\ued46\ue378 \ued48 \ue373\ue372 \ued46\ue37b \ue887 \ue754 \ue003 \ue740\ue756 \ueb38 \ueb35 \ue872 \ued4c \ued46\ue378 \ued48 \ue373\ue372 \ued46\ue37b \ue887 \ue754 \uedb1 \ue003\ue003 \ue740\ue756 \ueb38 \ueb35 \ue872 \ued4c \ued46\ue378 \ued48 \ue373\ue372 \ued46\ue37b \ue887 \ue754 \uf23a \ue376 \ued46 \ue373 \uf23b \ued4c \ue003 \ued46 \ue373\ue37a \ue887 \ue754 \ue003 \ue74a\ue730 Precisamos agora, repetir os m esmos cálculos para o segundo segmento \ue723\ue724 desta vez, o campo continua n a mesma direção mas varia d e acordo com a distância \ue754 . Ou seja: \ue874 \uebba\uebbb \ued4c \ue003 \ue72b \ue7e4 \ueb34 \ue374 \ue7e8\ue754 \ue887 \uebec \ue874 \uebba\uebbb \ued4c \ue003 \ue373\ue377 \uf23a\ue376\ue7e8 \ued48 \ue373\ue372 \ued46\ue379 \uf23b \ue374 \ue7e8\ue754 \ue887 \uebec \ue874 \uebba\uebbb \ued4c \ue003 \ue373\ue377 \uf23a \ue374\ued48 \ue373\ue372 \ued46\ue379 \uf23b \ue754 \ue887 \uebec \ued4c \uf23a \ue375\ue372 \ued48 \ue373\ue372 \ued46\ue379 \uf23b \ue754 \ue887 \uebec Sendo assim, a força será dada por: \ue872 \ued4c \uedb1 \ue72b\ue740 \ue878 \ued48 \ue86e \uebd5 \uebd4 Substituindo: \ue872 \uebba\uebbb \ued4c \uedb1 \uf23a \ue378 \ued48 \ue373\ue372 \ueb3f\ueb37 \uf23b \ue003\ue740\ue754 \ue003 \ue887 \uebeb \ued48 \uf23a \ue375\ue372 \ued48 \ue373\ue372 \ueb3f\ueb3b \uf23b \ue754 \ue887 \ue755 \ueb37 \ueb35 \ue872 \uebba\uebbb \ued4c \uedb1 \uf23a \ue378 \ued48 \ue373\ue372 \ueb3f\ueb37 \uf23b \ue003\ue740\ue754 \ue003 \ue887 \uebeb \ued48 \uf23a \ue375\ue372 \ued48 \ue373\ue372 \ueb3f\ueb3b \uf23b \ue754 \ue887 \ue755 \ueb37 \ueb35 \ue872 \ued4c \uedb1 \uf23a \ue373\ue37a \ued48 \ue373\ue372 \ueb3f\ueb3d \uf23b \ue754 \ue003 \ue887 \uebed \ue003\ue740\ue754 \ueb37 \ueb35 \ue872 \uebba\uebbb \ued4c \uf23a \ue373\ue37a \ued48 \ue373\ue372 \ueb3f\ueb3d \uf23b \uf23a \ue08e\ue090 \ue375 \ued46 \ue08e\ue090 \ue373\uf23b \ued4c \ue373\ue37b \ue1e1\ue379\ue003 \ue74a\ue730 2. Um motor utiliza u ma bobina retangular de \ue374\ue372 \ue003 \ue749\ue749 por \ue374\ue372 \ue003 \ue749\ue749 pivota do no ce ntro do lado menor. Se el e for m ontado e m um c ampo magnético radial constante de densidade de fluxo dada por \ue372\ue1e1\ue376\ue003\ue739\ue73e\ue200\ue749 \ueb36 que está sempre atuando em um ângulo de \ue375\ue372\ue3b9 em relação ao plano da bobina e se a bobin a tiver 500 v oltas e for atravessada por uma corrente de 5 mA, e ncontre o t orque exercido sobre a bobina. Solução: Sabemos que o torque exercido sobre uma espira será dado por: \ue736 \ued4c \ue724\ue72b\ue735\ue003\ue74f\ue741\ue74a\ue7d9 Enquanto o torque sobre \ue730 espiras será dado por: \ue736 \ued4c \ue730\ue724\ue72b\ue735\ue003\ue74f\ue741\ue74a\ue7d9 \ue736 \ued4c \uf23a \ue377\ue372\ue372 \uf23b\uf23a \ue372\ue1e1\ue376 \uf23b\uf23a \ue377\ued48 \ue373\ue372 \ueb3f\ueb37 \uf23b\uf23a \ue374\ue372 \ued48 \ue373\ue372 \ueb3f \ueb37 \uf23b\uf23a \ue374\ue372 \ued48 \ue373\ue372 \ueb3f\ueb37 \uf23b \ue74f\ue741\ue74a \ue375\ue372 \ue3b9 \ue736 \ued4c \ue374\ue372\ue372 \ue003\ue7e4\ue730\ue749 3. Em um material ferromagn ético isotrópico linear e homogêneo de \ue7e4 \uebe5 \ued4c \ue374\ue1e1\ue377 , sujeito a uma densidade de fluxo magnético da da por \ue86e \ued4c \ue376\ue755\ue887 \uebed \ue003\ue749\ue739\ue73e \ue200\ue749 \ueb36 , de termine o val or da magnetização \ue879 . Solução: Sabemos que a magnetizaçã o em meios isotrópi cos pode ser encon trada por: \ue879 \ued4c \ue231 \uebe0 \ue874\ue003 Mas, não temos nenhuma destas grandezas no enunciado então devemos começar observando que exi ste uma relação en tre a permeabi lidade r elativa e a su sceptibilidade por: \ue7e4 \uebe5 \ued4c \ue231 \uebe0 \ued45 \ue373 Logo: \ue7e4 \uebe5 \ued46 \ue373 \ued4c \ue231 \uebe0 \ue231 \uebe0 \ued4c \ue374\ue1e1\ue377 \ued46 \ue373 \ued4c \ue373\ue1e4\ue377 Também podemos relacionar o campo m agnético \ue874 com a densidade de f luxo magnético \ue86e por: \ue86e \ued4c \ue7e4\ue874 Logo: \ue86e \ued4c \ue7e4\ue874 \ue5f5 \ue874 \ued4c \ue86e \ue7e4 \ued4c \ue86e \ue7e4 \ueb34 \ue7e4 \uebe5 \ue874 \ued4c \ue86e \ue7e4 \ueb34 \ue7e4 \uebe5 \ued4c \ue376\ue755 \ued48 \ue373\ue372 \ued46\ue375 \ue887 \ue756 \uf23a\ue376\ue7e8 \ued48 \ue373\ue372 \ueb3f\ueb3b \uf23b\uf23a \ue374\ue1e1\ue377\uf23b \ued4c \ue373\ue1e1 \ue374\ue379\ue375 \ue003\ue755 \ue887 \ue756 \ue003 \ue747\ue723 \ue200\ue749 \ue003\ue003 Agora podemos chegar a magnetização: \ue879 \ued4c \ue231 \uebe0 \ue874 \ued4c \ue373\ue1e1\ue377 \uf23a \ue373\ue1e1 \ue374\ue379\ue375 \ue003 \uf23b \ued4c \ue373\ue1e1 \ue37b\ue373\ue372 \ue887 \uebed \ue003 \ue747\ue723 \ue200\ue749 \ue003 4. Em um certo material isotrópico line ar e homogêneo de \ue7e4 \uebe5 \ued4c \ue373\ue1e1\ue377 , sujei to a uma densidade de fluxo magnético dada por \ue874 \ued4c \ue373\ue372 \ue887 \uebed\ue003 \ued45 \ue374\ue372 \ue887 \uebec \ued46 \ue376\ue372 \ue887 \uebed \ue003\ue723\ue200\ue749 , determine a magnetização \ue879 . Solução: Sabemos que a magnetiz ação em meios isotrópi cos pode ser encontrada por : \ue879 \ued4c \ue231 \uebe0 \ue874\ue003 Mas, não temos nenhuma destas grandezas no enunciado então devemos começar observando que exi ste uma relação en tre a permeabili dade rel ativa e a susceptibilida de por: \ue7e4 \uebe5 \ued4c \ue231 \uebe0 \ued45 \ue373 Logo: \ue7e4 \uebe5 \ued46 \ue373 \ued4c \ue231 \uebe0 \ue231 \uebe0 \ued4c \ue373\ue1e1\ue377 \ued46 \ue373 \ued4c \ue372\ue1e4\ue377 Sabemos também que a magnetização pode ser determinada por: \ue879 \ued4c \ue231 \uebe0 \ue874 Logo: \ue879 \ued4c \ue231 \uebe0 \ue874 \ued4c \ue372\ue1e1\ue377\ued6b \ue373\ue372 \ue887 \ue756\ue003 \ued45 \ue374\ue372 \ue887 \ue755 \ued46 \ue376\ue372 \ue887 \ue756 \ue003\ue003\ued6f \ued4c \ue377\ue887 \ue756\ue003 \ued45 \ue373\ue372 \ue887 \ue755 \ued46 \ue374\ue372 \ue887 \ue756 \ue003\ue723\ue200\ue749 5. Em u m siste ma de coordenadas cilí ndricas, u m f io condutor ide al d e \ue374\ue749 de comprimento carregando uma corrente de \ue377\ue003\ue723 na direção positiva do eixo \ue756 \ue003 está localizado em \ue7e9 \ued4c \ue376\ue003\ue73f\ue749 \ue1e2 \ue003 \ued46\ue373\ue003\ue749 \ued4f \ue756 \ued4f \ue373\ue003\ue749 . Este condutor está sujeito a um campo magnético cuja densidade d e fluxo é dada por: \ue86e \ued4c \ue372\ue1e1\ue374 \ue085\ue091\ue095 \ue7f6 \ue003 \ue887 \uec18 . Determine a coordenada \ue7f6 onde a força será a maior possível. Solução: \ue872 \ued4c \ue72b\ue748 \ued48 \ue86e \ue872 \ued4c \uf23a \ue377\ue887 \uebed \uf23b \ue374 \ued48 \ue374\ue1e1\ue372 \ue085\ue091\ue095 \ue7f6 \ue887 \uec18 \ue872 \ued4c \ue373\ue372 \ue887 \uebed \ued48 \ue374\ue1e1 \ue372 \ue085\ue091\ue095 \ue7f6 \ue887 \uec18 Resolvendo este produto vetorial teremos: \ue872 \ued4c \uee2d \ue887 \ue7e9 \ue887 \ue7f6 \ue887 \ue756 \ue372 \ue372 \ue373\ue372 \ue003 \ue372\ue1e1\ue374 \ue085\ue091\ue095 \ue7f6 \ue372 \ue372 \uee2d \ue872 \ued4c \ue003 \uf25a \ue372 \ue373\ue372 \ue372 \ue372 \uf25a \ue887 \ue7e9 \ued46 \uee2c \ue372 \ue373\ue372 \ue372\ue1e1\ue374 \ue085\ue091\ue095 \ue7f6 \ue372 \uee2c \ue887 \ue7f6 \ued45 \uee2c \ue372 \ue372 \ue372\ue1e1\ue374 \ue085\ue091\ue095 \ue7f6 \ue372 \uee2c \ue887 \ue756 \ue872 \ued4c \ue374 \ue085\ue091\ue095 \ue7f6 \ue887 \uec25 Ou seja, nossa força depende do cosseno de \ue7f6 . Como o cosseno varia entre 0 e 1 a força será a maior possív el em \ue7f6 \ued4c \ue372 6. Dado um material no qual encontramos \ue231 \uebe0 \ued4c \ue376 com um fluxo magnético interno \ue86e \ued4c \ue373\ue1e1\ue374\ue755\ue003 \ue887 \uebed \ue003\ue736 en contre a magnetização \ue879 no interior deste material. Solução: Sabemos que a densidade de corrente pode ser relacionada com o campo magnético por: \ue876 \ued4c \ue5cf \ued48 \ue874 Então, antes d e achar a densidade de corrent e precisamos ac har o ca mpo \ue874 no interior deste material para tal podemos relacionar o campo \ue874 co m susceptibilidade magnética \ue231 \uebe0 por: \ue86e \ued4c \ue003 \ue7e4 \uebe2 \uf23a \ue874 \ued45 \ue231 \uebe0 \ue874 \uf23b Ou, acertando o algebrismo: \ue86e \ued4c \ue003 \ue7e4 \ueb34 \uf23a \ue373 \ued45 \ue231 \uebe0 \uf23b \ue874 Logo: \ue86e \ue7e4 \ueb34 \uf23a \ue373 \ued45 \ue231 \uebe0 \uf23b \ued4c \ue003\ue874 Neste caso: \ue874 \ued4c \ue86e \ue7e4 \uebe2 \uf23a \ue373 \ued45 \ue231 \uebe0 \uf23b \ued4c \ue373\ue1e1\ue374\ue755\ue887 \uebed \ue7e4 \ueb34 \uf23a\ue373 \ued45 \ue375\ue1e1\ue373\uf23b \ued4c \ue003\ue003 \ue373\ue1e1\ue374\ue755\ue887 \uebed \uf23a\ue003\ue376\ue7e8 \ued48 \ue373\ue372 \ueb3f\ueb3b \uf23b\uf23a\ue373 \ued45 \ue376\uf23b \ue874 \ued4c \ue373\ue37b\ue373 \ue003\ue755\ue887 \uebed \ue003 \ue747\ue723 \ue200\ue749 Sabemos também que podemos relacionar a magnetização com o campo \ue874\ue003 por: \ue879 \ued4c \ue231 \uebe0 \ue874 \ue879 \ued4c \ue376 \uf23a \ue373\ue37b\ue373 \ue003\ue755\ue887 \uebed \uf23b \ued4c \ue379\ue378\ue376 \ue003 \ue747\ue723 \ue200\ue749 7. Considere uma reg ião do espaço para a q ual temos \ue231 \uebe0 \ued4c \ue375 e um campo magnético dado por \ue72a \ued4c \ue377\ue754 \ue887 \uebeb \ued45 \ue374\ue755 \ue887 \uebec \ued46 \ue375\ue756\ue887 \uebed . Det ermine a energ ia total acumulada em \ued46\ue373 \ued4f \ue754 \ued4f \ue374 ; \ue372 \ued4f \ue755 \ued4f \ue374 , \ue372 \ued4f \ue756 \ued4f \ue373\ue003 . Solução: Sabemos q ue podemos relacionar susceptibilidade magnética co m a permeabilidade magnética relativa por: \ue7e4 \uebe5 \ued4c \ue231 \uebe0 \ued45 \ue373 \ue7e4 \uebe5 \ued4c \ue375 \ued45 \ue373 \ued4c \ue376 Também podemos relacionar o campo magnético com densidade de f luxo magnético por: \ue86e \ued4c \ue003 \ue7e4 \uebe2 \uf23a \ue373 \ued45 \ue231 \uebe0 \uf23b \ue874 \ue86e \ued4c \ue003 \ue7e4 \uebe2 \uf23a \ue376 \uf23b \ue874 Por fim, a energia armazenada em um camp o magnético é dada por: \ue739 \uebe0 \ued4c \ue373 \ue374 \ue86e \ue684 \ue874 Antes de progredirmos precisamos resolver \ue86e \ue684 \ue874 \ue7e4 \uebe2 \uf23a \ue376 \uf23b \ue874 \ue684 \ue874 \ue874 \ue684 \ue874 \ued4c \ued6b\ue377\ue754 \ue887 \uebeb \ued45 \ue374\ue755\ue887 \uebec \ued46 \ue375\ue756 \ue887 \uebed \ued6f \ue684 \ued6b\ue377\ue754 \ue887 \uebeb \ued45 \ue374\ue755\ue887 \uebec \ued46 \ue375\ue756 \ue887 \uebed \ued6f \ue874 \ue684 \ue874 \ued4c \uf23a \ue377\ue754 \ued48 \ue377\ue754 \uf23b \ued45 \uf23a \ue374\ue755 \ued48 \ue374\ue755 \uf23b \ued45 \uf23a\ued46\ue375\ue756 \ued48 \ued46\ue375\ue756 \uf23b \ue874 \ue684 \ue874 \ued4c \uf23a \ue374\ue377 \ue754 \ueb36 \uf23b \ued45 \uf23a \ue376\ue755 \ueb36 \uf23b \ued45 \uf23a\ue37b\ue756\uf23b Então a energia acumulada será dada por \ue739 \uebe0 \ued4c \ue373 \ue374 \ue7e4 \uebe2 \uf23a \ue376 \uf23b \ue874 \ue684 \ue874 \ue739 \uebe0 \ued4c \ue376\ue7e4 \ueb34 \ue374 \ue874 \ue684 \ue874 \ue739 \uebe0 \ued4c \ue374\ue7e4 \ueb34 \ue874 \ue684 \ue874 \ue739 \uebe0 \ued4c \ue374\ue7e4 \ueb34 \uf23a \ue374\ue377 \ue754 \ueb36 \ued45 \ue376\ue755 \ueb36 \ued45 \ue37b\ue756 \uf23b Para encontrar a ene rgia total precisa mos integrar e sta equação nos limites determinados pe lo enunciado em relação a um elemento de volume no espaço cartesiano dado por \ue740\ue754\ue740\ue755\ue740\ue756 \ue739 \uebe0 \ued4c \ue003\ue374\ue7e4 \ueb34 \uedb1 \uedb1 \uedb1 \ue374\ue377 \ue754 \ueb36 \ued45 \ue376\ue755 \ueb36 \ued45 \ue37b\ue756 \ue003\ue740\ue754\ue740\ue755\ue740\ue756 \ueb36 \ueb3f\ueb35 \ueb36 \ueb34 \ueb35 \ueb34 \ued4c \ue374\ue7e4 \ueb34 \uf23a \ue374\ue372\ue37b \uf23b \ue739 \uebe0 \ued4c \ue374\ue7e4 \ueb34 \uf23a \ue374\ue377\ue378 \uf23b \ued4c \ue374 \uf23a \ue376\ue7e8 \ued48 \ue373\ue372 \ueb3f\ueb3b \uf23b\uf23a \ue374\ue372\ue37b \uf23b \ued4c \ue377\ue374\ue377 \ue1e1\ue375\ue003 \ue7e4\ue72c 8. O entendimento do campo magnético gerado por filamentos d e corrente e fundamental para o entendimento de motores e solenoides. Um filamen to infinito de corrente, no espa ço livre, provoca no ponto \ue732 \uf23a\ue374\ue1e1 \ue374\ue1e1 \ue379\uf23b , um campo magnético \ue86e \ued4c \ue373\ue372\ue372 \ue003 \ue74a\ue739 \ue200\ue749 \ueb36 calcule a corrent e nec essária, na direção positiva de \ue887 \uebed capaz de gerar este campo. Solução: Partimos do formulário para encontrar a fó rmula do campo magnético \ue86e em torno de uma distribuição linear e infinita de corrente. Sabemos de antemão que o campo mag nético será d ado p ela regra da m ão direita com o polegar a pontado no se ntido d a corrente, n a direçã o positiv a de \ue887 \uebed então este campo se propaga na forma de círculos por todo o espaço. Como o f ilamento está no eix o \ue756 , este e este propaga a corrente o c ampo existirá em um plano \ue754\ue755 em um determinado \ue756 , neste caso segundo o enunciado, \ue756 \ued4c \ue379 O campo \ue86e irá variar apenas no sen tido de \ue7f6 lembre-se que em coordenadas cilíndricas a coordenada \ue7f6 é a coordenada relacionada ao ângulo. Logo: \ue86e \ued4c \ue7e4 \ueb34 \ue72b \ue374 \ue7e8\ue7e9 \ue003 \ue887 \uec25 Temos todas a variáveis e xceto a corrente desejada e este \ue7e9 . Trata-se da distância entre o ponto desejado e o filamento. Sobre um plano \ue754\ue755 , o \ue7e9 , raio do círculo que passa pelo ponto desejado pode se r encontrado usando o teorema de Pitá goras onde cada coordenada é um lado e o raio, \ue7e9 , a hipotenusa. Sendo assim, a distância entre o filamento e o ponto desejado será: \ue7e9 \ued4c \ueda5 \ue754 \ueb36 \ued45 \ue755 \ueb36 \ued4c \ue003 \ueda5 \ue374 \ueb36 \ued45 \ue374 \ueb36 \ued4c \ue3be \ue37a\ue003 Ou seja, aplicando os valores dados no enunciado na fórmula e resolvendo teremos: \ue373\ue372\ue372 \ue754 \ue373\ue372 \ueb3f\ueb3d \ue887 \uec25 \ued4c \uf23a\ue376\ue7e8 \ued48 \ue373\ue372 \ueb3f \ueb3b \uf23b\uf23a\ue72b\uf23b \ue374\ue7e8 \uf23a \ue3be \ue37a\uf23b \ue003 \ue887 \uec25 \ue373\ue372\ue372 \ue754 \ue373\ue372 \ueb3f\ueb3d \uf240\ue374\ue7e8 \ued6b \ue3be \ue37a\ued6f\uf241 \ue376\ue7e8 \ued48 \ue373\ue372 \ueb3f\ueb3b \ued4c \ue875 \ue373\ue372\ue372 \ue754 \ue373\ue372 \ueb3f\ueb3d \uf240\ue374\ue7e8 \ued6b\ue374 \ue3be \ue374\ued6f\uf241 \ue376\ue7e8 \ued48 \ue373\ue372 \ueb3f\ueb3b \ued4c \ue875 \ue373\ue754 \ue373\ue372 \ueb3f\ueb3b \ued6b \ue3be \ue374\ued6f \ue373\ue372 \ueb3f\ueb3b \ued4c \ue875 \ue875 \ued4c \ue3be \ue374\ue003\ue723

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Eletromagnetismo

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Quais são os parâmetros observados no ensaio que afetam a força magnética entre dois fios paralelos? Os parâmetros observados no ensaio que afetam...

Mantendo os demais parâmetros constantes e variando apenas a distância (d) entre os fios paralelos, construa um gráfico entre a força magnética e a...

Mantendo os demais parâmetros constantes e variando apenas o comprimento (l) dos fios, construa um gráfico entre a força magnética e o comprimento ...

Ao inverter a polaridade de um dos circuitos analisados, o que ocorre com a força magnética entre os dois fios paralelos? Justifique o comportament...

Como a intensidade da corrente que percorre o condutor 2 (circuito da direita) afeta a força magnética sobre o condutor 1 (circuito da esquerda)? ...

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