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Prof. Calçada 1 Acidez e basicidade Questões de classe 1) Observe o exemplo a seguir: Usando setas curvas complete as reações a seguir de forma semelhante e classifique os reagentes como eletrófilos ou nucleófilos. 2) Para cada reação abaixo indique se o equilíbrio está deslocado para a direita ou esquerda. 3) Mostre a reação f acima usando setas curvas para mostrar o movimento dos elétrons. 4) Coloque os álcoois a seguir em ordem crescente de acidez. 5) Coloque os ácidos a seguir em ordem decrescente de acidez. 6) Responda a) Por que o m-nitrofenol é menos ácido que seus isômeros de posição mas é mais ácido que o fenol? b) Coloque em ordem crescente de acidez: (A) fenol, (B)3,4-dimetilfenol, (C)ácido m-hidroxibenzoico, (D) 4-fluorometilfenol ORIENTAÇÃO DE ESTUDO 1. Termine o capítulo 9 do livro 3. 2. Leia as páginas 12 a 15 do livro do Mecanismos de Reações e resolva os exercícios 1 e 2. 3. Resolva os extras a seguir. EXTRAS PARA CASA 1) Em qual dos compostos abaixo o par isolado do nitrogênio não está deslocalizado sobre o anel aromático? 2) O par de moléculas a seguir representa: a) enantiômeros b) diastereoisômeros 672 - 3 A c i d s a n d B a s e s C H A P T E R 2 The reaction between boron trifl uoride and ethoxyethane (diethyl ether) to give the Lewis acid-base reaction product is shown on the previous page, and also in the form of electro- static potential maps (above). As electron density is transferred, the oxygen becomes more positive (blue) and the boron more negative (red). As we have seen in Section 2-2, the dissociation of a Brønsted acid HA is just the reverse of the combination of the Lewis acid H+ and the Lewis base A2: Dissociation of a Brønsted Acid H! "ðAAHO ! As a reminder (see Section 2-3), the use of the symbol for the free proton, H+, in the above equation is for convenience, and we will encounter it in future reaction schemes and mech- anisms. Nonetheless, bear in mind that H+ in solution is always associated with a Lewis basic species such as a molecule of solvent. Electrophiles and nucleophiles are similar to acids and bases Many processes in organic chemistry exhibit characteristics of acid-base reactions. For example, heating an aqueous mixture of sodium hydroxide and chloromethane, CH3Cl, produces methanol and sodium chloride. As noted in Section 2-2, this process involves the same kind of movement of two pairs of electrons as does the acid-base reaction between sodium hydroxide and HCl: Reaction of Sodium Hydroxide and Chloromethane Na! Na! Note: The Na! ion is a nonparticipating “bystander”Methanol HO "" CH3 ClO HO CH3O! ! ! !šð# šð# Clšðð#š# H2O, ∆ Flow of Electrons Using Curved-Arrow Representation (Na+ Omitted) ðð ð Clðš#ClðHO#š HO#šOOð "" !! CH3 CH3 Compare to a Brønsted acid-base reaction: šð#Clðš#ClðHO#š HO#šOOð "" !! H H Because the reaction between NaOH and CH3Cl results in substitution of a nucleophile (hydroxide) for another atom or group in the starting organic molecule, it is called a nucleo- philic substitution. The terms nucleophile and Lewis base are synonymous. All nucleophiles are Lewis bases. Nucleophiles, often denoted by the abbreviation Nu, may be negatively charged, such as ! 68 S t r u c t u r e a n d R e a c t i v i t yC H A P T E R 2 hydroxide, or neutral, such as water, but every nucleophile contains at least one unshared pair of electrons. All Lewis acids are electrophiles, as shown earlier in the examples of Lewis acid- base reactions. Species such as HCl and CH3Cl have closed outer shells and therefore are not Lewis acids. However, they may still behave as electrophiles, because they possess polar bonds that impart electrophilic character to the H in HCl and the C in CH3Cl, respectively. Nucleophilic substitution is a general reaction of haloalkanes, organic compounds pos- sessing carbon–halogen bonds. The two following equations are additional examples: CH3 2CH3 !! CCH H CH3 2CH3CCH Br H "I " ! ðð Br! ðð!š šðð I!ðð CH3 2NH !! CH H H CH3 32CH " ! ðNHI!šð I!šðð Although the haloalkanes in these examples contain different halogens and varied num- bers and arrangements of carbon and hydrogen atoms, they behave very similarly toward nucleophiles. We conclude that it is the presence of the carbon–halogen bond that governs the chemical behavior of haloalkanes: The C–X bond is the structural feature that directs the chemical reactivity—structure determines function. The C–X bond constitutes the func- tional group, or the center of chemical reactivity, of the haloalkanes. In the next section, we shall introduce the major classes of organic compounds, identify their functional groups, and briefl y preview their reactivity. In Summary In Brønsted-Lowry terms, acids are proton donors and bases are proton accep- tors. Acid-base interactions are governed by equilibria, which are quantitatively described Solved Exercise 2-14 Working with the Concepts: Using Curved Arrows Using earlier examples in this section as models, add curved arrows to the fi rst of the two reactions immediately above. Strategy In the organic substrate, identify the likely reactive bond and its polarization. Classify the other reacting species, and look for reactions in the text between similar types of substances. Solution • The C–Br bond is the site of reactivity in the substrate and is polarized (!1)C–Br(!2). Iodide is a Lewis base and therefore a potential nucleophile (electron-pair donor). Thus the situation resembles that found in the reaction between hydroxide and CH3Cl just above and Example 3 at the beginning of the section. • Follow the earlier patterns in order to add the appropriate arrows. !! CH2 CH3 3CH "I!šðð šð!Brðš! ð "CO BrO !! !" H CO HOI CH2 CH3 3CH Exercise 2-15 Try It Yourself Add curved arrows to the second of the reactions immediately above Exercise 2-14 in the text. 92 S t r u c t u r e a n d R e a c t i v i t yC H A P T E R 2 Average strength Bond (kcal mol!1 ) COC 83 CPC 146 COH 99 BrOBr 46 HOBr 87 COBr 68 (a) Iodide ion, I2 (b) Hydrogen ion, H1 (c) Carbon in methyl cation, 1CH3 (d) Sulfur in hydrogen sulfi de, H2S (e) Aluminum in aluminum trichloride, AlCl3 (f) Magnesium in magnesium oxide, MgO 33. Circle and identify by name each functional group in the com- pounds pictured. (a) OH (b) (c) I (d) O (e) H O (f) (g) O O (h) N O H (i) O OH O HO (j) O O O 34. On the basis of electrostatics (Coulomb attraction), predict which atom in each of the follow ing organic molecules might react with the indicated reagent. Write “no reaction’’ if none seems likely. (See Table 2-3 for the structures of the organic molecules.) (a) Bromoethane, with the oxygen of HO2; (b) propanal, with the nitrogen of NH3; (c) methoxyethane, with H1; (d) 3-hexanone, with the carbon of CH3 2; (e) eth- anenitrile (acetonitrile), with the carbon of CH3 1; (f) butane, with HO2. 35. Use curved arrows to show the electron movement in each reaction in Problem 34. 36. Name the following molecules according to the IUPAC system of nomenclature. (a) CH3 CH3 H3C CHCH3CH2 CH (b) CH2 CH3 CH2 C CH3 CH2CH2 CH2 CHCH3 CH CH3 CH2CH3 CH3CH CH3 26. You have just baked a pizza and turned off your oven. When you open the door to cool the hot oven, what happens to the total en- thalpy of the system “oven 1 room”? The total entropy of the system? How about the free energy? Is the process thermody- namically favorable? What can you say about the temperatures of the oven and of the kitchen after equilibrium has been reached? 27. The hydrocarbon propene (CH3OCHPCH2) can react in two different ways with bromine (Chapters 12 and 14). (i) CH2P Br !CHCH2OCHCH3 OCH2 HBr Br A CH2O P ! CHCH3OCHCH3 OCH2 A Br2 A Br P ! Br2 (ii) (a) Using the bond strengths (kcal mol21) given in the table, cal-culate DH8 for each of these reactions. (b) DS8 ! 0 cal K21 mol21 for one of these reactions and 235 cal K21 mol21 for the other. Which reaction has which DS8? Briefl y explain your answer. (c) Calculate DG8 for each reaction at 258C and at 6008C. Are both of these reactions thermodynamically favorable at 258C? At 6008C? Problems 28. (i) Determine whether each species in the following equations is acting as a Brønsted acid or base, and label it. (ii) Indicate whether the equilibrium lies to the left or to the right. (iii) Estimate K for each equation if possible. (Hint: Use the data in Table 2-2.) (a) H2O 1 HCN 34 H3O 1 1 CN2 (b) CH3O 2 1 NH3 34 CH3OH 1 NH2 2 (c) HF 1 CH3COO 2 34 F2 1 CH3COOH (d) CH3 2 1 NH3 34 CH4 1 NH2 2 (e) H3O 1 1 Cl2 34 H2O 1 HCl (f) CH3COOH 1 CH3S 2 34 CH3COO 2 1 CH3SH 29. Use curved arrows to show electron movement in each acid-base reaction in Problem 28. 30. Identify each of the following species as either a Lewis acid or a Lewis base, and write an equation illustrating a Lewis acid-base reaction for each one. Use curved arrows to depict electron-pair movement. Be sure that the product of each reaction is depicted by a complete, correct Lewis structure. (a) CN2 (b) CH3OH (c) (CH3)2CH 1 (d) MgBr2 (e) CH3BH2 (f) CH3S 2 31. For each example in Table 2-3, identify all polarized covalent bonds and label the appropriate atoms with partial positive or negative charges. (Do not consider carbon–hydrogen bonds.) 32. Characterize each of the following atoms as being either nucleo- philic or electrophilic. 286 H y d r o x y F u n c t i o n a l G r o u p : A l c o h o l s C H A P T E R 8 polarized as a result of the high electronegativity of X (Sections 1-3 and 6-1). Electron withdrawal by the halogen also causes atoms farther away to be slightly positively charged. This phenomenon of transmission of charge, both negative and positive, through the s bonds in a chain of atoms is called an inductive effect. Here it stabilizes the negative charge on the alkoxide oxygen by electrostatic attraction. The inductive effect in alcohols increases with the number of electronegative groups but decreases with distance from the oxygen. Figure 8-4 The smaller methoxide ion is better solvated than is the larger tertiary butoxide ion. (S 5 solvent molecules). −− S S S S S S S S S SO O Increasing inductive effect Cl Inductive Effect of the Chlorine in 2-Chloroethoxide OCH2O CH2 !O O ðš# Exercise 8-5 Rank the following alcohols in order of increasing acidity. OH Cl Cl Cl OH OH OH Exercise 8-6 Which side of the following equilibrium reaction is favored (assume equimolar concentrations of starting materials)? (CH3)3CO 2 1 CH3OH ∆ (CH3)3COH 1 CH3O2 The lone electron pairs on oxygen make alcohols weakly basic Alcohols may also be basic, although weakly so. Very strong acids are required to protonate the OH group, as indicated by the low pKa values (strong acidity) of their conjugate acids, the alkyloxonium ions (Table 8-3). Molecules that may be both acids and bases are called amphoteric (ampho, Greek, both). The amphoteric nature of the hydroxy functional group characterizes the chemical reac- tivity of alcohols. In strong acids, they exist as alkyloxonium ions, in neutral media as alcohols, and in strong bases as alkoxides. RO !ROH Alcohols Are Amphoteric Strong acid Mild base Alkyloxonium ion Alcohol Alkoxide ion Strong base Mild acid š" š"ðR H H O " O i f ð Table 8-3 pKa Values of Four Protonated Alcohols Compound pKa CH3O ! H2 22.2 CH3CH2O ! H2 22.4 (CH3)2CHO ! H2 23.2 (CH3)3CO ! H2 23.8 842 C a r b o x y l i c A c i d sC H A P T E R 1 9 Why do carboxylic acids dissociate to a greater extent than do alcohols? The difference is that the hydroxy substituent of a carboxylic acid is attached to a carbonyl group, whose positively polarized and sp2-hybridized carbonyl carbon exerts a powerful electron-withdrawing inductive effect. In addition, the carboxylate ion is signifi cantly stabilized by resonance, much as is the enolate ion formed by deprotonation of the !-carbon in aldehydes and ketones (Section 18-1). Resonance in Carboxylate and Enolate Ions (B ! base)Carboxylate ion ! BH B R C O Oð ð ð" "E H " ! pKa 4–5 B R C O H Oð ð #½ ! B"ðE EH A R C O Oð ð ð" " "E H " " A R C O Oð ð ½ ½ " E N " pKa 19–21 Enolate ion ! BH B C CHR Oð ð " E H " CHR CHR" " ! B R# R# R# R# C C H H R Oð ð ! B"ðE E A A H A C Oð ð " E H " A C Oð ð " E N " In contrast with enolates, two of the three resonance forms in carboxylate ions are equivalent (Section 1-5). As a result, carboxylates are symmetric, with equal carbon–oxygen bond lengths (1.26 Å), in between the lengths typical of the carbon–oxygen double (1.20 Å) and single (1.34 Å) bonds in the corresponding acids (see Figure 19-1). The electrostatic potential map of acetate ion in the margin shows the equal distribution of negative charge (red) over the two oxygens. Electron-withdrawing substituents increase the acidity of carboxylic acids We saw previously (Section 8-3) that the inductive effect of electron-withdrawing groups close to the hydroxy function increases the acidity of alcohols. A similar phenomenon is observed in carboxylic acids. Table 19-3 shows the pKa values of selected acids. Note that two or three electron-withdrawing groups on the !-carbon can result in carboxylic acids whose strength approaches that of some inorganic (mineral) acids. B ! H2O RCO B š" O "ð ðððð ! HOH2š ! Carboxylic Acids Dissociate Readily Carboxylate ionKa 10"4 pKa 4–5 –10"5 š"RCOH š" O Acetate ion Exercise 19-5 In the following sets of acids, rank the compounds in order of decreasing acidity. (a) CH3CH2COOH A CH3CHCOOH Br CH3CBr2COOH (b) CH3CHCH2COOH A Br CH3CHCH2COOH A F (c) COOH F COOH COOH F Turma ITA – Frente 1 Prof. Calçada 2018 2 c) isômeros constitucionais d) duas moléculas do mesmo composto 3) Sobre aminoácido glicina (ácido aminoetanoico) são feitas as seguintes afirmações: (1) Existe em forma cristalina (2) É opticamente ativo (3) É solúvel em água (4) Forma zwitterion São corretas: a) 1, 2 e 3 b) 1, 2 e 4 c) 1, 3 e 4 d) 2, 3 e 4 4) A ordem correta de basicidade dos compostos a seguir é: 5) A ordem decrescente de acidez dos compostos a seguir é: 6) Qual dos compostos a seguir é o mais ácido? Dica: retire o próton e veja qual espécie terá mais formas ressonantes. 7) Qual a ordem correta de força das seguintes aminas: 8) Qual dos compostos a seguir é o ácido mais fraco? 9) Em pH próximo de 6,0 um amino ácido está na forma de zwitterion. A diminuição e o aumento de pH fazem o aminoácido: R = B a) ficar ácido e básico, respectivamente. b) ficar básico e ácido, respectivamente. c) perder a carga e ficar uma molécula neutra. d) perder sua atividade óptica (exceto a glicina). 10 ) DESAFIO: RESPOSTAS 1) C 2) C 3) C 4) B O ácido conjugado da protonação de I é estabilizado por ressonância, logo I é mais básico. Aminas 2a são mais básicas que 1a e a carbonila deslocaliza o par de elétrons do N diminuindo a basicidade. 5) B Fenóis são ácidos por natureza. A presença de grupos que removem elétrons (-NO2, - X, -NR3+, -CHO, -COX, -COOR, -CN) no anel, estabiliza o íon fenóxido e aumenta a acidez. Por outro lado, a presença de grupos que cedem elétrons ( grupos alquila e –OR) desestabiliza o íon e diminui a acidez do fenol. Além disso, o isômero meta é estabilizado mais pelo efeito indutivo que pela ressonância, assim os isômeros orto e para são mais ácidos. De forma semelhante os isômeros meta (do metoxi) são menos desestabilizados que o para. 6) B – fica estabilizado por ressonância. 7) C Aminas aromática são menos básicas que as aminas cíclicas. Além disso o grupo nitro retira elétrons e diminui a basicidade. 8) A 9) B 10 ) Ver no HD 319C H A P T E R 8P r o b l em s 24. Name the following alcohols according to the IUPAC nomen- clature system. Indicate stereochemistry (if any) and label the hydroxy groups as primary, secondary, or tertiary. (a) CH3CH2CHCH3 OH A (b) CH3CHCH2CHCH2CH3 Br A OH A (c) HOCH2CH(CH2CH2CH3)2 (d) C H3C CH2Cl H OH A ; G^ (e) CH2CH3 OH/∑ (f) OH Br [ ~ (g) C(CH2OH)4 (h) H OH CH2OH CH2OH H OH (i) ] - OH CH2CH2OH ( j) ClH3C CH2OH CH2CH3 25. Draw the structures of the following alcohols. (a) 2-(Trimethyl- silyl)ethanol; (b) 1-methylcyclopropanol; (c) 3-(1-methylethyl)- 2-hexanol; (d) (R)-2-pentanol; (e) 3,3-dibromocyclohexanol. 26. Rank each group of compounds in order of increasing boiling point. (a) Cyclohexane, cyclohexanol, chlorocyclohexane; (b) 2,3-dimethyl-2-pentanol, 2-methyl-2-hexanol, 2-heptanol. 27. Explain the order of water solubilities for the compounds in each of the following groups. (a) Ethanol . chloroethane . ethane; (b) methanol . ethanol . 1-propanol. 28. 1,2-Ethanediol exists to a much greater extent in the gauche conformation than does 1,2-dichloroethane. Explain. Would you expect the gauche: anti conformational ratio of 2-chloro- ethanol to be similar to that of 1,2-dichloroethane or more like that of 1,2-ethanediol? 29. The most stable conformation of trans-1,2-cyclohexanediol is the chair in which both hydroxy groups are equatorial. (a) Draw the structure or, better yet, make a model of the compound in this conformation. (b) Reaction of this diol with the chlorosilane R3SiCl, R 5 (CH3)2CH (isopropyl), gives the corresponding disilyl ether shown below. Remarkably, this transformation causes the chair to fl ip, giving a conformation where both silyl ether groups are in axial positions. Explain this observation by means of either structural drawings or models. OSiR3] ~OSiR3 30. Rank the compounds in each group in order of decreasing acidity. (a) CH3CHClCH2OH, CH3CHBrCH2OH, BrCH2CH2CH2OH (b) CH3CCl2CH2OH, CCl3CH2OH, (CH3)2CClCH2OH (c) (CH3)2CHOH, (CF3)2CHOH, (CCl3)2CHOH Problems 31. Write an appropriate equation to show how each of the follow- ing alcohols acts as, fi rst, a base, and, second, an acid in solu- tion. How do the base and acid strengths of each compare with those of methanol? (a) (CH3)2CHOH; (b) CH3CHFCH2OH; (c) CCl3CH2OH. 32. Given the pKa values of 22.2 for CH3O ! H2 and 15.5 for CH3OH, calculate the pH at which (a) methanol will contain exactly equal amounts of CH3O 1 H2 and CH3O 2; (b) 50% CH3OH and 50% CH3O 1 H2 will be present; (c) 50% CH3OH and 50% CH3O 2 will be present. 33. Do you expect hyperconjugation to be important in the stabili- zation of alkyloxonium ions (e.g., R 1 OH2, R2 1 OH)? Explain your answer. 34. Evaluate each of the following possible alcohol syntheses as being good (the desired alcohol is the major or only product), not so good (the desired alcohol is a minor product), or worth- less. (Hint: Refer to Section 7-9 if necessary.) (a) CH3CH2CH2CH2Cl CH3CH2CH2CH2OH H2O, CH3CCH3 O B (b) CH3OSO2 CH3 CH3OH HO!, H2O, ∆ (c) I HO!, H2O, ∆ OH (d) CH3CHCH2CH2CH3 I CH3CHCH2CH2CH3 H2O, ∆A OH A (e) CH3CHCH3 CH3CHCH3 CN A OH AHO!, H2O, ∆ (f ) CH3OCH3 CH3OH HO!, H2O, ∆ (g) H3C Br H2O H3C OH (h) CH3CHCH2Cl CH3 A CH3CHCH2OH CH3 AHO!, H2O, ∆ 35. For every process in Problem 34 that gives the designated prod- uct in poor yield, suggest a superior method if possible. 36. Give the major product(s) of each of the following reactions. Aqueous work-up steps (when necessary) have been omitted. (a) CH3CH CHCH3 H3PO4, H2O, ∆ P (Hint: See Section 8-4.) (b) CH3CCH2CH2CCH3 O B O B 1. LiAlH4, (CH3CH2)2O 2. H", H2O (c) C O NaBH4, CH3CH2OH B H