Prévia do material em texto
Chapter 14.5, Problem 1E Step-by-step solution Step 1 of 2 1. (a) R(Q) = (28Q e0.3Q) dQ = +c. The initial condition is R(0) : Setting Q = 0 in R(Q), we find R(0) = +c. Thus = And R(Q) + Step 2 of 2 (b) R(Q) = Let u = Then = 1, or du = dQ, and 10 u du = 10 = 10(1 + Q) +c. Since R(0) = 0, we have 0 = -10- or = 10. Thus R(Q) = 1+Q -10 + 10 = 1+Q = 1+Q 100