<div id="pf1" class="pf w0 h0" data-page-no="1"><div class="pc pc1 w0 h0"><img class="bi x0 y0 w1 h1" alt="" src="https://files.passeidireto.com/1d85f28a-ee9c-4642-9753-10f15b465d51/bg1.png"><div class="t m0 x0 h2 y1 ff1 fs0 fc0 sc0 ls3e ws0">1. <span class="fs1 ws1">N Ú M E RO<span class="_0 blank"> </span>S<span class="_1 blank"> </span>R E A IS<span class="_2 blank"> </span>C Á L C U L O<span class="_1 blank"> </span></span><span class="ls0">1<span class="fs1 ls1">-</span></span><span class="ws2">2018.2</span></div><div class="t m0 x0 h3 y2 ff1 fs2 fc1 sc0 ls3e ws3">1.<span class="_3 blank"></span>1<span class="_4 blank"> </span>V<span class="_5 blank"></span>al<span class="_3 blank"></span>or A<span class="_3 blank"></span>b<span class="_3 blank"></span>so<span class="_3 blank"></span>lu<span class="_3 blank"></span>t<span class="_3 blank"></span>o & De<span class="_3 blank"></span>si<span class="_3 blank"></span>gu<span class="_3 blank"></span>a<span class="_3 blank"></span>ld<span class="_3 blank"></span>a<span class="_3 blank"></span>de<span class="_3 blank"></span>s</div><div class="t m0 x1 h4 y3 ff2 fs3 fc2 sc0 ls3e ws4">1.<span class="_6 blank"> </span>Estude o sinal de cada uma das expressões abaixo.</div><div class="t m0 x2 h5 y4 ff2 fs3 fc2 sc0 ls3e ws5">(a) <span class="ff3 ls2 v1">x<span class="ff4 ls3">\ue000<span class="ff5 ls3e">1</span></span></span></div><div class="t m0 x3 h6 y5 ff3 fs3 fc2 sc0 ls2">x<span class="ff4 ls3">\ue000<span class="ff5 ls4">2<span class="ff2 ls3e ws6 v1">(b) </span><span class="ls3e ws7 v1">(2</span></span></span><span class="v1">x<span class="ff5 ls3e ws8">+<span class="_7 blank"> </span>1) (</span>x<span class="ff4 ls3">\ue000<span class="ff5 ls3e ws9">2) <span class="ff2 wsa">(c) </span><span class="ls5 v1">2</span></span><span class="v1">\ue000<span class="ff5 ls6">3<span class="ff3 ls3e">x</span></span></span></span></span></div><div class="t m0 x4 h7 y5 ff3 fs3 fc2 sc0 ls2">x<span class="ff5 ls3e wsb">+ 2<span class="_8 blank"> </span><span class="ff2 ws6 v1">(d) </span></span><span class="ls7 v1">x<span class="ff5 ls3e ws7">(</span></span><span class="v1">x<span class="ff4 ls8">\ue000<span class="ff5 ls3e ws8">1) (2</span></span>x<span class="ff5 ls3e wsb">+ 3)</span></span></div><div class="t m0 x2 h8 y6 ff2 fs3 fc2 sc0 ls3e wsc">(e) <span class="ff5 ws7">(2<span class="ff3 ls2">x<span class="ff4 ls3">\ue000</span></span><span class="wsd">1) <span class="ff6 ls9 v2">\ue000</span></span><span class="ff3">x<span class="ff7 fs1 lsa v3">2</span></span><span class="wsb">+ 1<span class="ff6 lsb v2">\ue001</span></span></span><span class="wse">(f )<span class="_1 blank"> </span><span class="ff3 ls7">x<span class="ff6 ls9 v2">\ue000</span><span class="ls3e ws7">x<span class="ff7 fs1 lsa v3">2</span><span class="ff5 wsb">+ 3<span class="ff6 lsc v2">\ue001</span></span></span></span><span class="wsf">(g) <span class="ff3 ws7">x<span class="ff7 fs1 lsd v3">6</span><span class="ff6 ls9 v2">\ue000</span>x<span class="ff7 fs1 lsa v3">2</span><span class="ff5 wsb">+ 3<span class="ff6 lsb v2">\ue001</span></span></span><span class="ws6">(h) <span class="ff4 ws7">\ue000<span class="ff3 ls7">x<span class="ff6 ls9 v2">\ue000</span><span class="ls3e">x<span class="ff7 fs1 lsa v3">2</span></span></span><span class="ls3">\ue000<span class="ff5 ls6">4<span class="ff6 lse v2">\ue001</span></span></span><span class="ff3">:</span></span></span></span></span></div><div class="t m0 x1 h4 y7 ff2 fs3 fc2 sc0 ls3e ws4">2.<span class="_6 blank"> </span>Resolv<span class="_9 blank"></span>a as desigualdades.</div><div class="t m0 x5 h9 y8 ff2 fs3 fc2 sc0 ls3e ws10">(a) <span class="ff3 ws7">x<span class="ff7 fs1 lsa v3">2</span><span class="ff4 ls3">\ue000<span class="ff5 lsf">4</span></span><span class="ls10">><span class="ff5 ls11">0</span></span></span><span class="ws6">(b) <span class="ff3 ws7">x<span class="ff7 fs1 ls12 v3">2</span><span class="ff4 ls3">\ue000<span class="ff5 lsf">1</span><span class="ls10">\ue014<span class="ff5 ls11">0</span></span></span></span><span class="ws11">(c) <span class="ff3 ws7">x<span class="ff7 fs1 ls13 v3">2</span><span class="ff4 ls10">\ue014<span class="ff5 ls11">4</span></span></span></span>(d) <span class="ff3 ws7">x<span class="ff7 fs1 ls14 v3">2</span><span class="ls10">><span class="ff5 ls11">1</span></span></span><span class="wsc">(e) <span class="ff5 ws7">(<span class="ff3 ls2">x<span class="ff4 ls3">\ue000</span><span class="ls3e">a</span></span>)<span class="ff7 fs1 ls13 v4">2</span><span class="ff3 ws12"><<span class="_a blank"> </span>r <span class="ff7 fs1 ls15 v3">2</span><span class="ws13">;<span class="_6 blank"> </span>r <span class="ff4 ls10">\ue015</span></span></span><span class="ls6">0</span><span class="ff3">:</span></span></span></span></div><div class="t m0 x1 h4 y9 ff2 fs3 fc2 sc0 ls3e ws4">3.<span class="_6 blank"> </span>Resolv<span class="_9 blank"></span>a as equações.</div><div class="t m0 x2 h4 ya ff2 fs3 fc2 sc0 ls3e wsf">(a) <span class="ff4 ws7">j<span class="ff3">x</span><span class="ls16">j</span><span class="ff5 ws14">= 2<span class="_b blank"> </span></span></span><span class="ws6">(b) <span class="ff4 ws7">j<span class="ff3 ls2">x</span><span class="ff5 wsb">+ 1</span><span class="ls17">j</span><span class="ff5 ws14">= 3<span class="_c blank"> </span></span><span class="ff2">(c)</span>j<span class="ff5 ls6">2<span class="ff3 ls2">x</span></span><span class="ls3">\ue000</span><span class="ff5">1</span><span class="ls17">j</span><span class="ff5 ws14">= 1<span class="_8 blank"> </span></span></span>(d) <span class="ff4 ws7">j<span class="ff3 ls2">x</span><span class="ls3">\ue000<span class="ff5 ls6">2</span><span class="ls16">j<span class="ff5 ls10">=</span></span></span>\ue000<span class="ff5">1</span></span></span></div><div class="t m0 x2 ha yb ff2 fs3 fc2 sc0 ls3e wsc">(e) <span class="ff4 ws7">j<span class="ff5 ls6">2<span class="ff3 ls2">x</span><span class="ls3e wsb">+ 3</span></span><span class="ls17">j</span><span class="ff5 ws14">= 0<span class="_d blank"> </span></span></span><span class="wse">(f )<span class="_1 blank"> </span><span class="ff4 ws7">j<span class="ff3">x</span><span class="ls17">j</span><span class="ff5 ws14">= 2<span class="ff3 ls2">x</span><span class="wsb">+ 1<span class="_d blank"> </span></span></span></span><span class="ws15">(g) <span class="ff4 ws7">j<span class="ff5 ls18">1</span><span class="ls3">\ue000<span class="ff5 ls6">2</span></span><span class="ff3">x</span><span class="ls16">j<span class="ff5 ls10">=</span></span>j<span class="ff5">3<span class="ff3 ls2">x</span><span class="wsb">+ 5</span></span><span class="ls19">j</span></span><span class="ws16">(h) <span class="ff6 ws7 v5">q</span><span class="ff5 ws7">(<span class="ff3 ls2">x<span class="ff4 ls3">\ue000</span></span>4)<span class="ff7 fs1 ls13 v4">2</span><span class="ls10">=</span><span class="ff4">\ue000</span>1</span></span></span></span></div><div class="t m0 x2 hb yc ff2 fs3 fc2 sc0 ls3e ws17">(i) <span class="ff6 ws7 v5">q</span><span class="ff5 ws7">(<span class="ff3 ls2">x<span class="ff4 ls3">\ue000</span></span>1)<span class="ff7 fs1 ls14 v4">2</span><span class="ws14">= 5<span class="_e blank"> </span></span></span><span class="ws18">(j) <span class="ff6 ws7 v5">q</span><span class="ff5 ws19">(2 <span class="ff4 ls3">\ue000</span><span class="ff3 ws7">x<span class="ff5">)<span class="ff7 fs1 ls13 v4">2</span><span class="ws14">= 4<span class="_e blank"> </span></span></span></span></span><span class="ws1a">(k) <span class="ff6 v6">\ue00c</span></span></span></div><div class="t m0 x6 hc yd ff6 fs3 fc2 sc0 ls3e">\ue00c</div><div class="t m0 x6 hc ye ff6 fs3 fc2 sc0 ls3e">\ue00c</div><div class="t m0 x6 hc yf ff6 fs3 fc2 sc0 ls3e">\ue00c</div><div class="t m0 x7 h4 y10 ff3 fs3 fc2 sc0 ls3e">x</div><div class="t m0 x8 hd y11 ff5 fs3 fc2 sc0 ls5">1<span class="ff4 ls3">\ue000</span><span class="ls6">5<span class="ff3 ls1a">x<span class="ff6 ls3e v7">\ue00c</span></span></span></div><div class="t m0 x9 hc yd ff6 fs3 fc2 sc0 ls3e">\ue00c</div><div class="t m0 x9 hc ye ff6 fs3 fc2 sc0 ls3e">\ue00c</div><div class="t m0 x9 he yf ff6 fs3 fc2 sc0 ls1b">\ue00c<span class="ff5 ls3e ws14 v3">= 4<span class="_f blank"> </span><span class="ff2 ws1b">(l) <span class="ff3 ls1c">x<span class="ff5 ls10">=</span></span></span></span><span class="ls1d v8">q</span><span class="ff5 ls3e ws7 v3">(<span class="ff4">\ue000</span>4)<span class="ff7 fs1 v4">2</span></span></div><div class="t m0 x1 h4 y12 ff2 fs3 fc2 sc0 ls3e ws1c">4.<span class="_6 blank"> </span>As desigualdades abaixo,<span class="_10 blank"> </span>en<span class="_3 blank"></span>v<span class="_3 blank"></span>olv<span class="_9 blank"></span>e<span class="_11 blank"> </span>ndo pro<span class="_11 blank"> </span>dutos e quo<span class="_11 blank"> </span>cientes, p<span class="_11 blank"> </span>o<span class="_11 blank"> </span>dem ser resolvidas p<span class="_0 blank"> </span>or meio do</div><div class="t m0 xa h4 y13 ff2 fs3 fc2 sc0 ls3e ws4">estudo do sinal, como no Exercício 9 da Seção 1.1.</div><div class="t m0 x2 h9 y14 ff2 fs3 fc2 sc0 ls3e wsf">(a) <span class="ff5 ws7">(4<span class="ff3 ls2">x</span><span class="wsb">+ 7)<span class="ff7 fs1 ws1d v4">20 </span></span>(2<span class="ff3 ls2">x</span><span class="wsb">+ 8)<span class="_a blank"> </span><span class="ff3 ls10"><</span><span class="ls1e">0</span></span></span><span class="ws6">(b) <span class="ff3 ls7">x</span><span class="ff5 ws7">(2<span class="ff3 ls2">x<span class="ff4 ls3">\ue000</span></span><span class="ws8">1) (<span class="ff3 ls2">x</span><span class="wsb">+ 1)<span class="_a blank"> </span><span class="ff3 ls10">></span><span class="ls1e">0</span></span></span></span><span class="ws1e">(c) <span class="ff8 fs4 v9">3</span></span></span></div><div class="t m0 xb h4 y15 ff4 fs3 fc2 sc0 ls1f">p<span class="ff3 ls3e ws7 va">x</span><span class="ff7 fs1 lsa vb">2</span><span class="ls3 va">\ue000<span class="ff5 lsf">1<span class="ff4 ls10">\ue014</span><span class="ls1e">0<span class="ff2 ls3e ws1f">(d) </span><span class="ls3e ws7 v1">2<span class="ff3 ls2">x</span></span></span></span><span class="v1">\ue000<span class="ff5 ls3e">1</span></span></span></div><div class="t m0 xc h7 y16 ff3 fs3 fc2 sc0 ls2">x<span class="ff4 ls3">\ue000<span class="ff5 ls20">3</span></span><span class="ls10 v1">><span class="ff5 ls3e">5</span></span></div><div class="t m0 x2 h5 y17 ff2 fs3 fc2 sc0 ls3e ws20">(e) <span class="ff3 v1">x</span></div><div class="t m0 x3 h6 y18 ff5 fs3 fc2 sc0 ls6">2<span class="ff3 ls2">x<span class="ff4 ls3">\ue000</span></span><span class="ls21">3<span class="ff4 ls10 v1">\ue014</span><span class="ls22 v1">3<span class="ff2 ls3e wse">(f )<span class="_1 blank"> </span><span class="ff5 ws7">(2<span class="ff3 ls2">x<span class="ff4 ls3">\ue000</span></span><span class="ws8">1) (<span class="ff3 ls2">x</span><span class="wsb">+ 3)<span class="_a blank"> </span><span class="ff3 ls10"><</span><span class="ls23">0</span></span></span></span><span class="ws5">(g) </span></span></span><span class="ls3e ws7 vc">2<span class="ff3 ls2">x<span class="ff4 ls3">\ue000</span></span>1</span></span></div><div class="t m0 xd h6 y18 ff3 fs3 fc2 sc0 ls2">x<span class="ff5 ls3e wsb">+ 1<span class="_12 blank"> </span></span><span class="ls10 v1"><<span class="ff5 ls24">0<span class="ff2 ls3e ws1f">(h) </span><span class="ls3e ws7 v1">3</span></span></span><span class="vc">x<span class="ff4 ls3">\ue000<span class="ff5 ls3e">2</span></span></span></div><div class="t m0 xc h7 y18 ff5 fs3 fc2 sc0 ls5">2<span class="ff4 ls3">\ue000<span class="ff3 ls25">x</span><span class="ls10 v1">\ue014</span></span><span class="ls3e v1">0</span></div><div class="t m0 x2 hf y19 ff2 fs3 fc2 sc0 ls3e ws1f">(d) <span class="ff3 ws7 v1">x</span><span class="ff7 fs1 lsa vd">2</span><span class="ff4 ls8 v1">\ue000</span><span class="ff5 v1">9</span></div><div class="t m0 xe h10 y1a ff3 fs3 fc2 sc0 ls2">x<span class="ff5 ls3e wsb">+ 1<span class="_13 blank"> </span></span><span class="ls10 v1"><<span class="ff5 ls26">0<span class="ff2 ls3e ws21">(j) </span><span class="ls3e ws7">(2</span></span></span><span class="v1">x<span class="ff4 ls3">\ue000<span class="ff5 ls3e ws22">1) <span class="ff6 ls9 v2">\ue000</span><span class="ff3 ws7">x<span class="ff7 fs1 ls12 v3">2</span></span></span>\ue000<span class="ff5 ls6">4<span class="ff6 ls27 v2">\ue001</span></span><span class="ls10">\ue014<span class="ff5 ls28">0</span></span></span></span><span class="ls29 vc">x<span class="ff4 ls3">\ue000<span class="ff5 ls3e">3</span></span></span></div><div class="t m0 xf h11 y1a ff3 fs3 fc2 sc0 ls3e ws7">x<span class="ff7 fs1 ls12 ve">2</span><span class="ff5 wsb">+ 1<span class="_14 blank"> </span></span><span class="ls10 v1">><span class="ff5 ls2a">5<span class="ff2 ls3e ws23">(i) </span></span></span><span class="vc">x</span><span class="ff7 fs1 ls12 vf">2</span><span class="ff4 ls3 vc">\ue000</span><span class="ff5 vc">4</span></div><div class="t m0 x10 h7 y1a ff3 fs3 fc2 sc0 ls3e ws7">x<span class="ff7 fs1 ls12 ve">2</span><span class="ff5 wsb">+ 4<span class="_14 blank"> </span></span><span class="ls10 v1">><span class="ff5 ls6">0</span></span><span class="v1">:</span></div><div class="t m0 x1 h4 y1b ff2 fs3 fc2 sc0 ls3e ws4">5.<span class="_6 blank"> </span>Resolv<span class="_9 blank"></span>a as Desigualdades.</div><div class="t m0 x2 h12 y1c ff2 fs3 fc2 sc0 ls3e wsf">(a) <span class="ff3 ws7">x<span class="ff7 fs1 lsa v3">2</span><span class="ff4 ls3">\ue000<span class="ff5 ls6">3</span></span><span class="ls2">x</span><span class="ff5 wsb">+ 2<span class="_a blank"> </span></span><span class="ls10"><<span class="ff5 ls2b">0</span></span></span><span class="ws16">(b) <span class="ff3 ws7">x<span class="ff7 fs1 ls12 v3">2</span><span class="ff5 ls3">+</span><span class="ls2">x</span><span class="ff5 wsb">+ 1<span class="_a blank"> </span><span class="ff4 ls10">\ue014</span><span class="ls2c">0</span></span></span><span class="wsc">(c) <span class="ff5 ws7">3<span class="ff3">x<span class="ff7 fs1 lsa v3">2</span></span><span class="ls3">+<span class="ff3 ls29">x</span><span class="ff4">\ue000</span><span class="ls2d">2<span class="ff3 ls2e">></span></span></span>0</span></span></span></div><div class="t m0 x2 h13 y1d ff2 fs3 fc2 sc0 ls3e ws16">(d) <span class="ff5 ws7">4<span class="ff3">x<span class="ff7 fs1 ls12 v3">2</span><span class="ff4 ls3">\ue000</span></span>4<span class="ff3 ls2">x</span><span class="wsb">+ 1<span class="_a blank"> </span><span class="ff4 ls10">\ue014</span><span class="ls2f">0</span></span></span><span class="wsc">(e) <span class="ff3 ws7">x<span class="ff7 fs1 ls12 v3">2</span><span class="ff5 wsb">+ 3<span class="_a blank"> </span></span><span class="ls10">><span class="ff5 ls30">0</span></span></span><span class="wse">(f )<span class="_1 blank"> </span><span class="ff3 ws7">x<span class="ff7 fs1 lsa v3">2</span><span class="ff5 ls3">+</span><span class="ls2">x</span><span class="ff5 wsb">+ 1<span class="_a blank"> </span></span><span class="ls10">></span><span class="ff5">0</span></span></span></span></div><div class="t m0 x2 h13 y1e ff2 fs3 fc2 sc0 ls3e wsf">(g) <span class="ff3 ws7">x<span class="ff7 fs1 ls12 v3">2</span><span class="ff4 ls3">\ue000<span class="ff5 ls6">5</span></span><span class="ls2">x</span><span class="ff5 wsb">+ 6<span class="_a blank"> </span><span class="ff4 ls10">\ue015</span><span class="ls2b">0</span></span></span><span class="ws6">(h) <span class="ff3 ws7">x<span class="ff7 fs1 ls12 v3">2</span><span class="ff5 wsb">+ 5<span class="_a blank"> </span><span class="ff4 ls10">\ue014</span><span class="ls31">0</span></span></span><span class="ws17">(i) <span class="ff5 ws7">(<span class="ff3 ls2">x<span class="ff4 ls3">\ue000</span></span><span class="ws8">2) (<span class="ff3 ls2">x</span>+<span class="_7 blank"> </span>3) (1<span class="_7 blank"> </span><span class="ff4 ls3">\ue000</span></span><span class="ff3">x</span><span class="ls32">)<span class="ff3 ls10">></span></span>0</span></span></span></div><div class="t m0 x2 h14 y1f ff2 fs3 fc2 sc0 ls3e ws18">(j) <span class="ff3 ws7">x<span class="ff7 fs1 lsa v3">2</span><span class="ff5 wsb">+ 1<span class="_a blank"> </span></span><span class="ls10"><<span class="ff5 ls6">3</span><span class="ls2">x<span class="ff4 ls3">\ue000</span></span></span>x<span class="ff7 fs1 lsa v3">2</span><span class="ff4 ls3">\ue000<span class="ff5 ls1e">3</span></span></span><span class="ws1a">(k) <span class="ff3 ls7">x</span><span class="ff5 ws7">(<span class="ff3 ls2">x</span><span class="wsb">+ 4)<span class="ff7 fs1 lsd v4">2</span></span>(<span class="ff3 ls2">x<span class="ff4 ls3">\ue000</span></span>2)<span class="ff9 fs1 ls33 v4">\ue000<span class="ff7 ls14">4</span></span><span class="ff3 ls10"><</span><span class="ls1e">0</span></span><span class="ws17">(l) <span class="ff6 ls9 v2">\ue000</span><span class="ff3 ws7">x<span class="ff7 fs1 lsa v3">2</span><span class="ff4 ls3">\ue000<span class="ff5 ls6">4</span></span><span class="ff6 ws8 v2">\ue001 \ue000</span>x<span class="ff7 fs1 lsa v3">2</span><span class="ff4 ls3">\ue000<span class="ff5 ls6">3</span></span><span class="ls2">x</span><span class="ff5 wsb">+ 2<span class="ff6 ls27 v2">\ue001</span><span class="ff4 ls10">\ue014</span>0</span></span></span></span></div><div class="t m0 x1 h4 y20 ff2 fs3 fc2 sc0 ls3e ws4">6.<span class="_6 blank"> </span>Dê o conjun<span class="_3 blank"></span>to solução de cada uma das inequações mo<span class="_11 blank"> </span>dulares abaixo.</div><div class="t m0 x2 h4 y21 ff2 fs3 fc2 sc0 ls3e wsf">(a) <span class="ff4 ws7">j<span class="ff3">x</span><span class="ws24">j \ue014 <span class="ff5 ls34">1</span></span></span><span class="ws6">(b) <span class="ff4 ws7">j<span class="ff5 ls6">2<span class="ff3 ls2">x</span></span><span class="ls3">\ue000<span class="ff5 ls6">1</span><span class="ls16">j<span class="ff3 ls10"><<span class="ff5 ls35">3</span></span></span></span></span><span class="ws11">(c) <span class="ff4 ws7">j<span class="ff3">x</span><span class="ls17">j<span class="ff3 ls10">><span class="ff5 ls36">3</span></span></span></span></span>(d) <span class="ff4 ws7">j<span class="ff5 ls6">3<span class="ff3 ls2">x</span><span class="ls3e wsb">+ 3</span></span><span class="ws25">j \ue014 <span class="ff5 ls6">1</span></span><span class="ff3">=<span class="ff5">3</span></span></span></span></div><div class="t m0 x2 h15 y22 ff2 fs3 fc2 sc0 ls3e wsc">(e) <span class="ff6 v10">\ue00c</span></div><div class="t m0 x11 h16 y23 ff6 fs3 fc2 sc0 ls37">\ue00c<span class="ff5 ls6 v11">2<span class="ff3 ls3e ws7">x<span class="ff7 fs1 lsa v3">2</span><span class="ff4 ls3">\ue000</span></span>1</span><span class="ls3e v12">\ue00c</span></div><div class="t m0 x12 hc y23 ff6 fs3 fc2 sc0 ls1b">\ue00c<span class="ff3 ls10 v11"><<span class="ff5 ls38">1<span class="ff2 ls3e wse">(f )<span class="_1 blank"> </span><span class="ff4 ws7">j</span></span><span class="ls6">3<span class="ff3 ls2">x<span class="ff4 ls3">\ue000</span></span><span class="ls3e ws7">1<span class="ff4 ls17">j</span></span></span></span><<span class="ff4 ls3e ws7">\ue000<span class="ff5 ls39">2</span><span class="ff2 ws15">(g) </span>j</span><span class="ls2">x<span class="ff5 ls3e wsb">+ 3<span class="ff4 ws24">j \ue015 </span><span class="ls3a">1</span><span class="ff2 ws6">(h) <span class="ff4 ws7">j</span></span><span class="ls6">2</span></span>x<span class="ff4 ls3">\ue000<span class="ff5 ls6">1</span><span class="ls16">j</span></span><span class="ls3e ws14">< x</span></span></span></div><div class="t m0 x2 h17 y24 ff2 fs3 fc2 sc0 ls3e ws17">(i) <span class="ff4 ws7">j<span class="ff3 ls2">x</span><span class="ff5 wsb">+ 1</span><span class="ls17">j<span class="ff3 ls10"><</span></span>j<span class="ff5 ls6">2<span class="ff3 ls2">x</span></span><span class="ls3">\ue000</span><span class="ff5">1</span><span class="ls3b">j</span></span><span class="ws21">(j) <span class="ff4 ws7">j<span class="ff3 ls2">x</span><span class="ls3">\ue000</span><span class="ff5">2</span><span class="ls3 ws26">j\ue000j<span class="_15 blank"></span><span class="ff3 ls2">x<span class="ff4 ls3">\ue000<span class="ff5 ls6">5</span><span class="ls16">j</span></span><span class="ls3e ws14">> x<span class="_e blank"> </span><span class="ff2 ws1a">(k) <span class="ff6 v13">\ue00c</span></span></span></span></span></span></span></div><div class="t m0 x13 hc y25 ff6 fs3 fc2 sc0 ls3e">\ue00c</div><div class="t m0 x13 h18 y26 ff6 fs3 fc2 sc0 ls37">\ue00c<span class="ff5 ls3e ws7 v14">(<span class="ff3 ls2">x<span class="ff4 ls3">\ue000</span></span>1)<span class="ff7 fs1 ls15 v4">3</span><span class="ff6 v13">\ue00c</span></span></div><div class="t m0 xd hc y25 ff6 fs3 fc2 sc0 ls3e">\ue00c</div><div class="t m0 xd h19 y26 ff6 fs3 fc2 sc0 ls3c">\ue00c<span class="ff3 ls10 v14"><<span class="ff5 ls1e">1<span class="ff2 ls3e ws1b">(l) <span class="ff4 ws7">j<span class="ff3 ls2">x</span><span class="ls3">\ue000</span><span class="ff5">1</span><span class="ls3d">j</span></span></span><span class="ls3">+<span class="ff4 ls3e ws7">j<span class="ff3 ls2">x</span></span><span class="ls3e wsb">+ 3<span class="ff4 ls17">j</span></span></span></span><<span class="ff4 ls3e ws7">j<span class="ff5 ls6">4</span><span class="ff3">x</span>j</span></span></div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf2" class="pf w0 h0" data-page-no="2"><div class="pc pc2 w0 h0"><img class="bi x14 y27 w2 h1a" alt="" src="https://files.passeidireto.com/1d85f28a-ee9c-4642-9753-10f15b465d51/bg2.png"><div class="t m0 x14 h4 y28 ff2 fs3 fc2 sc0 ls3f">2<span class="ff1 fs1 fc0 ls3e ws1">C Á L C U L O<span class="_1 blank"> </span>D E<span class="_1 blank"> </span>U M A<span class="_1 blank"> </span>V<span class="_9 blank"></span>A R I Á<span class="_9 blank"></span>V E L<span class="_16 blank"> </span>M A R I V<span class="_9 blank"></span>A LD O<span class="_17 blank"> </span>P<span class="_9 blank"></span>.<span class="_1 blank"> </span>M ATO S</span></div><div class="t m0 x15 h4 y29 ff2 fs3 fc2 sc0 ls3e ws28">7.<span class="_6 blank"> </span>Duas desigualdades são ditas <span class="ffa ws7">e<span class="_9 blank"></span>quivalentes<span class="ff2 ws29">, se p<span class="_11 blank"> </span>ossuem o mesmo conjunto de soluções.<span class="_6 blank"> </span>Com base</span></span></div><div class="t m0 x3 h4 y2a ff2 fs3 fc2 sc0 ls3e ws4">nesta de\u2026<span class="_18 blank"></span>nição, classi\u2026<span class="_18 blank"></span>que os pares de desigualdades abaixo.</div><div class="t m0 x16 h1b y2b ff2 fs3 fc2 sc0 ls3e ws10">(a) <span class="ff4 ls1f v15">p</span><span class="ff3 ls2">x<span class="ff4 ls3">\ue000<span class="ff5 lsf">1</span></span><span class="ls10"><<span class="ff4 ls1f v15">p</span><span class="ff5 ls18">2<span class="ff4 ls3">\ue000</span></span><span class="ls40">x</span></span></span><span class="ls41">e<span class="ff3 ls2">x<span class="ff4 ls3">\ue000<span class="ff5 lsf">2</span></span><span class="ls10"><<span class="ff5 ls5">1<span class="ff4 ls3">\ue000</span></span><span class="ls42">x</span></span></span></span><span class="ff1 ws2a">(b) <span class="ff3 ws7">x<span class="ff7 fs1 ls14 v3">2</span><span class="ls2e">><span class="ff5 ls43">1</span></span></span></span><span class="ls44">e</span><span class="ff5 wsb">1 +<span class="_19 blank"> </span><span class="v1">2</span></span></div><div class="t m0 x17 h7 y2c ff3 fs3 fc2 sc0 ls2">x<span class="ff4 ls3">\ue000<span class="ff5 ls21">1</span></span><span class="ls10 v1">><span class="ff5 ls6">0<span class="ff3 ls3e">:</span></span></span></div><div class="t m0 x15 h4 y2d ff2 fs3 fc2 sc0 ls3e ws2b">8.<span class="_6 blank"> </span>Resolv<span class="_9 blank"></span>a os sistemas de inequações.</div><div class="t m0 x18 h1c y2e ff2 fs3 fc2 sc0 ls3e wsf">(a) <span class="ff6 ls45 vf">(</span><span class="ff5 ws7 v16">8<span class="ff3 ls2">x<span class="ff4 ls8">\ue000<span class="ff5 ls2d">2</span></span><span class="ls3e ws2c"><<span class="_a blank"> </span>x <span class="ff4 ls3">\ue000</span><span class="ff5">1</span></span></span></span></div><div class="t m0 x12 h1d y2f ff5 fs3 fc2 sc0 ls3e ws7">2<span class="ff3">x<span class="ff7 fs1 ls12 v3">2</span><span class="ff4 ls3">\ue000</span><span class="ls1c">x<span class="ff4 ls10">\ue014</span></span></span><span class="ls46">1</span><span class="ff2 ws6 v17">(b) </span><span class="ff6 ls45 v18">(</span><span class="ls6 v8">4</span><span class="ff3 v8">x</span><span class="ff7 fs1 lsa v19">2</span><span class="ff4 ls3 v8">\ue000</span><span class="ls6 v8">4<span class="ff3 ls2">x<span class="ff4 ls3">\ue000<span class="ff5 lsf">3</span></span><span class="ls10"><</span></span></span><span class="v8">0</span></div><div class="t m0 x19 h13 y2f ff5 fs3 fc2 sc0 ls6">1<span class="ff3 ls3e ws7">=x<span class="ff7 fs1 ls13 v3">2</span><span class="ff4 ls10">\ue015</span><span class="ff5">1</span></span></div><div class="t m0 x15 h4 y30 ff2 fs3 fc2 sc0 ls3e ws2b">9.<span class="_6 blank"> </span>Mostre que:</div><div class="t m0 x1a h5 y31 ff3 fs3 fc2 sc0 ls2">x<span class="ff5 ls47">+<span class="ls3e v1">1</span></span></div><div class="t m0 x1b h7 y32 ff3 fs3 fc2 sc0 ls48">x<span class="ff4 ls10 v1">\ue015<span class="ff5 ls3e ws7">2<span class="ff3 ls49">;<span class="ff4 ls4a">8</span><span class="ls3e ws2d">x > </span></span>0<span class="ff3">:</span></span></span></div><div class="t m0 x5 h4 y33 ff2 fs3 fc2 sc0 ls3e ws4">10.<span class="_6 blank"> </span>Mostre que não existem n<span class="_3 blank"></span>úmeros reais <span class="ff3 ls4b">x</span><span class="ls4c">e<span class="ff3 ls4d">y</span></span>, tais que:</div><div class="t m0 x1c h4 y34 ff5 fs3 fc2 sc0 ls3e">1</div><div class="t m0 x1c h6 y35 ff3 fs3 fc2 sc0 ls4e">x<span class="ff5 ls4f v1">+<span class="ls3e v1">1</span></span></div><div class="t m0 x1d h6 y35 ff3 fs3 fc2 sc0 ls50">y<span class="ff5 ls51 v1">=<span class="ls3e v1">1</span></span></div><div class="t m0 x1e h7 y35 ff3 fs3 fc2 sc0 ls2">x<span class="ff5 ls3">+</span><span class="ls52">y<span class="ls3e v1">:</span></span></div><div class="t m0 x1f h1e y36 ff1 fs1 fc1 sc0 ls3e ws2e">R E S P O<span class="_0 blank"> </span>S T<span class="_9 blank"></span>A<span class="_0 blank"> </span>S<span class="_1 blank"> </span>&<span class="_1 blank"> </span>S U G<span class="_0 blank"> </span>E S T Õ E<span class="_0 blank"> </span>S</div><div class="t m0 x14 h1f y37 ffb fs4 fc1 sc0 ls3e ws2f">:<span class="_9 blank"></span>::<span class="_9 blank"></span>:<span class="_9 blank"></span>:<span class="_3 blank"></span>:<span class="_9 blank"></span>::<span class="_9 blank"></span>:<span class="_9 blank"></span>::<span class="_9 blank"></span>:<span class="_9 blank"></span>:</div><div class="t m0 x14 h1e y38 ff1 fs1 fc1 sc0 ls3e ws30">E X<span class="_0 blank"> </span>E R C<span class="_0 blank"> </span>ÍC<span class="_11 blank"> </span>I O<span class="_0 blank"> </span>S</div><div class="t m0 x20 h1f y37 ffb fs4 fc1 sc0 ls3e ws2f">:<span class="_9 blank"></span>::</div><div class="t m0 x12 h1e y38 ff1 fs1 fc1 sc0 ls53">&<span class="ffb fs4 ls3e ws2f v1a">:<span class="_9 blank"></span>::<span class="_9 blank"></span>:<span class="_9 blank"></span>:<span class="_3 blank"></span>:<span class="_9 blank"></span>::<span class="_9 blank"></span>:<span class="_9 blank"></span>::<span class="_9 blank"></span>:<span class="_9 blank"></span>:<span class="_3 blank"></span>:<span class="_9 blank"></span>::<span class="_9 blank"></span>:<span class="_9 blank"></span>::</span></div><div class="t m0 x21 h1e y38 ff1 fs1 fc1 sc0 ls3e ws31">C O M<span class="_0 blank"> </span>P L E M E N T O S</div><div class="t m0 x22 h1f y37 ffb fs4 fc1 sc0 ls3e ws2f">:<span class="_9 blank"></span>::<span class="_9 blank"></span>:</div><div class="t m0 x23 h2 y38 ff1 fs0 fc1 sc0 ls3e">1.1</div><div class="t m0 x15 h4 y39 ff2 fs3 fc2 sc0 ls3e ws4">1.<span class="_6 blank"> </span>Como ilustração, v<span class="_3 blank"></span>eja na Figura abaixo como se obtém o sinal da expressão <span class="ff5 ws7">(<span class="ff3 ls2">x<span class="ff4 ls3">\ue000</span></span><span class="ws8">1) (<span class="ff3 ls2">x<span class="ff4 ls8">\ue000</span></span><span class="wsd">2) <span class="ff3">:</span></span></span></span></div><div class="t m0 x3 h4 y3a ff2 fs3 fc2 sc0 ls3e ws4">V<span class="_1a blank"></span>emos que a expressão <span class="ff5 ws7">(<span class="ff3 ls2">x<span class="ff4 ls3">\ue000</span></span><span class="ws8">1) (<span class="ff3 ls2">x<span class="ff4 ls3">\ue000</span></span><span class="ws32">2) </span></span></span><span class="ws33">é<span class="_1 blank"> </span>p ositiv<span class="_9 blank"></span>a<span class="_1 blank"> </span>se<span class="_1 blank"> </span><span class="ff3 ws2d">x < <span class="ff5 ls54">1</span></span><span class="ws34">ou <span class="ff3 ws2d">x > <span class="ff5 ls54">2</span></span><span class="ws4">e é negativ<span class="_9 blank"></span>a se <span class="ff5 lsf">1</span><span class="ff3 ws2d">< x < <span class="ff5 ls6">2</span>:</span></span></span></span></div><div class="t m0 x24 h4 y3b ff2 fs3 fc2 sc0 ls3e ws33">p ositiv<span class="_9 blank"></span>a<span class="_1b blank"> </span>negativ<span class="_9 blank"></span>a<span class="_1c blank"> </span>zero<span class="_1d blank"> </span>inde\u2026<span class="_18 blank"></span>nida</div><div class="t m0 x18 h4 y3c ff2 fs3 fc2 sc0 ls3e ws35">(a) <span class="ff5 ws7">(<span class="ff4">\ue0001<span class="ff3 ls55">;</span></span><span class="ws19">1) <span class="ff4 ls56">[</span></span>(2<span class="ff3 ls57">;</span>+<span class="ff4">1</span><span class="ws36">) (1<span class="ff3 ls55">;</span><span class="ws37">2) <span class="ff4 ls6">f</span></span></span>1<span class="ff4 ls58">g<span class="ff3 ls1c">x</span></span><span class="ws14">= 2</span></span></div><div class="t m0 x18 h4 y3d ff2 fs3 fc2 sc0 ls3e ws38">(b) <span class="ff5 ws7">(<span class="ff4">\ue0001<span class="ff3 ls55">;</span>\ue000</span><span class="ls6">1</span><span class="ff3">=</span><span class="ws19">2) <span class="ff4 ls56">[</span></span>(2<span class="ff3 ls57">;</span>+<span class="ff4">1</span><span class="ws39">) (</span><span class="ff4">\ue000</span>1<span class="ff3 ls6">=<span class="ff5">2</span><span class="ls55">;</span></span><span class="ws3a">2) </span><span class="ff4">f\ue000</span><span class="ls6">1</span><span class="ff3">=</span><span class="ls6">2<span class="ff3 ls55">;</span>2</span><span class="ff4">g</span></span></div><div class="t m0 x18 h4 y3e ff2 fs3 fc2 sc0 ls3e ws3b">(c) <span class="ff5 ws7">(<span class="ff4">\ue000</span>2<span class="ff3 ls57">;</span>2<span class="ff3 ls6">=</span><span class="ws3c">3) (</span><span class="ff4">\ue0001<span class="ff3 ls55">;</span>\ue000</span><span class="ws19">2) <span class="ff4 ls56">[</span></span>(2<span class="ff3 ls6">=</span>3<span class="ff3 ls57">;</span>+<span class="ff4">1</span><span class="ls59">)</span><span class="ff4">f</span><span class="ls6">2</span><span class="ff3">=</span><span class="ls6">3<span class="ff4 ls5a">g<span class="ff3 ls1c">x</span></span><span class="ls10">=</span></span><span class="ff4">\ue000</span>2</span></div><div class="t m0 x18 h4 y3f ff2 fs3 fc2 sc0 ls3e ws3d">(d) <span class="ff5 ws7">(<span class="ff4">\ue000</span>3<span class="ff3 ls6">=</span>2<span class="ff3 ls57">;</span><span class="ws19">0) <span class="ff4 ls56">[</span></span>(1<span class="ff3 ls55">;<span class="ff4 ls1d">1</span></span><span class="ws3e">) (</span><span class="ff4">\ue0001<span class="ff3 ls57">;</span>\ue000</span>3<span class="ff3 ls6">=</span><span class="ws19">2) <span class="ff4 ls56">[</span></span>(0<span class="ff3 ls55">;</span><span class="ws3f">1) <span class="ff4 ls6">f</span></span>0<span class="ff3 ls57">;</span>1<span class="ff3 ls57">;</span><span class="ff4">\ue000</span>3<span class="ff3 ls6">=</span>2<span class="ff4">g</span></span></div><div class="t m0 x18 h4 y40 ff2 fs3 fc2 sc0 ls3e ws40">(e) <span class="ff5 ws7">(1<span class="ff3 ls6">=</span>2<span class="ff3 ls57">;</span>+<span class="ff4">1</span><span class="ws41">) (</span><span class="ff4">\ue0001<span class="ff3 ls55">;</span></span><span class="ls6">1</span><span class="ff3">=</span><span class="ws42">2) </span><span class="ff4">f</span><span class="ls6">1</span><span class="ff3">=</span><span class="ls6">2</span><span class="ff4">g</span></span></div><div class="t m0 x18 h4 y41 ff2 fs3 fc2 sc0 ls3e wse">(f )<span class="_1e blank"> </span><span class="ff5 ws7">(0<span class="ff3 ls55">;</span>+<span class="ff4">1</span><span class="ws43">) (</span><span class="ff4">\ue0001<span class="ff3 ls57">;</span></span><span class="ws44">0) <span class="ff4 ls6">f</span></span>0<span class="ff4">g</span></span></div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf3" class="pf w0 h0" data-page-no="3"><div class="pc pc3 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 y42 w3 h20" alt="" src="https://files.passeidireto.com/1d85f28a-ee9c-4642-9753-10f15b465d51/bg3.png"><div class="t m0 x0 h2 y28 ff1 fs1 fc0 sc0 ls3e ws45">C O M P L E M E N T O S<span class="_1 blank"> </span><span class="fs0 ls5b">1</span><span class="ws1">N Ú M E RO S<span class="_1 blank"> </span>R E A I S<span class="_19 blank"> </span><span class="ff2 fs3 fc2">3</span></span></div><div class="t m0 x1 h21 y29 ff2 fs3 fc2 sc0 ls3e ws46">2. <span class="ff1 ws47">(a) <span class="ff3 ws7">x<span class="ff7 fs1 ls13 v3">2</span><span class="ls10">><span class="ff5 lsf">4</span></span><span class="ff4 ws14">, j</span>x<span class="ff4 ls17">j</span><span class="ls10">><span class="ff5 lsf">2<span class="ff4 ls5c">,</span></span></span><span class="ws2d">x > <span class="ff5 ls11">2</span></span></span></span><span class="ws48">ou <span class="ff3 ws2d">x < <span class="ff4 ws7">\ue000<span class="ff5 ls6">2</span></span>:</span></span></div><div class="t m0 xa h21 y43 ff1 fs3 fc2 sc0 ls3e ws49">(b) <span class="ff3 ws7">x<span class="ff7 fs1 ls13 v3">2</span><span class="ff4 ls10">\ue014<span class="ff5 lsf">1</span><span class="ls3e ws14">, j</span></span>x<span class="ff4 ws24">j \ue014 <span class="ff5 lsf">1</span><span class="ws14">, \ue000<span class="ff5 lsf">1</span><span class="ls10">\ue014</span></span></span><span class="ls1c">x<span class="ff4 ls10">\ue014<span class="ff5 ls6">1</span></span></span>:</span></div><div class="t m0 xa h21 y44 ff1 fs3 fc2 sc0 ls3e ws4a">(c) <span class="ff3 ws7">x<span class="ff7 fs1 ls14 v3">2</span><span class="ff4 ls10">\ue014<span class="ff5 lsf">4</span><span class="ls3e ws14">, j</span></span>x<span class="ff4 ws25">j \ue014 <span class="ff5 lsf">2</span><span class="ws14">, \ue000<span class="ff5 lsf">2</span><span class="ls10">\ue014</span></span></span><span class="ls1c">x<span class="ff4 ls10">\ue014<span class="ff5 ls6">2</span></span></span>:</span></div><div class="t m0 xa h21 y45 ff1 fs3 fc2 sc0 ls3e ws49">(d) <span class="ff3 ws2d">x > <span class="ff5 ls54">1</span><span class="ff2 ws1b">ou </span>x < <span class="ff4 ws7">\ue000<span class="ff5 ls6">1</span></span>:</span></div><div class="t m0 xa h9 y46 ff1 fs3 fc2 sc0 ls3e ws4b">(e) <span class="ff5 ws7">(<span class="ff3 ls2">x<span class="ff4 ls8">\ue000</span><span class="ls3e">a</span></span>)<span class="ff7 fs1 ls13 v4">2</span><span class="ff3 ws12"><<span class="_a blank"> </span>r <span class="ff7 fs1 ls14 v3">2</span><span class="ff4 ws14">) j</span><span class="ls2">x<span class="ff4 ls3">\ue000</span></span><span class="ws7">a<span class="ff4 ls16">j</span><span class="ws14">< r<span class="_1 blank"> </span><span class="ff4 ls5d">,</span><span class="ls5e">a<span class="ff4 ls3">\ue000</span></span><span class="ws2d">r < x < a<span class="_7 blank"> </span></span></span></span></span><span class="ls3">+</span><span class="ff3">r:</span></span></div><div class="t m0 x1 h4 y47 ff2 fs3 fc2 sc0 ls3e ws4c">3.<span class="_6 blank"> </span>Decorre da de\u2026<span class="_18 blank"></span>nição de V<span class="_1a blank"></span>alor Absoluto que <span class="ff4 ws7">j<span class="ffc">\ue003</span><span class="ls16">j<span class="ff5 ls10">=<span class="ff3 ls5f">a</span></span><span class="ls5c">,<span class="ffc ls10">\ue003<span class="ff5 ls2e">=</span></span></span></span>\ue006<span class="ff3 ws4d">a: </span></span>Esta é a propriedade a ser usada.</div><div class="t m0 x2 h4 y48 ff2 fs3 fc2 sc0 ls3e wsf">(a) <span class="ff3 ls1c">x<span class="ff5 ls10">=</span></span><span class="ff4 ws7">\ue006<span class="ff5 ls60">2</span></span><span class="ws6">(b) <span class="ff3 ls1c">x</span><span class="ff5 ws14">= 2<span class="_1 blank"> </span></span><span class="ws34">ou <span class="ff3 ls1c">x<span class="ff5 ls10">=</span></span><span class="ff4 ws7">\ue000<span class="ff5 ls1e">4</span></span><span class="ws11">(c) <span class="ff3 ls61">x</span><span class="ff5 ws14">= 0<span class="_1 blank"> </span></span><span class="ws1b">ou <span class="ff3 ls61">x</span><span class="ff5 ws14">= 1<span class="_1f blank"> </span></span></span></span></span>(d) <span class="ffd">?</span></span></div><div class="t m0 x2 h4 y49 ff2 fs3 fc2 sc0 ls3e wsc">(e) <span class="ff3 ls1c">x<span class="ff5 ls10">=</span></span><span class="ff4 ws7">\ue000<span class="ff5">3<span class="ff3 ls6">=</span><span class="ls62">2</span></span></span><span class="wse">(f )<span class="_1 blank"> </span><span class="ff3 ls1c">x<span class="ff5 ls10">=</span></span><span class="ff4 ws7">\ue000<span class="ff5 ls6">1</span><span class="ff3">=<span class="ff5 ls63">3</span></span></span><span class="ws15">(g) <span class="ff3 ls61">x<span class="ff5 ls10">=</span></span><span class="ff4 ws7">\ue000<span class="ff5">4<span class="ff3 ls6">=</span><span class="ls54">5</span></span></span><span class="ws1b">ou <span class="ff3 ls61">x<span class="ff5 ls10">=</span></span><span class="ff4 ws7">\ue000<span class="ff5 ls64">6</span></span><span class="ws6">(h) <span class="ffd">?</span></span></span></span></span></div><div class="t m0 x2 h4 y4a ff2 fs3 fc2 sc0 ls3e ws17">(i) <span class="ff3 ls1c">x</span><span class="ff5 ws14">= 6<span class="_1 blank"> </span></span><span class="ws34">ou <span class="ff3 ls1c">x<span class="ff5 ls10">=</span></span><span class="ff4 ws7">\ue000<span class="ff5 ls1e">4</span></span><span class="ws18">(j) <span class="ff3 ls1c">x<span class="ff5 ls10">=</span></span><span class="ff4 ws7">\ue000<span class="ff5 ls54">2</span></span><span class="ws1b">ou <span class="ff3 ls61">x</span><span class="ff5 ws14">= 6<span class="_20 blank"> </span></span><span class="ws1a">(k) <span class="ff3 ls1c">x</span><span class="ff5 ws14">= 4<span class="ff3 ls6">=</span><span class="ws4e">21 </span></span></span></span></span>ou <span class="ff3 ls1c">x</span><span class="ff5 ws14">= 4<span class="ff3 ws7">=</span><span class="ws4f">19 </span></span><span class="ws1b">(l) <span class="ff3 ls1c">x</span><span class="ff5 ws14">= 4</span></span></span></div><div class="t m0 x1 h4 y4b ff2 fs3 fc2 sc0 ls3e ws4">4.<span class="_6 blank"> </span>Expressemos as resp<span class="_11 blank"> </span>ostas na forma de interv<span class="_1a blank"></span>alo.</div><div class="t m0 x5 h9 y4c ff2 fs3 fc2 sc0 ls3e ws50">(a)<span class="_6 blank"> </span>Na expressão <span class="ff5 ws7">(4<span class="ff3 ls2">x</span><span class="wsb">+ 7)<span class="ff7 fs1 ws51 v4">20 </span></span>(2<span class="ff3 ls2">x</span><span class="wsb">+ 8)<span class="_21 blank"> </span></span></span><span class="ws52">v<span class="_3 blank"></span>emos que o primeiro fator é p<span class="_11 blank"> </span>ositiv<span class="_9 blank"></span>a e a expressão será</span></div><div class="t m0 x3 h4 y4d ff2 fs3 fc2 sc0 ls3e ws4">negativ<span class="_9 blank"></span>a quando <span class="ff5 ws7">2<span class="ff3 ls2">x<span class="ff4 ls3">\ue000</span></span><span class="lsf">8<span class="ff3 ls10"><</span><span class="ls6">0</span></span></span>, isto é, <span class="ff3 ws2d">x < <span class="ff4 ws7">\ue000<span class="ff5">4</span></span></span>.</div><div class="t m0 x5 h4 y4e ff2 fs3 fc2 sc0 ls3e ws53">(b) <span class="ff4 ws7">\ue000<span class="ff5 ls2d">1</span><span class="ff3 ws2d">< x < <span class="ff5 ls54">0</span></span></span><span class="ws34">ou <span class="ff3 ws2d">x > <span class="ff5 ws7">1</span><span class="ls6">=</span><span class="ff5 ws7">2</span></span><span class="ws4">.<span class="_21 blank"> </span>Na forma de interv<span class="_1a blank"></span>alo, temos <span class="ff5 ws7">(<span class="ff4">\ue000</span>1<span class="ff3 ls57">;</span><span class="ws19">0) <span class="ff4 ls56">[</span></span>(1<span class="ff3">=</span><span class="ls6">2<span class="ff3 ls55">;</span></span>+<span class="ff4">1</span><span class="ls65">)</span><span class="ff3">:</span></span></span></span></div><div class="t m0 x5 h4 y4f ff2 fs3 fc2 sc0 ls3e ws54">(c) <span class="ff5 ws7">[<span class="ff4">\ue000</span>1<span class="ff3 ls57">;</span><span class="ws55">1] <span class="ff3">:</span></span></span></div><div class="t m0 x5 h4 y50 ff2 fs3 fc2 sc0 ls3e ws53">(d) <span class="ff5 ws7">(3<span class="ff3 ls55">;</span>14<span class="ff3 ls6">=</span><span class="wsd">3) <span class="ff3">:</span></span></span></div><div class="t m0 x5 h4 y51 ff2 fs3 fc2 sc0 ls3e ws54">(e) <span class="ff5 ws7">(<span class="ff4">\ue000</span><span class="ls6">3<span class="ff3 ls55">;</span>1</span><span class="ff3">=</span><span class="wsd">2) <span class="ff3">:</span></span></span></div><div class="t m0 x2 h4 y52 ff2 fs3 fc2 sc0 ls3e wse">(f )<span class="_6 blank"> </span><span class="ff5 ws7">(<span class="ff4">\ue0001<span class="ff3 ls57">;</span></span>3<span class="ff3 ls6">=</span><span class="ws19">2) <span class="ff4 ls56">[</span></span>(9<span class="ff3">=</span><span class="ls6">5<span class="ff3 ls55">;</span></span>+<span class="ff4">1</span><span class="ls65">)</span><span class="ff3">:</span></span></div><div class="t m0 x5 h4 y53 ff2 fs3 fc2 sc0 ls3e ws10">(g) <span class="ff5 ws7 v0">(<span class="ff4">\ue000</span><span class="ls6">1<span class="ff3 ls55">;</span>1</span><span class="ff3">=</span><span class="wsd">2) <span class="ff3">:</span></span></span></div><div class="t m0 x5 h4 y54 ff2 fs3 fc2 sc0 ls3e ws53">(h) <span class="ff5 ws7">(<span class="ff4">\ue0001<span class="ff3 ls57">;</span></span>2<span class="ff3 ls6">=</span><span class="wsb">3] <span class="ff4 ls56">[</span></span>(2<span class="ff3 ls55">;</span>+<span class="ff4">1</span><span class="ls65">)</span><span class="ff3">:</span></span></div><div class="t m0 x1 h13 y55 ff2 fs3 fc2 sc0 ls3e ws4">5.<span class="_6 blank"> </span>No estudo do sinal do trinômio do segundo grau <span class="ff3 ws7">ax<span class="ff7 fs1 lsa v3">2</span><span class="ff5 ls8">+</span><span class="ws56">bx <span class="ff5 ls3">+</span><span class="ws57">c;<span class="_6 blank"> </span>a </span></span><span class="ff4">6<span class="ff5 ws14">= 0</span></span></span>, ressaltamos alguns fatos:</div><div class="t m0 x25 h13 y56 ff4 fs3 fc2 sc0 ls66">\ue00f<span class="ff2 ls3e ws58">Se o discriminan<span class="_3 blank"></span>te <span class="ff5 ws59">\ue001 = <span class="ff3 ls67">b<span class="ff7 fs1 ls68 v3">2</span><span class="ff4 ls69">\ue000</span></span><span class="ws7">4<span class="ff3 ws5a">ac </span></span></span><span class="ws5b">for negativ<span class="_3 blank"></span>o,<span class="_22 blank"> </span>en<span class="_3 blank"></span>tão o trinômio terá o mesmo sinal do</span></span></div><div class="t m0 x3 h4 y57 ff2 fs3 fc2 sc0 ls3e ws33">co e\u2026<span class="_18 blank"></span>cien<span class="_3 blank"></span>te<span class="_1 blank"> </span><span class="ff3 ws7">a</span><span class="ws4">, seja qual for o v<span class="_9 blank"></span>alor que se atribua a <span class="ff3">x:</span></span></div><div class="t m0 x25 h4 y58 ff4 fs3 fc2 sc0 ls66">\ue00f<span class="ff2 ls3e ws5c">Se <span class="ff5 ls6a">\ue001<span class="ff3 ls6b">></span><span class="ls3e ws7">0</span></span><span class="ws5d">, en<span class="_3 blank"></span>tão o trinômio terá duas raízes reais e distin<span class="_3 blank"></span>tas <span class="ff3 ws7">x<span class="ff7 fs1 ls6c v1b">1</span></span><span class="ls6d">e</span><span class="ff3 ws7">x<span class="ff7 fs1 ls6c v1b">2</span></span><span class="ws5e">e o sinal será o mesmo</span></span></span></div><div class="t m0 x3 h4 y59 ff2 fs3 fc2 sc0 ls3e ws33">do<span class="_1 blank"> </span>coe\u2026<span class="_18 blank"></span>ciente<span class="_1 blank"> </span><span class="ff3 ws7">a</span><span class="ws5f">, se o <span class="ff3 ls6e">x</span><span class="ws60">não estiv<span class="_9 blank"></span>er entre as raízes <span class="ff3 ws7">x<span class="ff7 fs1 ls6f v1b">1</span></span><span class="ls70">e</span><span class="ff3 ws7">x<span class="ff7 fs1 ls71 v1b">2</span></span>; ele terá sinal con<span class="_3 blank"></span>trário ao de <span class="ff3 ws7">a</span><span class="ws61">, se</span></span></span></div><div class="t m0 x3 h4 y5a ff2 fs3 fc2 sc0 ls72">o<span class="ff3 ls73">x</span><span class="ls3e ws4">estiv<span class="_3 blank"></span>er en<span class="_3 blank"></span>tre as raízes</span></div><div class="t m0 x25 h4 y5b ff4 fs3 fc2 sc0 ls66">\ue00f<span class="ff2 ls3e ws62">Se </span><span class="ff5 ls74 ws63">\ue001=0<span class="_23 blank"></span><span class="ff2 ls3e ws64">, o trinômio terá uma única raiz real <span class="ff3 ws7">x<span class="ff7 fs1 ls75 v1b">0</span></span>e o sinal coincide com sinal de <span class="ff3 ws7">a</span><span class="ws65">, se <span class="ff3 ls1c">x</span><span class="ff4 ws7">6<span class="ff5 ls10">=</span><span class="ff3">x<span class="ff7 fs1 ls15 v1b">0</span></span></span>.</span></span></span></div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf4" class="pf w0 h0" data-page-no="4"><div class="pc pc4 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x25 y5c w3 h22" alt="" src="https://files.passeidireto.com/1d85f28a-ee9c-4642-9753-10f15b465d51/bg4.png"><div class="t m0 x14 h4 y28 ff2 fs3 fc2 sc0 ls3f">4<span class="ff1 fs1 fc0 ls3e ws1">C Á L C U L O<span class="_1 blank"> </span>D E<span class="_1 blank"> </span>U M A<span class="_1 blank"> </span>V<span class="_9 blank"></span>A R I Á<span class="_1a blank"></span>V E L<span class="_24 blank"> </span>M A R I V<span class="_1a blank"></span>A L D O<span class="_1 blank"> </span>P.<span class="_a blank"> </span>M<span class="_0 blank"> </span>A<span class="_3 blank"></span>T O S</span></div><div class="t m0 x3 h4 y29 ff2 fs3 fc2 sc0 ls3e ws4">Na \u2026<span class="_18 blank"></span>gura abaixo ilustramos algumas situações.</div><div class="t m0 x16 h13 y5d ff2 fs3 fc2 sc0 ls3e ws10">(a) <span class="ff3 ws7">x<span class="ff7 fs1 lsa v3">2</span><span class="ff4 ls3">\ue000<span class="ff5 ls6">3</span></span><span class="ls2">x</span><span class="ff5 wsb">+ 2<span class="_a blank"> </span></span><span class="ls10"><</span><span class="ff5">0</span><span class="ls49">;<span class="ff5 ls74 ws63">\ue001=1</span><span class="ls10">><span class="ff5 ls6">0</span></span></span>:</span></div><div class="t m0 x26 h4 y5e ff2 fs3 fc2 sc0 ls3e ws66">As raízes são <span class="ff3 ws7">x<span class="ff7 fs1 ls14 v1b">1</span><span class="ff5 ws14">= 2<span class="_1 blank"> </span></span></span><span class="ls76">e</span><span class="ff3 ws7">x<span class="ff7 fs1 ls14 v1b">2</span><span class="ff5 ws14">= 1<span class="_1 blank"> </span></span></span><span class="ws67">e o trinômio será <span class="ff3 ls10"><<span class="ff5 ls77">0</span></span><span class="ws68">quando <span class="ff5 ls2d">1</span><span class="ff3 ws2d">< x < <span class="ff5 ws7">2</span><span class="ls78">:</span></span></span>O conjun<span class="_3 blank"></span>to solução é</span></div><div class="t m0 x27 h4 y5f ff3 fs3 fc2 sc0 ls79">S<span class="ff5 ls3e ws14">= (1</span><span class="ls55">;<span class="ff5 ls3e ws69">2) <span class="ff2 ws6a">ou </span></span></span>S<span class="ff5 ls10">=<span class="ff4 ls3e ws7">f</span></span><span class="ls61">x<span class="ff4 ls7a">2<span class="ffd ls74">R<span class="ff5 ls3e ws6b">: 1 </span></span></span><span class="ls3e ws2d">< x < <span class="ff5 ls6">2<span class="ff4 ls7b">g</span></span>:</span></span></div><div class="t m0 x26 h4 y60 ff2 fs3 fc2 sc0 ls3e ws4">V<span class="_1a blank"></span>eja a ilustração na \u2026<span class="_18 blank"></span>gura abaixo.</div><div class="t m0 xe h13 y61 ff2 fs3 fc2 sc0 ls3e ws53">(b) <span class="ff3 ws7">x<span class="ff7 fs1 lsa v3">2</span><span class="ff5 ls3">+</span><span class="ls2">x</span><span class="ff5 wsb">+ 1<span class="_a blank"> </span><span class="ff4 ls10">\ue014</span><span class="ls6">0</span></span><span class="ls49">;</span><span class="ff5 ws6c">\ue001 = </span><span class="ff4">\ue000<span class="ff5 lsf">3</span></span><span class="ls10"><</span><span class="ff5">0</span><span class="ls7c">:</span></span><span class="ws4">Conjun<span class="_3 blank"></span>to solução <span class="ff3 ls7d">S<span class="ff5 ls10">=<span class="ffd ls7e">?</span></span></span>(conjun<span class="_3 blank"></span>to v<span class="_9 blank"></span>azio).</span></div><div class="t m0 x16 h12 y62 ff2 fs3 fc2 sc0 ls3e ws54">(c) <span class="ff5 ws7">3<span class="ff3">x<span class="ff7 fs1 ls12 v3">2</span></span><span class="ls3">+<span class="ff3 ls2">x</span><span class="ff4">\ue000</span><span class="lsf">2<span class="ff3 ls10">></span></span></span>0<span class="ff3 ls49">;</span><span class="ws14">\ue001 = 25 <span class="ff3 ls10">></span></span>0<span class="ff3 ls7c">:</span></span><span class="ws4">Conjun<span class="_3 blank"></span>to solução <span class="ff3 ls79">S</span><span class="ff5 ws14">= (<span class="ff4 ws7">\ue0001<span class="ff3 ls57">;</span>\ue000</span><span class="ws6d">1) <span class="ff4 ls56">[</span><span class="ws7">(2<span class="ff3">=</span><span class="ls6">3<span class="ff3 ls55">;</span></span>+<span class="ff4">1</span><span class="ls65">)</span><span class="ff3">:</span></span></span></span></span></div><div class="t m0 xe h13 y63 ff2 fs3 fc2 sc0 ls3e ws53">(d) <span class="ff5 ws7">4<span class="ff3">x<span class="ff7 fs1 ls12 v3">2</span><span class="ff4 ls3">\ue000</span></span>4<span class="ff3 ls2">x</span><span class="wsb">+ 1<span class="_a blank"> </span><span class="ff4 ls10">\ue014</span><span class="ls6">0<span class="ff3 ls49">;</span><span class="ls74 ws63">\ue001=0<span class="_23 blank"></span><span class="ff3 ls7f">:<span class="ff2 ls3e ws4">Conjun<span class="_3 blank"></span>to solução <span class="ff3 ls79">S<span class="ff5 ls10">=</span></span><span class="ff4 ws7">f<span class="ff5 ls6">1</span><span class="ff3">=<span class="ff5 ls6">2</span></span><span class="ls54">g</span></span>(conjun<span class="_3 blank"></span>to unitário).</span></span></span></span></span></span></div><div class="t m0 x16 h12 y64 ff2 fs3 fc2 sc0 ls3e ws54">(e) <span class="ff3 ws7">x<span class="ff7 fs1 lsa v3">2</span><span class="ff5 wsb">+ 3<span class="_a blank"> </span></span><span class="ls10">><span class="ff5 ls6">0</span><span class="ls80">;</span></span><span class="ff5 ws6e">\ue001 = </span><span class="ff4">\ue000<span class="ff5 ws6f">12 </span></span><span class="ls10"><<span class="ff5 ls6">0</span><span class="ls7f">:</span></span></span><span class="ws4">Conjun<span class="_3 blank"></span>to solução <span class="ff3 ls79">S<span class="ff5 ls10">=<span class="ffd ls81">R</span></span></span><span class="ws34">ou <span class="ff3 ls7d">S</span><span class="ff5 ws14">= (<span class="ff4 ws7">\ue0001<span class="ff3 ls55">;</span><span class="ff5">+</span>1<span class="ff5">)</span></span></span>.</span></span></div><div class="t m0 x18 h13 y65 ff2 fs3 fc2 sc0 ls3e wse">(f )<span class="_6 blank"> </span><span class="ff3 ws7">x<span class="ff7 fs1 lsa v3">2</span><span class="ff5 ls3">+</span><span class="ls2">x</span><span class="ff5 wsb">+ 1<span class="_a blank"> </span></span><span class="ls10">><span class="ff5 ls6">0</span><span class="ls49">;</span></span><span class="ff5 ws6c">\ue001 = </span><span class="ff4">\ue000<span class="ff5 lsf">3</span></span><span class="ls10"><</span><span class="ff5">0</span><span class="ls7c">:</span></span><span class="ws4">Conjun<span class="_3 blank"></span>to solução <span class="ff3 ls7d">S<span class="ff5 ls10">=<span class="ffd ls82">R</span></span></span><span class="ws34">ou <span class="ff3 ls7d">S</span><span class="ff5 ws14">= (<span class="ff4 ws7">\ue0001<span class="ff3 ls57">;</span><span class="ff5">+</span>1<span class="ff5">)</span></span></span>.</span></span></div><div class="t m0 x16 h12 y66 ff2 fs3 fc2 sc0 ls3e ws10">(g) <span class="ff3 ws7">x<span class="ff7 fs1 lsa v3">2</span><span class="ff4 ls3">\ue000<span class="ff5 ls6">5</span></span><span class="ls2">x</span><span class="ff5 wsb">+ 6<span class="_a blank"> </span><span class="ff4 ls10">\ue015</span><span class="ws7">0</span></span><span class="ls49">;<span class="ff5 ls74 ws63">\ue001=1</span><span class="ls10">><span class="ff5 ls6">0</span><span class="ls7c">:</span></span></span></span><span class="ws4">Conjun<span class="_3 blank"></span>to solução <span class="ff3 ls7d">S</span><span class="ff5 ws14">= (<span class="ff4 ws7">\ue0001<span class="ff3 ls55">;</span></span><span class="wsb">2] <span class="ff4 ls56">[</span><span class="ws7">[3<span class="ff3 ls55">;</span>+<span class="ff4">1</span>)</span></span></span>.</span></div><div class="t m0 xe h13 y67 ff2 fs3 fc2 sc0 ls3e ws53">(h) <span class="ff3 ws7">x<span class="ff7 fs1 lsa v3">2</span><span class="ff5 wsb">+ 5<span class="_a blank"> </span><span class="ff4 ls10">\ue014</span><span class="ls6">0</span></span><span class="ls80">;</span><span class="ff5 ws6e">\ue001 = </span><span class="ff4">\ue000<span class="ff5 ws6f">20 </span></span><span class="ls10"><<span class="ff5 ls6">0</span><span class="ls7f">:</span></span></span><span class="ws4">Conjun<span class="_3 blank"></span>to solução <span class="ff3 ls79">S<span class="ff5 ls10">=<span class="ffd ls83">?</span></span></span>(conjun<span class="_3 blank"></span>to v<span class="_9 blank"></span>azio).</span></div><div class="t m0 x28 h4 y68 ff2 fs3 fc2 sc0 ls3e ws70">(i) <span class="ff5 ws7">(<span class="ff3 ls2">x<span class="ff4 ls3">\ue000</span></span><span class="ws8">2) (<span class="ff3 ls2">x</span>+<span class="_7 blank"> </span>3) (1<span class="_7 blank"> </span><span class="ff4 ls3">\ue000</span></span><span class="ff3">x</span><span class="ls32">)<span class="ff3 ls10">></span><span class="ls6">0<span class="ff3 ls7f">:</span></span></span></span><span class="ws4">P<span class="_3 blank"></span>ara começar, v<span class="_3 blank"></span>eja a ilustração na \u2026<span class="_5 blank"></span>gura abaixo.</span></div><div class="t m0 x26 h4 y69 ff2 fs3 fc2 sc0 ls3e ws4">O conjun<span class="_3 blank"></span>to solução é <span class="ff3 ls7d">S</span><span class="ff5 ws14">= (<span class="ff4 ws7">\ue0001<span class="ff3 ls55">;</span>\ue000</span><span class="ws6d">3) <span class="ff4 ls84">[</span><span class="ws7">(1<span class="ff3 ls57">;</span>2)</span></span></span>.</div><div class="t m0 x18 h13 y6a ff2 fs3 fc2 sc0 ls3e ws4c">(j)<span class="_6 blank"> </span>A desigualdade prop<span class="_11 blank"> </span>osta é equiv<span class="_9 blank"></span>alente a <span class="ff5 ws7">2<span class="ff3">x<span class="ff7 fs1 ls85 v3">2</span><span class="ff4 ls86">\ue000</span></span>3<span class="ff3 ls87">x</span><span class="ws8">+ 4<span class="_a blank"> </span><span class="ff3 ls10"><</span><span class="ls6">0<span class="ff3 ls88">;</span></span></span></span>onde temos <span class="ff3 ls89">a</span><span class="ff5 ws14">= 2 </span><span class="ls8a">e</span><span class="ff5 ws6c">\ue001 = <span class="ff4 ws7">\ue000</span><span class="ws6f">23 <span class="ff3 ls10"><</span><span class="ls6">0</span><span class="ff3">:</span></span></span></div><div class="t m0 x26 h4 y5b ff2 fs3 fc2 sc0 ls3e ws4">O trinômio será sempre p<span class="_11 blank"> </span>ositivo (<span class="_3 blank"></span>tem o mesmo sinal de ) O conjunto solução <span class="ff3 ls7d">S<span class="ff5 ls10">=</span></span><span class="ffd ws7">?<span class="ff3">:</span></span></div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf5" class="pf w0 h0" data-page-no="5"><div class="pc pc5 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 y6b w3 h23" alt="" src="https://files.passeidireto.com/1d85f28a-ee9c-4642-9753-10f15b465d51/bg5.png"><div class="t m0 x0 h2 y28 ff1 fs1 fc0 sc0 ls3e ws45">C O M P L E M E N T O S<span class="_1 blank"> </span><span class="fs0 ls5b">1</span><span class="ws1">N Ú M E RO S<span class="_1 blank"> </span>R E A I S<span class="_19 blank"> </span><span class="ff2 fs3 fc2">5</span></span></div><div class="t m0 x5 h24 y29 ff2 fs3 fc2 sc0 ls3e wsb">(k)<span class="_6 blank"> </span>O termo <span class="ff5 ws7">(<span class="ff3 ls2">x</span><span class="wsb">+ 4)<span class="ff7 fs1 ls8b v4">2</span></span>(<span class="ff3 ls2">x<span class="ff4 ls3">\ue000</span></span>2)<span class="ff9 fs1 ls33 v4">\ue000<span class="ff7 lsa">4</span></span></span>é não negativ<span class="_3 blank"></span>o, exceto quando <span class="ff3 ls1c">x</span><span class="ff5 ws14">= 2</span>.<span class="_21 blank"> </span>O sinal de <span class="ff3 ls7">x</span><span class="ff5 ws7">(<span class="ff3 ls2">x</span><span class="wsb">+ 4)<span class="ff7 fs1 lsd v4">2</span></span>(<span class="ff3 ls2">x<span class="ff4 ls3">\ue000</span></span>2)<span class="ff9 fs1 ls8c v4">\ue000<span class="ff7 ls3e">4</span></span></span></div><div class="t m0 x3 h4 y2a ff2 fs3 fc2 sc0 ls3e ws4">dep<span class="_11 blank"> </span>ende tão somente do sinal de <span class="ff3 ws71">x: </span><span class="ws7">Assim,</span></div><div class="t m0 x29 h24 y6c ff3 fs3 fc2 sc0 ls7">x<span class="ff5 ls3e ws7">(</span><span class="ls2">x<span class="ff5 ls3e wsb">+ 4)<span class="ff7 fs1 ls8b v4">2</span><span class="ws7">(</span></span>x<span class="ff4 ls3">\ue000<span class="ff5 ls3e ws7">2)<span class="ff9 fs1 ls33 v4">\ue000<span class="ff7 ls14">4</span></span></span></span><span class="ls10"><<span class="ff5 lsf">0<span class="ff4 ls5c">,</span></span><span class="ls3e ws2d">x < <span class="ff5">0</span></span></span></span></div><div class="t m0 x3 h4 y6d ff2 fs3 fc2 sc0 ls3e ws4">e o conjun<span class="_3 blank"></span>to solução é <span class="ff3 ls79">S</span><span class="ff5 ws14">= (<span class="ff4 ws7">\ue0001<span class="ff3 ls57">;</span></span><span class="wsd">0) <span class="ff3">:</span></span></span></div><div class="t m0 x2a h13 y6e ff2 fs3 fc2 sc0 ls3e ws72">(l)<span class="_6 blank"> </span>V<span class="_1a blank"></span>eja na \u2026<span class="_18 blank"></span>gura os sinais dos trinômios <span class="ff3 ws7">x<span class="ff7 fs1 ls8d v3">2</span><span class="ff4 ls8e">\ue000<span class="ff5 ls8f">4</span></span></span><span class="ls90">e</span><span class="ff3 ws7">x<span class="ff7 fs1 ls8d v3">2</span><span class="ff4 ls8e">\ue000</span><span class="ff5">3</span><span class="ls91">x</span><span class="ff5 ws73">+ 2<span class="_1 blank"> </span></span></span>e deduza que o conjunto solução</div><div class="t m0 x3 h4 y6f ff2 fs3 fc2 sc0 ls92">é<span class="ff3 ls79">S<span class="ff5 ls3e ws14">= [<span class="ff4 ws7">\ue000</span><span class="ls6">2</span></span><span class="ls55">;<span class="ff5 ls3e wsb">1] <span class="ff4">[ f</span><span class="ws7">2<span class="ff4 ls7b">g</span><span class="ff3">:</span></span></span></span></span></div><div class="t m0 x1 h4 y70 ff2 fs3 fc2 sc0 ls3e ws46">6. En<span class="_3 blank"></span>unciado</div><div class="t m0 x5 h4 y71 ff2 fs3 fc2 sc0 ls3e ws10">(a) <span class="ff3 ls7d">S</span><span class="ff5 ws14">= [<span class="ff4 ws7">\ue000</span><span class="ls6">1<span class="ff3 ls55">;</span></span><span class="ws74">1] </span></span><span class="ws6a">ou <span class="ff3 ls79">S<span class="ff5 ls10">=<span class="ff4 ls6">f</span></span><span class="ls1c">x<span class="ff4 ls7a">2<span class="ffd ls74">R<span class="ff5 ls16">:</span></span><span class="ls3e ws7">\ue000<span class="ff5 lsf">1</span><span class="ls10">\ue014</span></span></span>x<span class="ff4 ls10">\ue014<span class="ff5 ls6">1</span><span class="ls93">g</span></span><span class="ls3e">:</span></span></span></span></div><div class="t m0 x5 h4 y72 ff2 fs3 fc2 sc0 ls3e ws53">(b) <span class="ff3 ls7d">S</span><span class="ff5 ws14">= (<span class="ff4 ws7">\ue000<span class="ff5">1<span class="ff3 ls57">;</span><span class="ws75">2) </span></span></span></span><span class="ws48">ou <span class="ff3 ls7d">S<span class="ff5 ls10">=<span class="ff4 ls6">f</span></span><span class="ls1c">x<span class="ff4 ls7a">2<span class="ffd ls74">R<span class="ff5 ls17">:</span></span><span class="ls3e ws7">\ue000<span class="ff5 lsf">1</span><span class="ff3 ws2d">< x < </span><span class="ff5">2</span><span class="ls7b">g</span><span class="ff3">:</span></span></span></span></span></span></div><div class="t m0 x5 h4 y73 ff2 fs3 fc2 sc0 ls3e ws54">(c) <span class="ff3 ls7d">S</span><span class="ff5 ws14">= (<span class="ff4 ws7">\ue0001<span class="ff3 ls55">;</span>\ue000</span><span class="ws19">3) <span class="ff4 ls56">[</span><span class="ws7">(3<span class="ff3 ls57">;</span>+<span class="ff4 ls1d">1</span><span class="ls94">)</span></span></span></span><span class="ws48">ou <span class="ff3 ls79">S<span class="ff5 ls10">=</span></span><span class="ff4 ws7">f<span class="ff3 ls1c">x</span><span class="ls7a">2<span class="ffd ls74">R<span class="ff5 ls17">:</span></span></span><span class="ff3 ws2d">x < </span>\ue000<span class="ff5 ls11">3</span></span>ou <span class="ff3 ws2d">x > <span class="ff5 ws7">3<span class="ff4 ls7b">g</span></span>:</span></span></div><div class="t m0 x5 h4 y74 ff2 fs3 fc2 sc0 ls3e ws53">(d) <span class="ff3 ls7d">S</span><span class="ff5 ws14">= [<span class="ff4 ws7">\ue000<span class="ff5">10<span class="ff3">=</span><span class="ls6">9<span class="ff3 ls55">;</span></span></span>\ue000</span><span class="ls6">8</span><span class="ff3 ws7">=</span><span class="ws76">9] </span></span><span class="ws48">ou <span class="ff3 ls7d">S<span class="ff5 ls2e">=</span></span><span class="ff4 ws7">f<span class="ff3 ls1c">x</span><span class="ls7a">2<span class="ffd ls74">R<span class="ff5 ls17">:</span></span></span>\ue000<span class="ff5">10<span class="ff3">=</span><span class="lsf">9</span></span><span class="ls10">\ue014<span class="ff3 ls1c">x</span></span><span class="ws14">\ue014 \ue000<span class="ff5 ls6">8</span></span><span class="ff3">=<span class="ff5 ls6">9</span></span><span class="ls7b">g</span><span class="ff3">:</span></span></span></div><div class="t m0 x5 h4 y75 ff2 fs3 fc2 sc0 ls3e ws54">(e) <span class="ff3 ls7d">S</span><span class="ff5 ws14">= (<span class="ff4 ws7">\ue000<span class="ff5">1<span class="ff3 ls57">;</span><span class="ws19">0) </span></span><span class="ls56">[</span><span class="ff5">(0<span class="ff3 ls55">;</span><span class="ws77">1) </span></span></span></span><span class="ws6a">ou <span class="ff3 ls79">S<span class="ff5 ls10">=</span></span><span class="ff4 ws7">f<span class="ff3 ls61">x</span><span class="ls7a">2<span class="ffd ls74">R<span class="ff5 ls16">:</span></span></span>\ue000<span class="ff5 lsf">1</span><span class="ff3 ws2d">< x < <span class="ff5 ls11">1</span></span></span><span class="ls44">e<span class="ff3 ls1c">x</span></span><span class="ff4 ws7">6<span class="ff5 ws14">= 0</span><span class="ls93">g</span><span class="ff3">:</span></span></span></div><div class="t m0 x2 h4 y76 ff2 fs3 fc2 sc0 ls3e wse">(f )<span class="_6 blank"> </span><span class="ff3 ls7d">S<span class="ff5 ls10">=<span class="ffd ls95">?</span></span></span><span class="ws4">(conjun<span class="_3 blank"></span>to v<span class="_9 blank"></span>azio).</span></div><div class="t m0 x5 h4 y77 ff2 fs3 fc2 sc0 ls3e ws10">(g) <span class="ff3 ls7d">S</span><span class="ff5 ws14">= (<span class="ff4 ws7">\ue0001<span class="ff3 ls55">;</span>\ue000</span><span class="wsb">4] <span class="ff4 ls56">[</span><span class="ws7">[<span class="ff4">\ue000</span><span class="ls6">2<span class="ff3 ls55">;</span></span>+<span class="ff4">1</span><span class="ls96">)</span></span></span></span><span class="ws34">ou <span class="ff3 ls7d">S<span class="ff5 ls10">=<span class="ff4 ls6">f</span></span><span class="ls1c">x<span class="ff4 ls7a">2<span class="ffd ls74">R<span class="ff5 ls17">:</span></span></span>x</span></span><span class="ff4 ws14">\ue014 \ue000<span class="ff5 ls54">4</span></span><span class="ws1b">ou <span class="ff3 ls61">x</span><span class="ff4 ws14">\ue015 \ue000<span class="ff5 ws7">2</span><span class="ls7b">g</span><span class="ff3">:</span></span></span></span></div><div class="t m0 x5 h4 y78 ff2 fs3 fc2 sc0 ls3e ws53">(h) <span class="ff3 ls7d">S</span><span class="ff5 ws14">= (1<span class="ff3 ls6">=</span><span class="ws7">3<span class="ff3 ls57">;</span><span class="ws75">1) </span></span></span><span class="ws48">ou <span class="ff3 ls7d">S<span class="ff5 ls10">=<span class="ff4 ls6">f</span></span><span class="ls1c">x<span class="ff4 ls7a">2<span class="ffd ls74">R</span></span></span></span><span class="ff5 ws14">: 1<span class="ff3 ls6">=</span><span class="lsf">3</span><span class="ff3 ws2d">< x < </span><span class="ws7">1<span class="ff4 ls7b">g</span><span class="ff3">:</span></span></span></span></div><div class="t m0 x2a h4 y79 ff2 fs3 fc2 sc0 ls3e ws70">(i) <span class="ff3 ls7d">S</span><span class="ff5 ws14">= (<span class="ff4 ws7">\ue0001<span class="ff3 ls55">;</span></span><span class="ws19">0) <span class="ff4 ls56">[</span><span class="ws7">(2<span class="ff3 ls57">;</span>+<span class="ff4">1</span><span class="ls97">)</span></span></span></span><span class="ws6a">ou <span class="ff3 ls79">S<span class="ff5 ls10">=</span></span><span class="ff4 ws7">f<span class="ff3 ls61">x</span><span class="ls7a">2<span class="ffd ls74">R<span class="ff5 ls16">:</span></span></span><span class="ff3 ws2d">x < <span class="ff5 ls11">0</span></span></span><span class="ws48">ou <span class="ff3 ws2d">x > <span class="ff5 ls6">2<span class="ff4 ls93">g</span></span>:</span></span></span></div><div class="t m0 x2 h4 y7a ff2 fs3 fc2 sc0 ls3e ws78">(j) <span class="ff3 ls7d">S</span><span class="ff5 ws14">= (<span class="ff4 ws7">\ue0001<span class="ff3 ls55">;</span>\ue000</span><span class="ws75">3) </span></span><span class="ws48">ou <span class="ff3 ls79">S<span class="ff5 ls10">=</span></span><span class="ff4 ws7">f<span class="ff3 ls1c">x</span><span class="ls7a">2<span class="ffd ls74">R<span class="ff5 ls17">:</span></span></span><span class="ff3 ws2d">x < </span>\ue000<span class="ff5 ls6">3</span><span class="ls93">g</span><span class="ff3">:</span></span></span></div><div class="t m0 x5 h4 y7b ff2 fs3 fc2 sc0 ls3e ws79">(k) <span class="ff3 ls7d">S</span><span class="ff5 ws14">= (0<span class="ff3 ls57">;</span><span class="ws75">2) </span></span><span class="ws48">ou <span class="ff3 ls7d">S<span class="ff5 ls10">=<span class="ff4 ls6">f</span></span><span class="ls1c">x<span class="ff4 ls7a">2<span class="ffd ls74">R</span></span></span></span><span class="ff5 ws6b">: 0 <span class="ff3 ws2d">< x < </span><span class="ws7">2<span class="ff4 ls7b">g</span><span class="ff3">:</span></span></span></span></div><div class="t m0 x2a h4 y7c ff2 fs3 fc2 sc0 ls3e ws70">(l) <span class="ff3 ls7d">S</span><span class="ff5 ws14">= (<span class="ff4 ws7">\ue0001<span class="ff3 ls55">;</span>\ue000</span><span class="ws19">1) <span class="ff4 ls56">[</span><span class="ws7">(1<span class="ff3 ls57">;</span>+<span class="ff4 ls1d">1</span><span class="ls94">)</span></span></span></span><span class="ws48">ou <span class="ff3 ls79">S<span class="ff5 ls10">=</span></span><span class="ff4 ws7">f<span class="ff3 ls1c">x</span><span class="ls7a">2<span class="ffd ls74">R<span class="ff5 ls17">:</span></span></span><span class="ff3 ws2d">x < </span>\ue000<span class="ff5 ls11">1</span></span>ou <span class="ff3 ws2d">x > <span class="ff5 ws7">1<span class="ff4 ls7b">g</span></span>:</span></span></div><div class="t m0 x5 h4 y7d ff2 fs3 fc2 sc0 ls3e ws4">(a)<span class="_6 blank"> </span>não equiv<span class="_9 blank"></span>alen<span class="_3 blank"></span>tes<span class="_25 blank"> </span>(b) equiv<span class="_9 blank"></span>alen<span class="_3 blank"></span>tes.</div><div class="t m0 x1 h4 y7e ff2 fs3 fc2 sc0 ls3e ws46">7. En<span class="_3 blank"></span>unciado</div><div class="t m0 x5 h25 y5b ff2 fs3 fc2 sc0 ls3e ws10">(a) <span class="ff3 ls7d">S</span><span class="ff5 ws14">= [<span class="ff4 ls98">\ue000</span><span class="ff7 fs1 v1c">1</span></span></div><div class="t m0 x2b h26 y7f ff7 fs1 fc2 sc0 ls99">2<span class="ff3 fs3 ls9a v3">;</span><span class="ls3e v16">1</span></div><div class="t m0 x2c h27 y7f ff7 fs1 fc2 sc0 ls9b">7<span class="ff5 fs3 ls96 v3">)<span class="ff2 ls3e ws34">ou <span class="ff3 ls7d">S<span class="ff5 ls2e">=</span></span><span class="ff4 ws7">f<span class="ff3 ls1c">x</span><span class="ls7a">2<span class="ffd ls74">R<span class="ff5 ls17">:</span></span></span>\ue000<span class="ff5">1<span class="ff3 ls6">=</span><span class="ls2d">2</span><span class="ff3 ws2d">< x < </span>1<span class="ff3 ls6">=</span>7</span><span class="ls7b">g</span><span class="ff3">:</span></span></span></span></div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf6" class="pf w0 h0" data-page-no="6"><div class="pc pc6 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x14 y80 w2 h28" alt="" src="https://files.passeidireto.com/1d85f28a-ee9c-4642-9753-10f15b465d51/bg6.png"><div class="t m0 x14 h4 y28 ff2 fs3 fc2 sc0 ls3f">6<span class="ff1 fs1 fc0 ls3e ws1">C Á L C U L O<span class="_1 blank"> </span>D E<span class="_1 blank"> </span>U M A<span class="_1 blank"> </span>V<span class="_9 blank"></span>A R I Á<span class="_1a blank"></span>V E L<span class="_24 blank"> </span>M A R I V<span class="_1a blank"></span>A L D O<span class="_1 blank"> </span>P.<span class="_a blank"> </span>M<span class="_0 blank"> </span>A<span class="_3 blank"></span>T O S</span></div><div class="t m0 xe h29 y29 ff2 fs3 fc2 sc0 ls3e ws53">(b) <span class="ff3 ls7d">S</span><span class="ff5 ws14">= [<span class="ff4 ls98">\ue000</span><span class="ff7 fs1 v1c">1</span></span></div><div class="t m0 x2d h27 y81 ff7 fs1 fc2 sc0 ls99">2<span class="ff3 fs3 ls55 v3">;<span class="ff5 ls3e ws19">0) <span class="ff4 ls56">[</span><span class="ws7">(0<span class="ff3 ls57">;</span><span class="ws7a">1] <span class="ff2 ws34">ou <span class="ff3 ls7d">S</span></span><span class="ls10">=<span class="ff4 ls6">f<span class="ff3 ls1c">x</span><span class="ls7a">2<span class="ffd ls74">R</span></span></span><span class="ls17">:</span></span></span><span class="ff4">\ue000</span><span class="ls6">1<span class="ff3">=</span><span class="ls2d">2<span class="ff4 ls10">\ue014</span></span></span><span class="ff3 ws2d">x < </span><span class="ls54">0</span><span class="ff2 ws1b">ou </span><span class="lsf">0</span><span class="ff3 ws7b">< x <span class="ff4 ls2e">\ue014</span></span>1<span class="ff4 ls7b">g</span><span class="ff3">:</span></span></span></span></div><div class="t m0 x15 h4 y82 ff2 fs3 fc2 sc0 ls3e ws46">8. En<span class="_3 blank"></span>unciado</div><div class="t m0 x16 h4 y83 ff2 fs3 fc2 sc0 ls3e ws4">(a)<span class="_6 blank"> </span>Basta observ<span class="_9 blank"></span>ar que se <span class="ff3 ws2d">x > <span class="ff5 ls6">0</span></span>, en<span class="_3 blank"></span>tão</div><div class="t m0 x2e h5 y84 ff3 fs3 fc2 sc0 ls2">x<span class="ff5 ls47">+<span class="ls3e v1">1</span></span></div><div class="t m0 x2f h2a y85 ff3 fs3 fc2 sc0 ls48">x<span class="ff4 ls10 v1">\ue015<span class="ff5 lsf">2<span class="ff4 ls5c">,<span class="ff3 ls3e ws7">x<span class="ff7 fs1 ls12 v1c">2</span></span><span class="ls3">\ue000</span></span><span class="ls3e ws7">2<span class="ff3 ls2">x</span><span class="wsb">+ 1<span class="_a blank"> </span></span></span></span>\ue015<span class="ff5 ls3e">0</span></span></div><div class="t m0 x26 h4 y86 ff2 fs3 fc2 sc0 ls3e ws4">e esta última desigualdade é v<span class="_9 blank"></span>álida seja qual for o v<span class="_9 blank"></span>alor real que se atribua a <span class="ff3">x:</span></div><div class="t m0 xe h4 y87 ff2 fs3 fc2 sc0 ls3e ws2b">(b)<span class="_6 blank"> </span>Se existissem tais n<span class="_3 blank"></span>úmeros <span class="ff3 ls4b">x</span><span class="ls4c">e<span class="ff3 ls9c">y</span></span><span class="ws7">satisfazendo</span></div><div class="t m0 x7 h4 y88 ff5 fs3 fc2 sc0 ls3e">1</div><div class="t m0 x7 h2b y89 ff3 fs3 fc2 sc0 ls9d">x<span class="ff5 ls4f v1">+<span class="ls3e v1">1</span></span></div><div class="t m0 x30 h2b y89 ff3 fs3 fc2 sc0 ls50">y<span class="ff5 ls51 v1">=<span class="ls3e v1">1</span></span></div><div class="t m0 xf h4 y89 ff3 fs3 fc2 sc0 ls2">x<span class="ff5 ls3">+</span><span class="ls3e">y</span></div><div class="t m0 x26 h4 y8a ff2 fs3 fc2 sc0 ls3e ws7">teríamos</div><div class="t m0 x31 h2c y8b ff3 fs3 fc2 sc0 ls3e ws7">x<span class="ff7 fs1 lsa v1c">2</span><span class="ff5 ls3">+</span><span class="ws7c">xy <span class="ff5 ls3">+</span><span class="ls4d">y<span class="ff7 fs1 ls13 v1c">2</span></span><span class="ff5 ws14">= 0<span class="_26 blank"> </span></span></span><span class="ff2">(1.1)</span></div><div class="t m0 x26 h13 y8c ff2 fs3 fc2 sc0 ls3e ws7d">e, olhando (<span class="fc3 ws7">1.1</span>) como uma equação do segundo grau em <span class="ff3 ws7">x</span><span class="ws7e">,<span class="_21 blank"> </span>v<span class="_3 blank"></span>emos que <span class="ff5 ws7f">\ue001 = <span class="ff4 ws7">\ue000</span><span class="ls6">3<span class="ff3 ls4d">y<span class="ff7 fs1 ls9e v3">2</span><span class="ls9f"><</span></span><span class="lsa0">0</span></span></span><span class="ws80">e a</span></span></div><div class="t m0 x26 h4 y8d ff2 fs3 fc2 sc0 ls3e ws2b">equação não tem solução.</div><a class="l" data-dest-detail='[6,"XYZ",303.836,517.78,null]'><div class="d m1" style="border-style:none;position:absolute;left:182.122000px;bottom:472.353000px;width:15.928000px;height:13.814000px;background-color:rgba(255,255,255,0.000001);"></div></a></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div>
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