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Exercício de Dinamica (141)

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PROPRIETARY MATERIAL. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. No part of this Manual may be displayed, 
reproduced or distributed in any form or by any means, without the prior written permission of the publisher, or used beyond the limited 
distribution to teachers and educators permitted by McGraw-Hill for their individual course preparation. If you are a student using this Manual, 
you are using it without permission. 
152 
 
PROBLEM 11.104 
A golfer hits a golf ball with an initial velocity of 160 ft/s at an angle of 25° with the horizontal. Knowing that 
the fairway slopes downward at an average angle of 5°, determine the distance d between the golfer and Point B 
where the ball first lands. 
 
 
SOLUTION 
First note 0
0
( ) (160 ft/s)cos 25
( ) (160 ft/s)sin 25
x
y
v
v
= °
= °
 
and at B cos 5 sin 5B Bx d y d= ° = − ° 
Now Horizontal motion. (Uniform) 
 00 ( )xx v t= + 
At B 
cos 5
cos 5 (160 cos 25 ) or
160 cos 25Bd t t d
°° = ° =
°
 
 Vertical motion. (Uniformly accelerated motion) 
 2 2
0
1
0 ( ) ( 32.2 ft/s )
2yy v t gt g= + − = 
At B: 21
sin 5 (160 sin 25 )
2B Bd t gt− ° = ° − 
Substituting for Bt 
2
2cos 5 1 cos 5
sin 5 (160 sin 25 )
160 cos 25 2 160 cos 25
d d g d
   ° °− ° = ° −   ° °   
 
or 22
(160 cos 25 ) (tan 5 tan 25 )
32.2 cos 5
726.06 ft
d = ° ° + °
°
=
 
or 242 ydd = 

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