Exercicios de concurso publico (1582)

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153
Resolução dos exercícios
	 c)	27	5	3x 8 x V	x2	5	9	V	x 5	3	&	x 5	3	cm
	 d)	(x	1	1)(x	1	5)	5	21	V	x2 1	6x 2	16 5	0
	 	 d	=	100
	 	 cm∞ &x x x
2
6 10 2 25 2 V 5 5
	 e)	
( )x 21( )x
2
8
20
1
5 V
	 	 V (x	1	8)(x	1	2)	5	40	V
	 	 V x2 1	10x 2	24 5	0
	 	 d	=	196
	 	
cm&x x x
2
10 2 25 2 6 V 5 514
	 f)	(x 1	4	1	x)(x	2	1)	5	56	V
	 	 V (2x 1	4)(x	2	1)	5	56	V
	 	 V	2x2 1	2x 2	60	5	0 V
	 	 V x2 1	x 2	30	5	0
	 	 d	=	121
	 	
cm&x x x
2
1 5 55 2 6 V 5 511
	 g)	
( )x 21( )x x
2
2
36
1
5 V
	 	 V 3x (x	1	2)	5	72	V
	 	 V 3x 2 1	6x 2	72 5	0	V
	 	 V x 2	1	2x 2	24 5	0
	 	 d	=	100
	 	
cm&x x x
2
2 4 45 2 6 V 5 510
22.	a)	172	5	152	1	x2	V
	 	 	 V 289	2	225	5	x2	V	x	5	8	&	x	5	8	cm
	 	
( )8
A
2
15 8
605 5
	 	 Portanto:	A	5	60	cm2
	 b)	
l
A
4
3
4
36 3
9 35 5 5
2
	 	 Portanto:	 cmA 9 35 2
	 c)	102	5	82	1	h2	V	h	5	6	&	x	5	6	cm
	 	
( )8
A
2
16 6
485 5
	 	 Portanto:	A	5	48	cm2
	 d)	h	5	4	cm
	 	 4 x4 2 5 1 V2 2 2_ i
	 	 V	32	2	16	5	x2	V	x	5	4
	 	 base:	4	cm	1	3	cm	=	7	cm
	 	
(7)
A
2
4
145
8
5
	 	 Portanto:	A	5	14	cm2
23.	a)	52	5	42	1	(x	2	6)2
	 	 25	2	16	5	x2	2	12x	1	36
	 	 x2	2	12x	1	27	5	0
	 	 d	5	36
	 	 &x x x
2
12 6 9 95 6 V 5 5 cm
	 	
( 6) 48
A
x
2
5
1
V
	
(9 6) 48
A
2
5
1
	 	 Portanto:	A	5	30	cm2
	 b)	(x	1	8)2	5	x2	1	(17	2	x)2	V
	 	 V	x2	1	16x	1	64	5	x2	1	289	2	34x	1	x2	V
 V	x2	2	50x	1	225	5	0
	 	
cm&x x x
2
50 40 5 55 6 V 5 5
	 	
(17 ) (17 5) 58 8
A
x x
2 2
555
1
5
1
5
	 	 Portanto:	A	5	55	cm2
	 c)	x2	5	64	1	(32	2	x)2	V
	 	 V	x2	5	64	1	1.024	2	64x	1	x2	V
 V	64x	5	1.088	V	x	5	17	&	x	5	17	cm
	 	
32 17 8( )
A
2
1965
1 8
5
	 	 Portanto:	A	5	196	cm2
24.	2x	1	4,2	1	16,4	5	54	V
	 V	2x	5	54	2	20,6	V
 V	x	5	16,7	&	x	5	16,7	m
	 16,72	5	H 2	1	(6,1)2	V
 V 278,89	2	37,21	5	H 2	V
	 V	H	5	15,54	&	H	5	15,54	m
	
, , 15,548
A
2
16 4 4 2
5
1
V
_ i
	A	5	10,3	8	(15,54)
	 Portanto:	A	q	160	m2
25.	altura:	x
	 x (x	1	7)	5	60	V
	 V	x2	1	7x	2	60	5	0
	 d	5	289
	
&x x x
2
7 17 5 55 2 6 V 5 5 m
26.	x (2x)	5	578	V
	 	 V	2x2	5	578	V	x2	5	289
	 	 Portanto:	x	5	17	m	e	y	5	34	m
27.	P	5	60	cm
	 	 A	5	56	cm2
	 	 (I)
(II)
x y x y x y
x y
2 2 60 30 30
56
1 5 V 1 5 V 5 2
8 5
*
	 	 (30	2	y)	8	y	5	56	V
	 	 V	30y	2	y2	2	56	5	0	V
	 	 V	y 2	2	30y	1	56	5	0
	 	 d	5	676
	 	 30y
2
265 6 V	y	5	28	ou	y	5	2
	 	 Substituindo	y em	(I),	obtemos:	x	5	2	ou	x	5	28
	 	 Portanto,	as	dimensões	são:	2	cm	e	28	cm	ou	28	cm	e	2	cm